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Re: The table above is a 3 by 3 grid of 9 numbers, 5 of which are given [#permalink]
Hi all,

Does anyone know where 6*sqrt(6) is coming from?

Thank you.
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Re: The table above is a 3 by 3 grid of 9 numbers, 5 of which are given [#permalink]
HarveyKlaus
Hi all,

Does anyone know where 6*sqrt(6) is coming from?

Thank you.

Refer to the center column that has numbers 1, 6 and sqrt(6). Multiply and you will get 6*sqrt(6).
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Re: The table above is a 3 by 3 grid of 9 numbers, 5 of which are given [#permalink]
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just square each number in the table and then the solution becomes obvious


A 1 12
B 6 6
3 6 D


so we need 6*6=36

cheers
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Re: The table above is a 3 by 3 grid of 9 numbers, 5 of which are given [#permalink]
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daviddaviddavid
just square each number in the table and then the solution becomes obvious


A 1 12
B 6 6
3 6 D


so we need 6*6=36

cheers
6^2 does not equal 6, (see column 2, row 3). Can you elaborate?
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The table above is a 3 by 3 grid of 9 numbers, 5 of which are given [#permalink]
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Smokeybear00
daviddaviddavid
just square each number in the table and then the solution becomes obvious


A 1 12
B 6 6
3 6 D


so we need 6*6=36

cheers


6^2 does not equal 6, (see column 2, row 3). Can you elaborate?

If you look at the question, the middle column reads 1,6,\(\sqrt{6}\) not 1,6,6
Hence squaring it will give you 1,36 and 6.

Btw, why are you squaring the numbers?

The solution to this problem is as follows :

Since the product of each of the rows and columns must be equal, only the center row has all three values,
the product of which is 6*\(\sqrt{6}\)

We need to find the product of A,B,C,D.

From the first row :
A * B * sqrt(3) = 6*sqrt(6) ==> A * B = 6 * sqrt(2)
From the third row :
C * D * 2sqrt(3) = 6*sqrt(6) ==> C * D = 3 * sqrt(2)

Therefore product of A,B,C and D as asked in the question is (6*sqrt(2))*(3*sqrt(2)) =6*3*2 = 36(Option A)

Hope it helps!
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Re: The table above is a 3 by 3 grid of 9 numbers, 5 of which are given [#permalink]
Smokeybear00
daviddaviddavid
just square each number in the table and then the solution becomes obvious


A 1 12
B 6 6
3 6 D


so we need 6*6=36

cheers
6^2 does not equal 6, (see column 2, row 3). Can you elaborate?


well, Im sorry I made a careless mistake, but you should get the point ;)


A 1 12
B 6 6
3 36 D
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Re: The table above is a 3 by 3 grid of 9 numbers, 5 of which are given [#permalink]
pushpitkc
Smokeybear00
daviddaviddavid
just square each number in the table and then the solution becomes obvious


A 1 12
B 6 6
3 6 D


so we need 6*6=36

cheers


6^2 does not equal 6, (see column 2, row 3). Can you elaborate?

If you look at the question, the middle column reads 1,6,\(\sqrt{6}\) not 1,6,6
Hence squaring it will give you 1,36 and 6.

Btw, why are you squaring the numbers?

The solution to this problem is as follows :

Since the product of each of the rows and columns must be equal, only the center row has all three values,
the product of which is 6*\(\sqrt{6}\)

We need to find the product of A,B,C,D.

From the first row :
A * B * sqrt(3) = 6*sqrt(6) ==> A * B = 6 * sqrt(2)
From the third row :
C * D * 2sqrt(3) = 6*sqrt(6) ==> C * D = 3 * sqrt(2)

Therefore product of A,B,C and D as asked in the question is (6*sqrt(2))*(3*sqrt(2)) =6*3*2 = 36(Option A)

Hope it helps!

yes thanks, I made a careless mistake

I squared the numbers, because for me the problem becomes much easier
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Re: The table above is a 3 by 3 grid of 9 numbers, 5 of which are given [#permalink]
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The table above is a 3 by 3 grid of 9 numbers, 5 of which are given. The 4 numbers that are not given are denoted by A, B, C, and D. The product of the numbers in each row and in each column is the same for all rows and columns. What is the value of the product ABCD ?

From Second column we see that the multiplication for each row/columns should be \(= 6 * \sqrt{6}\)

\(= 2 * 3 * \sqrt{3} * \sqrt{2}\)

\(AB * \sqrt{3}\) \(= 2 * 3 * \sqrt{3} * \sqrt{2}\)

\(AB = 6 * \sqrt{2}\)

\(CD * 2\sqrt{3}\) \(= 2 * 3 * \sqrt{3} * \sqrt{2}\)

\(CD = 3 * \sqrt{2}\)

\(AB * CD = 6 * \sqrt{2} * 3 * \sqrt{2}\)

\(AB * CD = 18 * 2\)

\(AB * CD = 36\)

Hence, Answer is A
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Re: The table above is a 3 by 3 grid of 9 numbers, 5 of which are given [#permalink]
2
Kudos
A faster way to solve this

All product = 6√6

A x B x √3 = 6√6, AB = (6√6 / √3)
C x D x 2√3 = 6√6, CD = (6√6 / 2√3)
A x B x C x D = (6√6 / 2√3) x (6√6 / √3) = (6 x 6 x 6) / ( 2 x 3) = 36

Don't solve for individual value, waste too much time
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Re: The table above is a 3 by 3 grid of 9 numbers, 5 of which are given [#permalink]
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Re: The table above is a 3 by 3 grid of 9 numbers, 5 of which are given [#permalink]
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