GMAT Question of the Day: Daily via email | Daily via Instagram New to GMAT Club? Watch this Video

 It is currently 29 May 2020, 13:25

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# The Simplastic language has only 2 unique vowels and 3 unique consonan

Author Message
TAGS:

### Hide Tags

Intern
Joined: 31 Oct 2010
Posts: 28
The Simplastic language has only 2 unique vowels and 3 unique consonan  [#permalink]

### Show Tags

Updated on: 06 Feb 2019, 07:57
7
58
00:00

Difficulty:

75% (hard)

Question Stats:

45% (01:25) correct 55% (01:28) wrong based on 872 sessions

### HideShow timer Statistics

The Simplastic language has only 2 unique vowels and 3 unique consonants. Every noun in Simplastic has the structure CVCVC, where C stands for a consonant and V stands for a vowel. How many different nouns are possible in Simplastic?

A. 9
B. 12
C. 36
D. 72
E. 108

Originally posted by mmcooley33 on 06 Dec 2010, 03:17.
Last edited by Bunuel on 06 Feb 2019, 07:57, edited 2 times in total.
Edited the question
Math Expert
Joined: 02 Sep 2009
Posts: 64242
Re: The Simplastic language has only 2 unique vowels and 3 unique consonan  [#permalink]

### Show Tags

06 Dec 2010, 04:46
6
7
mmcooley33 wrote:
The Simplastic language has only 2 unique values and 3 unique consonants. Every noun in Simplastic has the structure CVCVC, where C stands for a consonant and V stands for a vowel. How many different nouns are possible in Simplastic?

a.9
b.12
c.36
d.72
e.108

mmcooley33 wrote:
The answer is E because order does not matter making the combination 3*2*3*2*3?

The nouns have fixed structure C-V-C-V-C. Now, each C can take 3 values (let's say X, Y or Z) and each V can take 2 values (let's say A or E), so there will be 3*2*3*2*3=108 nouns possible.

It's basically the same if it were how many different 5-digit numbers are possible with the following structure odd-even-odd-even-odd, where odd numbers can be only 1, 3 or 5 and even numbers only 2 and 4.

108 is the answer if we assume that repetition is allowed, but how do we know whether repn is allowed or not if question doesnt mention anything

It's natural to think that a noun can have for example two same vowels (X-A-Y-A-Z) or 3 same consonants (X-A-X-A-X), so if this was not the case then this would be explicitly mentioned.
_________________
##### General Discussion
Intern
Joined: 31 Oct 2010
Posts: 28
Re: The Simplastic language has only 2 unique vowels and 3 unique consonan  [#permalink]

### Show Tags

06 Dec 2010, 03:19
3
The answer is E because order does not matter making the combination 3*2*3*2*3?
Manager
Joined: 02 Nov 2010
Posts: 77
Location: india
WE 1: 1.3
Re: The Simplastic language has only 2 unique vowels and 3 unique consonan  [#permalink]

### Show Tags

06 Dec 2010, 03:44
1
108 is the answer if we assume that repetition is allowed,but how do we know whether repn is allowed or not if question doesnt mention anything
Intern
Joined: 04 May 2009
Posts: 32
Location: Astoria, NYC
Re: The Simplastic language has only 2 unique vowels and 3 unique consonan  [#permalink]

### Show Tags

06 Dec 2010, 05:59
bunuel, what concept is this testing? I seem to not get the 3*2*3*2*3 aspect of your solution.
Math Expert
Joined: 02 Sep 2009
Posts: 64242
Re: The Simplastic language has only 2 unique vowels and 3 unique consonan  [#permalink]

### Show Tags

06 Dec 2010, 06:11
4
1
anish319 wrote:
bunuel, what concept is this testing? I seem to not get the 3*2*3*2*3 aspect of your solution.

Consider simpler case, 2-letter code Consonant-Vowel, where we can use only B, C or D for a consonant (3 options) and only A or E for a vowel (2 options). How many codes are possible?

BA;
BE;
CA;
CE;
DA;
DE.

So, total of 6 codes, 3*2=6, are possible. This is called Principle of Multiplication: If one event can occur in $$m$$ ways and a second can occur independently of the first in $$n$$ ways, then the two events can occur in $$mn$$ ways.

Now, the above is just expanded to CVCVC structure in the original question.

Hope it's clear.
_________________
Senior Manager
Status: Verbal Forum Moderator
Joined: 17 Apr 2013
Posts: 448
Location: India
GMAT 1: 710 Q50 V36
GMAT 2: 750 Q51 V41
GMAT 3: 790 Q51 V49
GPA: 3.3
Re: The Simplastic language has only 2 unique vowels and 3 unique consonan  [#permalink]

### Show Tags

18 Sep 2013, 03:18
1
Bunuel wrote:
mmcooley33 wrote:
The Simplastic language has only 2 unique values and 3 unique consonants. Every noun in Simplastic has the structure CVCVC, where C stands for a consonant and V stands for a vowel. How many different nouns are possible in Simplastic?

a.9
b.12
c.36
d.72
e.108

mmcooley33 wrote:
The answer is E because order does not matter making the combination 3*2*3*2*3?

The nouns have fixed structure C-V-C-V-C. Now, each C can take 3 values (let's say X, Y or Z) and each V can take 2 values (let's say A or E), so there will be 3*2*3*2*3=108 nouns possible.

It's basically the same if it were how many different 5-digit numbers are possible with the following structure odd-even-odd-even-odd, where odd numbers can be only 1, 3 or 5 and even numbers only 2 and 4.

108 is the answer if we assume that repetition is allowed, but how do we know whether repn is allowed or not if question doesnt mention anything

It's natural to think that a noun can have for example two same vowels (X-A-Y-A-Z) or 3 same consonants (X-A-X-A-X), so if this was not the case then this would be explicitly mentioned.

Great questions, at one point when this situation will arise, wouldn't we divide it by -

3*2*3*2*3/3!X2!
Manager
Joined: 24 Apr 2013
Posts: 50
Location: United States
Re: The Simplastic language has only 2 unique vowels and 3 unique consonan  [#permalink]

### Show Tags

20 Oct 2013, 05:04
My approach was as follows: 2 values and 3 constants can be counted as 2! * 3! = 12. I treated it as a counting problem with repeated values, why is this wrong?
Math Expert
Joined: 02 Sep 2009
Posts: 64242
Re: The Simplastic language has only 2 unique vowels and 3 unique consonan  [#permalink]

### Show Tags

20 Oct 2013, 05:09
Manager
Joined: 12 Sep 2014
Posts: 139
GMAT 1: 740 Q49 V41
GPA: 3.94
Re: The Simplastic language has only 2 unique vowels and 3 unique consonan  [#permalink]

### Show Tags

04 Oct 2014, 12:14
Answer is E. It just says any combination of CVCVC will work and so, calculate 3*2*3*2*3=108.

Doesn't mean 3*2*2*1*1, where you should subtract 1 each time. The letters can be re-used.
Intern
Joined: 16 May 2015
Posts: 26
Re: The Simplastic language has only 2 unique vowels and 3 unique consonan  [#permalink]

### Show Tags

26 May 2015, 18:59
Hi, do we need to account for the restriction that impose by the structure as C-V-C-V-C? as one V need to follow a C and we cant do C-C-C-V-V?
I am confused here..

And on top of it, when is it good to use the formula of combination and when we just use the method applied in this question ( like a number lock), thought believe that its the same concept?

Thank you..
Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 10477
Location: Pune, India
Re: The Simplastic language has only 2 unique vowels and 3 unique consonan  [#permalink]

### Show Tags

26 May 2015, 19:35
1
2
katzzzz wrote:
Hi, do we need to account for the restriction that impose by the structure as C-V-C-V-C? as one V need to follow a C and we cant do C-C-C-V-V?
I am confused here..

And on top of it, when is it good to use the formula of combination and when we just use the method applied in this question ( like a number lock), thought believe that its the same concept?

Thank you..

We are accounting for it by calculating only the number of ways of writing CVCVC. So the other arrangements of 3Cs and 2Vs are ignored.
You can write the first C in 3 ways.
You can write the next letter V in 2 ways.
The next letter is again C for which we again have 3 options (note that repetition of letters is not a problem)
The next letter V can be chosen in 2 ways.
The last letter C can be chosen in 3 ways again.
This gives us 3*2*3*2*3 = 108 ways.

You use the combination formula only when you have to select a few things out of many things. Here, no selection is required. Say, if there were 10 consonants and we had to make the nouns using 3 DISTINCT consonants, then we would have SELECTED 3 of the 10 (in 10C3 ways) and then arranged them in 3 places in 3! ways.
The method used in this question is the basic counting principle. It is used when you have distinct places for things. I suggest you to check out these posts:
http://www.veritasprep.com/blog/2011/10 ... inatorics/
http://www.veritasprep.com/blog/2011/11 ... binations/
_________________
Karishma
Veritas Prep GMAT Instructor

Intern
Joined: 16 May 2015
Posts: 26
Re: The Simplastic language has only 2 unique vowels and 3 unique consonan  [#permalink]

### Show Tags

27 May 2015, 04:07
thank you! it really helps! for special seating arrangement ( A must proceed by B), guess we use the same approach here rather than the formula as we don't have to choose something from a group?
Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 10477
Location: Pune, India
Re: The Simplastic language has only 2 unique vowels and 3 unique consonan  [#permalink]

### Show Tags

27 May 2015, 18:59
1
1
katzzzz wrote:
thank you! it really helps! for special seating arrangement ( A must proceed by B), guess we use the same approach here rather than the formula as we don't have to choose something from a group?

Yes, you use this concept for arrangements. Here is how you solve linear arrangements with constraints:

http://www.veritasprep.com/blog/2011/10 ... ts-part-i/
http://www.veritasprep.com/blog/2011/10 ... s-part-ii/
_________________
Karishma
Veritas Prep GMAT Instructor

Manager
Joined: 13 Mar 2013
Posts: 153
Location: United States
GPA: 3.5
WE: Engineering (Telecommunications)
Re: The Simplastic language has only 2 unique vowels and 3 unique consonan  [#permalink]

### Show Tags

15 Jul 2015, 05:21
Hi Bunuel ,

for any question on combination in GMAT . if no condition is stated then can we say that ... repetition is allowed .

_________________
Regards ,
Senior Manager
Joined: 28 Jun 2015
Posts: 272
Concentration: Finance
GPA: 3.5
Re: The Simplastic language has only 2 unique vowels and 3 unique consonan  [#permalink]

### Show Tags

15 Jul 2015, 07:33
Vowels - 2, Consonants - 3.

c-v-c-v-c = 3*2*3*2*3 = 108. Ans (E).
_________________
I used to think the brain was the most important organ. Then I thought, look what’s telling me that.
Director
Joined: 13 Mar 2017
Posts: 717
Location: India
Concentration: General Management, Entrepreneurship
GPA: 3.8
WE: Engineering (Energy and Utilities)
Re: The Simplastic language has only 2 unique vowels and 3 unique consonan  [#permalink]

### Show Tags

16 Aug 2017, 11:08
TheKingInTheNorth wrote:
Hi Bunuel ,

for any question on combination in GMAT . if no condition is stated then can we say that ... repetition is allowed .

Yes if the question is not providing any restriction on repetition means repetition is allowed... Also this is logical as we have repetition allowed in forming word (for e.g. rEpETITIon.)
Director
Joined: 13 Mar 2017
Posts: 717
Location: India
Concentration: General Management, Entrepreneurship
GPA: 3.8
WE: Engineering (Energy and Utilities)
Re: The Simplastic language has only 2 unique vowels and 3 unique consonan  [#permalink]

### Show Tags

16 Aug 2017, 11:11
mmcooley33 wrote:
The Simplastic language has only 2 unique values and 3 unique consonants. Every noun in Simplastic has the structure CVCVC, where C stands for a consonant and V stands for a vowel. How many different nouns are possible in Simplastic?

A. 9
B. 12
C. 36
D. 72
E. 108

Since the noun has a structure CVCVC
1st alphabet C can take 3 values
2nd alphabet V can take 2 values
3rd alphabet C can take 3 values
4th alphabet V can take 2 values
5th alphabet C can take 3 values

So, different nouns possible = 3*2*3*2*3 = 108

Intern
Joined: 28 Sep 2016
Posts: 17
Re: The Simplastic language has only 2 unique vowels and 3 unique consonan  [#permalink]

### Show Tags

16 Aug 2017, 20:31
Dear Math Experts,

What will be answer if repetition in CVCVC is not allowed(once a vowel or consonant is used it cannot be used again)

Thanks
Joepc
Director
Joined: 13 Mar 2017
Posts: 717
Location: India
Concentration: General Management, Entrepreneurship
GPA: 3.8
WE: Engineering (Energy and Utilities)
Re: The Simplastic language has only 2 unique vowels and 3 unique consonan  [#permalink]

### Show Tags

16 Aug 2017, 21:18
joepc wrote:
Dear Math Experts,

What will be answer if repetition in CVCVC is not allowed(once a vowel or consonant is used it cannot be used again)

Thanks
Joepc

In that case 1st C can take 3 values, 2nd C can take 2 values and 3rd C can take 1 value.

Similarly 1st V can take 2 values and 2nd V van take 1 value..

So, total no. of words formed = 3*2*1*2*1 = 12...
Re: The Simplastic language has only 2 unique vowels and 3 unique consonan   [#permalink] 16 Aug 2017, 21:18

Go to page    1   2    Next  [ 31 posts ]