Last visit was: 18 Nov 2025, 15:51 It is currently 18 Nov 2025, 15:51
Home
GMAT
Messages
Tests
Schools
Events
Rewards
Chat
My Profile
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
Back to Forum
Create Topic
 1   2   
User avatar
Gmatter111
User avatar
Joined: 12 Nov 2009
Last visit: 18 Jun 2010
Posts: 40
Own Kudos:
273
 [177]
Given Kudos: 2
Posts: 40
Kudos: 273
 [177]
The ‘moving walkway’ is a 300-foot long walkway consisting of a convey Updated on: 03 Oct 2017, 01:48
Originally posted by Gmatter111 on 02 Dec 2009, 20:34.
Last edited by Bunuel on 03 Oct 2017, 01:48, edited 2 times in total.
Edited the question, added the answer choices and OA
10
Kudos
Add Kudos
165
Bookmarks
Bookmark this Post
00:00
Start Timer
Pause Timer
Resume Timer
Show Answer
Hide
Show
History
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

75% (hard)

Question Stats:

59% (02:35) correct 41% (02:45) wrong based on 1886 sessions

History

Date
Time
Result
Not Attempted Yet
The ‘moving walkway’ is a 300-foot long walkway consisting of a conveyor belt that moves continuously at 3 feet per second. When Bill steps on the walkway, a group of people that are also on the walkway stands 120 feet in front of him. He walks toward the group at a rate of 3 feet per second. Once Bill reaches the group of people, he stops walking and stands with them until the walkway ends. What is Bill’s average rate of movement for his trip along the moving walkway?

A. 2 feet per second
B. 2.5 feet per second
C. 3 feet per second
D. 4 feet per second
E. 5 feet per second
ShowHide Answer
Official Answer
E
Most Helpful Reply
User avatar
Cantona
User avatar
Joined: 26 Mar 2012
Last visit: 14 Oct 2016
Posts: 48
Own Kudos:
90
 [60]
Given Kudos: 3
Concentration: Social Entrepreneurship, Strategy
Schools: LBS '16 (M)
GMAT 1: 710 Q47 V40
GPA: 3.7
Schools: LBS '16 (M)
GMAT 1: 710 Q47 V40
Posts: 48
Kudos: 90
 [60]
The ‘moving walkway’ is a 300-foot long walkway consisting of a convey 30 May 2012, 19:24
44
Kudos
Add Kudos
13
Bookmarks
Bookmark this Post
This is how I broke it down:

Total Distance = 300 feet
default rate is 3fps (feet per second)
walking rate is 6fps (default + walking)
catch up rate: is walking rate - default rate = 6-3 = 3fps

Part 1: Time for Catch up
As he gets on the walk way he instantly starts "catching up" to the group that is 120 feet ahead of him. How long does this take?

D/R = Time; so 120feet/3fps [ note I'm using the catch up rate here ] = 40 seconds of catch up

After 40 seconds, how much of the 300 feet of the moonwalk has been used? well if he was moving for 40 seconds at 6 feet per second (he was walking) then he covered 240 feet of actual walkway.

300-240 feet = 60 feet.

There are only 60 feet left of walkway.

Part 2: Standing with the crowd
Now bill just idles with the crowd for the last 60 feet. 60ft/3fps [ note this is the default rate ] = 20 seconds.

Part 3: Average rate

6 fps for 40 seconds = 240 feet
3 fps for 20 seconds = 60 feet
X fps for 60 seconds = 300 feet

300/60 = 5fps average rate. Answer is E.
User avatar
KarishmaB
User avatar
Joined: 16 Oct 2010
Last visit: 18 Nov 2025
Posts: 16,265
Own Kudos:
76,981
 [48]
Given Kudos: 482
Location: Pune, India
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,265
Kudos: 76,981
 [48]
The ‘moving walkway’ is a 300-foot long walkway consisting of a convey Updated on: 13 Aug 2023, 23:37
Originally posted by KarishmaB on 28 May 2015, 20:20.
Last edited by KarishmaB on 13 Aug 2023, 23:37, edited 1 time in total.
24
Kudos
Add Kudos
22
Bookmarks
Bookmark this Post
Gmatter111
The ‘moving walkway’ is a 300-foot long walkway consisting of a conveyor belt that moves continuously at 3 feet per second. When Bill steps on the walkway, a group of people that are also on the walkway stands 120 feet in front of him. He walks toward the group at a rate of 3 feet per second. Once Bill reaches the group of people, he stops walking and stands with them until the walkway ends. What is Bill’s average rate of movement for his trip along the moving walkway?

A. 2 feet per second
B. 2.5 feet per second
C. 3 feet per second
D. 4 feet per second
E. 5 feet per second
Show more

Using relative speed concepts:

Bill covers 120 feet at a relative speed of 6 - 3 = 3 feet/sec. Time taken to cover 120 feet = 120/3 = 40 sec
Distance covered in 40 secs = 6*40 = 240 feet
So now he just has 300 - 240 = 60 feet leftover to cover at 3 feet/sec
Time taken to cover 60 feet = 60/3 = 20 sec

Average Speed = Total Distance/Total Time = 300/(40 + 20) = 5 feet/sec

Answer (E)

Check this video for when to use relative speed: https://youtu.be/wrYxeZ2WsEM
avatar
prome2
avatar
Joined: 25 Nov 2009
Last visit: 29 Aug 2010
Posts: 30
Own Kudos:
27
 [23]
Given Kudos: 4
Posts: 30
Kudos: 27
 [23]
The ‘moving walkway’ is a 300-foot long walkway consisting of a convey Updated on: 03 Dec 2009, 02:31
Originally posted by prome2 on 03 Dec 2009, 02:11.
Last edited by prome2 on 03 Dec 2009, 02:31, edited 1 time in total.
17
Kudos
Add Kudos
6
Bookmarks
Bookmark this Post
Here's what I think the answer should be
-------

Time Bill takes to catchup with group = 120/3
= 40 secs
Time Group has moved in 40 secs = 40 x 3
= 120 feet
Remaining Distance on walkway = 300 - 120 -120
= 60
Time taken to cover the last 60 ft = 60/3
= 20sec

Total time Bill spends on walkway = 40 + 20 = 60 secs
Total length of walkway = 300 feet

Bill's Average speed = 300/60 = 5 ft/sec
General Discussion
User avatar
kp1811
User avatar
Joined: 30 Aug 2009
Last visit: 05 Sep 2015
Posts: 128
Own Kudos:
382
 [1]
Given Kudos: 5
Location: India
Concentration: General Management
Posts: 128
Kudos: 382
 [1]
The ‘moving walkway’ is a 300-foot long walkway consisting of a convey 02 Dec 2009, 23:35
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Gmatter111
The ‘moving walkway’ is a 300-foot long walkway consisting of a conveyor belt that moves continuously at 3 feet per second. When Bill steps on the walkway, a group of people that are also on the walkway stands 120 feet in front of him. He walks toward the group at a rate of 3 feet per second. Once Bill reaches the group of people, he stops walking and stands with them until the walkway ends. What is Bill’s average rate of movement for his trip along the moving walkway?
Show more

3.75feet per second?

total distance is 300 feets
120 feet is covered at a speed of (Bills' speed + Belt Speed) = (3+3) = 6feet/sec. Time taken 20sec
remaining 180 feet is covered at a speed of (Bills' speed + Belt Speed) = (0+3) = 3feet/sec. Time taken 60sec

so total time taken to cover 300 foot long walkway is 80 sec. Avg Speed = 300/80 = 3.75 feet/sec
avatar
prome2
avatar
Joined: 25 Nov 2009
Last visit: 29 Aug 2010
Posts: 30
Own Kudos:
27
 [1]
Given Kudos: 4
Posts: 30
Kudos: 27
 [1]
The ‘moving walkway’ is a 300-foot long walkway consisting of a convey 03 Dec 2009, 02:25
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
kp1811
Gmatter111
The ‘moving walkway’ is a 300-foot long walkway consisting of a conveyor belt that moves continuously at 3 feet per second. When Bill steps on the walkway, a group of people that are also on the walkway stands 120 feet in front of him. He walks toward the group at a rate of 3 feet per second. Once Bill reaches the group of people, he stops walking and stands with them until the walkway ends. What is Bill’s average rate of movement for his trip along the moving walkway?

3.75feet per second?

total distance is 300 feets
120 feet is covered at a speed of (Bills' speed + Belt Speed) = (3+3) = 6feet/sec. Time taken 20sec
remaining 180 feet is covered at a speed of (Bills' speed + Belt Speed) = (0+3) = 3feet/sec. Time taken 60sec

so total time taken to cover 300 foot long walkway is 80 sec. Avg Speed = 300/80 = 3.75 feet/sec
Show more

I could be wrong, but the average of 2 average speeds is not the average speed of the entire journey.

Let's take a man cycling 60 miles to work, at 10 miles/hour there and 15 miles/hour back.
The average of the two average speeds will be 12.5 miles/hour

However, the computed average speed is total dist over total time.
If he cycles 10 miles/hour there, he will take 6 hours, and at 15 miles/hour back he will take 4 hours.

120miles/10 hours = 12 miles/hour

----

Although I believe weighted average could be used to compute average speed.
But you would need to know time travelled at each speed.

((AverageSpeed1*Time@Speed1) + (AverageSpeed2*Time@Speed2) / (TotalTime)
=((6*10)+(4*15)) / 10
User avatar
kp1811
User avatar
Joined: 30 Aug 2009
Last visit: 05 Sep 2015
Posts: 128
Own Kudos:
382
Given Kudos: 5
Location: India
Concentration: General Management
Posts: 128
Kudos: 382
The ‘moving walkway’ is a 300-foot long walkway consisting of a convey 03 Dec 2009, 04:40
Kudos
Add Kudos
Bookmarks
Bookmark this Post
kp1811
Gmatter111
The ‘moving walkway’ is a 300-foot long walkway consisting of a conveyor belt that moves continuously at 3 feet per second. When Bill steps on the walkway, a group of people that are also on the walkway stands 120 feet in front of him. He walks toward the group at a rate of 3 feet per second. Once Bill reaches the group of people, he stops walking and stands with them until the walkway ends. What is Bill’s average rate of movement for his trip along the moving walkway?

3.75feet per second?

total distance is 300 feets
120 feet is covered at a speed of (Bills' speed + Belt Speed) = (3+3) = 6feet/sec. Time taken 20sec
remaining 180 feet is covered at a speed of (Bills' speed + Belt Speed) = (0+3) = 3feet/sec. Time taken 60sec

so total time taken to cover 300 foot long walkway is 80 sec. Avg Speed = 300/80 = 3.75 feet/sec
Show more

my bad....the above is incorrect :(

120 feet is covered at a speed of (Bills' speed + Belt Speed) = (3+3) = 6feet/sec. Time taken 20sec
but in this 20sec the group moves a further of 20*3= 60feet so Bill will take another 60/6 =10sec to catch the group. Now remaining 120 feet will be covered in 120/3 = 40 sec. So total time to cover is 20+10+40 = 70sec
Avg speed = 300/70 = 30/7 feet/sec
User avatar
getmba
User avatar
Joined: 07 Jul 2009
Last visit: 14 Apr 2011
Posts: 110
Own Kudos:
792
Given Kudos: 13
Posts: 110
Kudos: 792
The ‘moving walkway’ is a 300-foot long walkway consisting of a convey 03 Dec 2009, 08:14
Kudos
Add Kudos
Bookmarks
Bookmark this Post
prome2
Here's what I think the answer should be
-------

Time Bill takes to catchup with group = 120/3
= 40 secs
Time Group has moved in 40 secs = 40 x 3
= 120 feet
Remaining Distance on walkway = 300 - 120 -120
= 60
Time taken to cover the last 60 ft = 60/3
= 20sec

Total time Bill spends on walkway = 40 + 20 = 60 secs
Total length of walkway = 300 feet

Bill's Average speed = 300/60 = 5 ft/sec
Show more

This is correct. Average speed is total distance/total time.
User avatar
kashishh
User avatar
Joined: 02 Jun 2011
Last visit: 15 Oct 2019
Posts: 89
Own Kudos:
432
Given Kudos: 11
Posts: 89
Kudos: 432
The ‘moving walkway’ is a 300-foot long walkway consisting of a convey 07 May 2012, 02:06
Kudos
Add Kudos
Bookmarks
Bookmark this Post
kp1811
kp1811
Gmatter111
The ‘moving walkway’ is a 300-foot long walkway consisting of a conveyor belt that moves continuously at 3 feet per second. When Bill steps on the walkway, a group of people that are also on the walkway stands 120 feet in front of him. He walks toward the group at a rate of 3 feet per second. Once Bill reaches the group of people, he stops walking and stands with them until the walkway ends. What is Bill’s average rate of movement for his trip along the moving walkway?

3.75feet per second?

total distance is 300 feets
120 feet is covered at a speed of (Bills' speed + Belt Speed) = (3+3) = 6feet/sec. Time taken 20sec
remaining 180 feet is covered at a speed of (Bills' speed + Belt Speed) = (0+3) = 3feet/sec. Time taken 60sec

so total time taken to cover 300 foot long walkway is 80 sec. Avg Speed = 300/80 = 3.75 feet/sec

my bad....the above is incorrect :(

120 feet is covered at a speed of (Bills' speed + Belt Speed) = (3+3) = 6feet/sec. Time taken 20sec
but in this 20sec the group moves a further of 20*3= 60feet so Bill will take another 60/6 =10sec to catch the group. Now remaining 120 feet will be covered in 120/3 = 40 sec. So total time to cover is 20+10+40 = 70sec
Avg speed = 300/70 = 30/7 feet/sec
Show more

is this correct? does the group move further, even so is it required to be calculated for bill?
User avatar
piyushksharma
User avatar
Joined: 21 Feb 2012
Last visit: 21 Mar 2019
Posts: 52
Own Kudos:
456
Given Kudos: 15
Location: Canada
Concentration: Finance, General Management
GMAT 1: 600 Q49 V23
GPA: 3.8
WE:Information Technology (Computer Software)
GMAT 1: 600 Q49 V23
Posts: 52
Kudos: 456
The ‘moving walkway’ is a 300-foot long walkway consisting of a convey 09 May 2012, 11:36
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Gmatter111
The ‘moving walkway’ is a 300-foot long walkway consisting of a conveyor belt that moves continuously at 3 feet per second. When Bill steps on the walkway, a group of people that are also on the walkway stands 120 feet in front of him. He walks toward the group at a rate of 3 feet per second. Once Bill reaches the group of people, he stops walking and stands with them until the walkway ends. What is Bill’s average rate of movement for his trip along the moving walkway?

A. 2 feet per second
B. 2.5 feet per second
C. 3 feet per second
D. 4 feet per second
E. 5 feet per second
Show more


Hi Bunuel, could u please explain how to solve this question...
Thanks in advance
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 18 Nov 2025
Posts: 105,355
Own Kudos:
778,069
Given Kudos: 99,964
Products:
GMAT Club Tests Forum Quiz
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,355
Kudos: 778,069
The ‘moving walkway’ is a 300-foot long walkway consisting of a convey 20 Sep 2013, 11:29
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Gmatter111
The ‘moving walkway’ is a 300-foot long walkway consisting of a conveyor belt that moves continuously at 3 feet per second. When Bill steps on the walkway, a group of people that are also on the walkway stands 120 feet in front of him. He walks toward the group at a rate of 3 feet per second. Once Bill reaches the group of people, he stops walking and stands with them until the walkway ends. What is Bill’s average rate of movement for his trip along the moving walkway?

A. 2 feet per second
B. 2.5 feet per second
C. 3 feet per second
D. 4 feet per second
E. 5 feet per second
Show more

Similar question to practice: barry-walks-from-one-end-to-the-other-of-a-30-meter-long-141013.html
avatar
IvanW
avatar
Joined: 05 Jun 2011
Last visit: 06 May 2014
Posts: 11
Own Kudos:
25
 [6]
Given Kudos: 36
Schools: Stern '16 Kellogg '16 Sloan '16 Stanford '16 HBS '16 Marshall '16
Posts: 11
Kudos: 25
 [6]
The ‘moving walkway’ is a 300-foot long walkway consisting of a convey 26 Sep 2013, 10:29
3
Kudos
Add Kudos
3
Bookmarks
Bookmark this Post
I agree with the above posters about the way to handle the equations (Catona & Prome2) but to me there is an option that hasn't been discussed that just POPS out at me. I don't know if it does for anyone else...

If you look at the options for the choices:

A. 2 feet per second
B. 2.5 feet per second
C. 3 feet per second
D. 4 feet per second
E. 5 feet per second

A, B, and C don't make ANY sense! we know for some time...(a majority of the 300ft) Bill will walk at a pace of 6ft per second...and then at some later time he will stop and move at 3 ft per second... The average MUST be between 3-6 ft per second or the Earth is FLAT!!!.

So we are down to D & E, D doesn't make sense on a weighted averages level because we know when Bill gets on the walkway the patrons are already 40% of the way down the 300ft walkway AND they are still moving at half the rate of Bill!! So for Bill to average 4 ft per second he would have had to spend a majority of the 300 ft at 3ft per second because 4 is much closer (when you factor in the size of the values we're dealing with 2 is double 1) to 3 than to 6. We know from the information that isn't possible. Bill must have spent the majority of his time at 6 ft per second before he stopped walking. That leaves only answer E as plausible.
User avatar
prasannajeet
User avatar
Joined: 26 Feb 2012
Last visit: 10 Nov 2017
Posts: 76
Own Kudos:
126
Given Kudos: 56
Location: India
Concentration: General Management, Finance
WE:Engineering (Telecommunications)
Posts: 76
Kudos: 126
The ‘moving walkway’ is a 300-foot long walkway consisting of a convey 22 Feb 2014, 02:20
Kudos
Add Kudos
Bookmarks
Bookmark this Post
prome2
Here's what I think the answer should be
-------

Time Bill takes to catchup with group = 120/3
= 40 secs
Time Group has moved in 40 secs = 40 x 3
= 120 feet......Please make me understand whether bill there in this group to cover 120 feet.......
Remaining Distance on walkway = 300 - 120 -120
= 60
Time taken to cover the last 60 ft = 60/3
= 20sec

Total time Bill spends on walkway = 40 + 20 = 60 secs
Total length of walkway = 300 feet

Bill's Average speed = 300/60 = 5 ft/sec
Show more

I was little confused please som1 help me out
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 18 Nov 2025
Posts: 105,355
Own Kudos:
778,069
 [2]
Given Kudos: 99,964
Products:
GMAT Club Tests Forum Quiz
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,355
Kudos: 778,069
 [2]
The ‘moving walkway’ is a 300-foot long walkway consisting of a convey 22 Feb 2014, 03:04
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
prasannajeet
prome2
Here's what I think the answer should be
-------

Time Bill takes to catchup with group = 120/3
= 40 secs
Time Group has moved in 40 secs = 40 x 3
= 120 feet......Please make me understand whether bill there in this group to cover 120 feet.......
Remaining Distance on walkway = 300 - 120 -120
= 60
Time taken to cover the last 60 ft = 60/3
= 20sec

Total time Bill spends on walkway = 40 + 20 = 60 secs
Total length of walkway = 300 feet

Bill's Average speed = 300/60 = 5 ft/sec

I was little confused please som1 help me out
Show more


No, he is not. Bill takes 40 seconds to catch up the group but in that time the walkway continues to move at 3 feet per second, thus the group (as well as Bill) moves 3*40=120 feet towards the end.

Hope it's clear.
avatar
breakfree1
avatar
Joined: 01 Sep 2013
Last visit: 04 Jun 2014
Posts: 1
Posts: 1
Kudos: 0
The ‘moving walkway’ is a 300-foot long walkway consisting of a convey 27 Feb 2014, 14:00
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hello,
I just bumped into this question, I solved it this way :
At time t, Bill meets the crowd at the the distance x, the crowd has covered 120+X :
=> X/6=(X+120)/3
=> X=720/3=240 feet (I neglected the sign '-', x being a distance, so an absolute value)
So, Bill spends 240/6 =40 sec to cover the 240 feet

Remain 60 feet that bills covers in : 60/3 = 20 s

Hence total time : 40+20=60 sec.t

Bill s rate is : 300/60 = 5 feet

I think there s sthg wrong with my reasoning but I cant figure it out
Thank you for helping :)
avatar
PareshGmat
avatar
Joined: 27 Dec 2012
Last visit: 10 Jul 2016
Posts: 1,534
Own Kudos:
8,099
Given Kudos: 193
Status:The Best Or Nothing
Location: India
Concentration: General Management, Technology
WE:Information Technology (Computer Software)
Posts: 1,534
Kudos: 8,099
The ‘moving walkway’ is a 300-foot long walkway consisting of a convey 28 Feb 2014, 02:52
Kudos
Add Kudos
Bookmarks
Bookmark this Post
First 240 Feet are covered @ 6 f/sec...... so time taken = 40sec
Last 60 Feet are covered @ 3 f/sec...... so time taken = 20sec

Total time = 60seconds, total distance = 300 Feets

Avg speed = 300/60 = 5 = Answer = E
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 18 Nov 2025
Posts: 105,355
Own Kudos:
778,069
Given Kudos: 99,964
Products:
GMAT Club Tests Forum Quiz
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,355
Kudos: 778,069
The ‘moving walkway’ is a 300-foot long walkway consisting of a convey 28 Feb 2014, 03:44
Kudos
Add Kudos
Bookmarks
Bookmark this Post
breakfree1
Hello,
I just bumped into this question, I solved it this way :
At time t, Bill meets the crowd at the the distance x, the crowd has covered 120+X :
=> X/6=(X+120)/3
=> X=720/3=240 feet (I neglected the sign '-', x being a distance, so an absolute value)
So, Bill spends 240/6 =40 sec to cover the 240 feet

Remain 60 feet that bills covers in : 60/3 = 20 s

Hence total time : 40+20=60 sec.t

Bill s rate is : 300/60 = 5 feet

I think there s sthg wrong with my reasoning but I cant figure it out
Thank you for helping :)
Show more

The equation should be \(\frac{x}{6}=\frac{(x-120)}{3}\) --> \(x=240\).

Hope it helps.
User avatar
pramendrapandeya
User avatar
Joined: 05 Jun 2012
Last visit: 14 Feb 2016
Posts: 33
Own Kudos:
55
Given Kudos: 66
Schools: IIMA
Schools: IIMA
Posts: 33
Kudos: 55
The ‘moving walkway’ is a 300-foot long walkway consisting of a convey 16 Apr 2014, 08:49
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I think all info should be one place ; so here goes

let x be total distance covered by Bill till he catches group of people

as we know speed=distance/time; as time will be equal when it will catch

x/6(relative speed bill +group)=total -120/3 (*obviously it will be added only then bill will be able to catch; total x but 120 is already covered)

x/6=x-120/3

x=240 covered by speed of 6 , so time took 240/6=40, rest 60 will be covered by 3 (*speed of wheel)=60/3=20

Avg. speed of bill= 300/(40+20)=5
avatar
Relaximus
avatar
Joined: 24 Mar 2015
Last visit: 09 Feb 2019
Posts: 1
Own Kudos:
4
 [4]
Posts: 1
Kudos: 4
 [4]
The ‘moving walkway’ is a 300-foot long walkway consisting of a convey 29 May 2015, 14:31
2
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
It took me 2.14 min. May be someone will find my way of solving this task useful.

Av Speed is TotalDistance / TotalTime.
TotalDistance = 300 ft
TotalTime = .... here's the trick. The Bill couldn't make it faster then group of people, because he joined them, so his time is just equal to the time of the group of peopel making the last 180 ft, which is 180/3 = 60 sec.

Av Speed = 300 / 60 = 5 ft/sec.

E.
avatar
Kalaimagal
avatar
Joined: 27 Aug 2015
Last visit: 19 Jan 2016
Posts: 1
Own Kudos:
1
 [1]
Given Kudos: 2
Posts: 1
Kudos: 1
 [1]
The ‘moving walkway’ is a 300-foot long walkway consisting of a convey 13 Jan 2016, 10:08
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
prasannajeet
prome2
Here's what I think the answer should be
-------

Time Bill takes to catchup with group = 120/3
= 40 secs
Time Group has moved in 40 secs = 40 x 3
= 120 feet......Please make me understand whether bill there in this group to cover 120 feet.......
Remaining Distance on walkway = 300 - 120 -120
= 60
Time taken to cover the last 60 ft = 60/3
= 20sec

Total time Bill spends on walkway = 40 + 20 = 60 secs
Total length of walkway = 300 feet

Bill's Average speed = 300/60 = 5 ft/sec

I was little confused please som1 help me out


No, he is not. Bill takes 40 seconds to catch up the group but in that time the walkway continues to move at 3 feet per second, thus the group (as well as Bill) moves 3*40=120 feet towards the end.

Hope it's clear.
Show more

If the group moves 120 feet in 40 sec, doesn't we should consider the time taken by the Bill to catch up to that 120 feet also. Can you please explain why we are not considering time taken for that?
 1   2   
Moderators:
Bunuel
Math Expert
105355 posts
Krunaal
Tuck School Moderator
805 posts