GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 15 Nov 2018, 15:28

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Events & Promotions in November
PrevNext
SuMoTuWeThFrSa
28293031123
45678910
11121314151617
18192021222324
2526272829301
Open Detailed Calendar
  • Free GMAT Strategy Webinar

     November 17, 2018

     November 17, 2018

     07:00 AM PST

     09:00 AM PST

    Nov. 17, 7 AM PST. Aiming to score 760+? Attend this FREE session to learn how to Define your GMAT Strategy, Create your Study Plan and Master the Core Skills to excel on the GMAT.
  • GMATbuster's Weekly GMAT Quant Quiz # 9

     November 17, 2018

     November 17, 2018

     09:00 AM PST

     11:00 AM PST

    Join the Quiz Saturday November 17th, 9 AM PST. The Quiz will last approximately 2 hours. Make sure you are on time or you will be at a disadvantage.

The table above is a 3 by 3 grid of 9 numbers, 5 of which are given

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Director
Director
User avatar
V
Joined: 06 Jan 2015
Posts: 513
Location: India
Concentration: Operations, Finance
GPA: 3.35
WE: Information Technology (Computer Software)
Premium Member
The table above is a 3 by 3 grid of 9 numbers, 5 of which are given  [#permalink]

Show Tags

New post Updated on: 30 Jul 2016, 06:16
2
9
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

81% (02:23) correct 19% (02:49) wrong based on 253 sessions

HideShow timer Statistics

Image
The table above is a 3 by 3 grid of 9 numbers, 5 of which are given. The 4 numbers that are not given are denoted by A, B, C, and D. The product of the numbers in each row and in each column is the same for all rows and columns. What is the value of the product ABCD ?

A) 36

B) 72

C) \(36\sqrt{2}\)

D) \(36\sqrt{3}\)

E) \(72\sqrt{6}\)

Attachment:
Table.jpg
Table.jpg [ 6.52 KiB | Viewed 6767 times ]

_________________

आत्मनॊ मोक्षार्थम् जगद्धिताय च

Resource: GMATPrep RCs With Solution


Originally posted by NandishSS on 30 Jul 2016, 05:05.
Last edited by Bunuel on 30 Jul 2016, 06:16, edited 1 time in total.
Edited the question.
Most Helpful Community Reply
SC Moderator
User avatar
D
Joined: 13 Apr 2015
Posts: 1689
Location: India
Concentration: Strategy, General Management
GMAT 1: 200 Q1 V1
GPA: 4
WE: Analyst (Retail)
GMAT ToolKit User Premium Member
Re: The table above is a 3 by 3 grid of 9 numbers, 5 of which are given  [#permalink]

Show Tags

New post 30 Jul 2016, 07:42
4
1
A * B * sqrt(3) = 6*sqrt(6)
A * B = 6 * sqrt(2)

C * D * 2sqrt(3) = 6*sqrt(6)
C * D = 3 * sqrt(2)

A * B * C * D = 6 * 3 * 2 = 36

Answer: A
General Discussion
Manager
Manager
avatar
Joined: 18 Feb 2015
Posts: 85
Re: The table above is a 3 by 3 grid of 9 numbers, 5 of which are given  [#permalink]

Show Tags

New post 14 Aug 2016, 09:50
Hi all,

Does anyone know where 6*sqrt(6) is coming from?

Thank you.
SC Moderator
User avatar
D
Joined: 13 Apr 2015
Posts: 1689
Location: India
Concentration: Strategy, General Management
GMAT 1: 200 Q1 V1
GPA: 4
WE: Analyst (Retail)
GMAT ToolKit User Premium Member
Re: The table above is a 3 by 3 grid of 9 numbers, 5 of which are given  [#permalink]

Show Tags

New post 14 Aug 2016, 19:48
HarveyKlaus wrote:
Hi all,

Does anyone know where 6*sqrt(6) is coming from?

Thank you.


Refer to the center column that has numbers 1, 6 and sqrt(6). Multiply and you will get 6*sqrt(6).
Manager
Manager
avatar
B
Joined: 26 Mar 2017
Posts: 131
Re: The table above is a 3 by 3 grid of 9 numbers, 5 of which are given  [#permalink]

Show Tags

New post 22 Jun 2017, 07:40
just square each number in the table and then the solution becomes obvious


A 1 12
B 6 6
3 6 D


so we need 6*6=36

cheers
_________________

I hate long and complicated explanations!

Manager
Manager
avatar
S
Joined: 30 May 2017
Posts: 66
Concentration: Finance, General Management
GMAT 1: 690 Q47 V38
GPA: 3.23
Re: The table above is a 3 by 3 grid of 9 numbers, 5 of which are given  [#permalink]

Show Tags

New post 22 Jun 2017, 11:32
daviddaviddavid wrote:
just square each number in the table and then the solution becomes obvious


A 1 12
B 6 6
3 6 D


so we need 6*6=36

cheers

6^2 does not equal 6, (see column 2, row 3). Can you elaborate?
_________________

Veritas Prep 6/18/17 600 Q:38 V:35 IR:5
Veritas Prep 6/29/17 620 Q:43 V:33 IR:4
Manhattan 7/12/17 640 Q:42 V:35 IR:2.4
Veritas Prep 7/27/17 640 Q:41 V:37 IR:4
Manhattan 8/9/17 670 Q:44 V:37 IR:3
Veritas Prep 8/21/17 660 Q:45 V:36 IR:7
GMAT Prep 8/23/17 700 Q:47 V:38 IR:8
GMAT Prep 8/27/17 730 Q:49 V:40 IR:8
Veritas Prep 8/30/17 690 Q:47 V:37 IR:8

Senior PS Moderator
User avatar
V
Joined: 26 Feb 2016
Posts: 3307
Location: India
GPA: 3.12
Premium Member CAT Tests
The table above is a 3 by 3 grid of 9 numbers, 5 of which are given  [#permalink]

Show Tags

New post 22 Jun 2017, 12:24
Smokeybear00 wrote:
daviddaviddavid wrote:
just square each number in the table and then the solution becomes obvious


A 1 12
B 6 6
3 6 D


so we need 6*6=36

cheers



6^2 does not equal 6, (see column 2, row 3). Can you elaborate?


If you look at the question, the middle column reads 1,6,\(\sqrt{6}\) not 1,6,6
Hence squaring it will give you 1,36 and 6.

Btw, why are you squaring the numbers?

The solution to this problem is as follows :

Since the product of each of the rows and columns must be equal, only the center row has all three values,
the product of which is 6*\(\sqrt{6}\)

We need to find the product of A,B,C,D.

From the first row :
A * B * sqrt(3) = 6*sqrt(6) ==> A * B = 6 * sqrt(2)
From the third row :
C * D * 2sqrt(3) = 6*sqrt(6) ==> C * D = 3 * sqrt(2)

Therefore product of A,B,C and D as asked in the question is (6*sqrt(2))*(3*sqrt(2)) =6*3*2 = 36(Option A)

Hope it helps!
_________________

You've got what it takes, but it will take everything you've got

Manager
Manager
avatar
B
Joined: 26 Mar 2017
Posts: 131
Re: The table above is a 3 by 3 grid of 9 numbers, 5 of which are given  [#permalink]

Show Tags

New post 23 Jun 2017, 00:40
Smokeybear00 wrote:
daviddaviddavid wrote:
just square each number in the table and then the solution becomes obvious


A 1 12
B 6 6
3 6 D


so we need 6*6=36

cheers

6^2 does not equal 6, (see column 2, row 3). Can you elaborate?



well, Im sorry I made a careless mistake, but you should get the point ;)


A 1 12
B 6 6
3 36 D
_________________

I hate long and complicated explanations!

Manager
Manager
avatar
B
Joined: 26 Mar 2017
Posts: 131
Re: The table above is a 3 by 3 grid of 9 numbers, 5 of which are given  [#permalink]

Show Tags

New post 23 Jun 2017, 00:41
pushpitkc wrote:
Smokeybear00 wrote:
daviddaviddavid wrote:
just square each number in the table and then the solution becomes obvious


A 1 12
B 6 6
3 6 D


so we need 6*6=36

cheers



6^2 does not equal 6, (see column 2, row 3). Can you elaborate?


If you look at the question, the middle column reads 1,6,\(\sqrt{6}\) not 1,6,6
Hence squaring it will give you 1,36 and 6.

Btw, why are you squaring the numbers?

The solution to this problem is as follows :

Since the product of each of the rows and columns must be equal, only the center row has all three values,
the product of which is 6*\(\sqrt{6}\)

We need to find the product of A,B,C,D.

From the first row :
A * B * sqrt(3) = 6*sqrt(6) ==> A * B = 6 * sqrt(2)
From the third row :
C * D * 2sqrt(3) = 6*sqrt(6) ==> C * D = 3 * sqrt(2)

Therefore product of A,B,C and D as asked in the question is (6*sqrt(2))*(3*sqrt(2)) =6*3*2 = 36(Option A)

Hope it helps!


yes thanks, I made a careless mistake

I squared the numbers, because for me the problem becomes much easier
_________________

I hate long and complicated explanations!

Target Test Prep Representative
User avatar
G
Status: Head GMAT Instructor
Affiliations: Target Test Prep
Joined: 04 Mar 2011
Posts: 2830
Re: The table above is a 3 by 3 grid of 9 numbers, 5 of which are given  [#permalink]

Show Tags

New post 26 Jun 2017, 17:01
1
1
NandishSS wrote:
Image
The table above is a 3 by 3 grid of 9 numbers, 5 of which are given. The 4 numbers that are not given are denoted by A, B, C, and D. The product of the numbers in each row and in each column is the same for all rows and columns. What is the value of the product ABCD ?

A) 36

B) 72

C) \(36\sqrt{2}\)

D) \(36\sqrt{3}\)

E) \(72\sqrt{6}\)

Attachment:
Table.jpg


We can start with the middle column:

1 x √6 x 6 = 6√6.

Thus, we know that the entries in each row and in each column multiply to yield 6√6.

For Row 1:

A x 1 x 2√3 = 6√6

A = (6√6)/(2√3)

A = 3√2

For Column 1:

3√2 x B x √3 = 6√6

B x 3√6 = 6√6

B = (6√6)/(3√6)

B = 2

For Row 2:

2 x √6 x C = 6√6

C = (6√6)/(2√6)

C = 3

For Row 3:

√3 x 6 x D = 6√6

D = (6√6)/(6√3)

D = √2

Thus, ABCD =

3√2 x 2 x 3 x √2 = 18√2 x √2 = 36

Answer: A
_________________

Jeffery Miller
Head of GMAT Instruction

GMAT Quant Self-Study Course
500+ lessons 3000+ practice problems 800+ HD solutions

Retired Moderator
User avatar
P
Joined: 19 Mar 2014
Posts: 945
Location: India
Concentration: Finance, Entrepreneurship
GPA: 3.5
GMAT ToolKit User Premium Member
Re: The table above is a 3 by 3 grid of 9 numbers, 5 of which are given  [#permalink]

Show Tags

New post 27 Jun 2017, 13:49
1
The table above is a 3 by 3 grid of 9 numbers, 5 of which are given. The 4 numbers that are not given are denoted by A, B, C, and D. The product of the numbers in each row and in each column is the same for all rows and columns. What is the value of the product ABCD ?

From Second column we see that the multiplication for each row/columns should be \(= 6 * \sqrt{6}\)

\(= 2 * 3 * \sqrt{3} * \sqrt{2}\)

\(AB * \sqrt{3}\) \(= 2 * 3 * \sqrt{3} * \sqrt{2}\)

\(AB = 6 * \sqrt{2}\)

\(CD * 2\sqrt{3}\) \(= 2 * 3 * \sqrt{3} * \sqrt{2}\)

\(CD = 3 * \sqrt{2}\)

\(AB * CD = 6 * \sqrt{2} * 3 * \sqrt{2}\)

\(AB * CD = 18 * 2\)

\(AB * CD = 36\)

Hence, Answer is A
_________________

"Nothing in this world can take the place of persistence. Talent will not: nothing is more common than unsuccessful men with talent. Genius will not; unrewarded genius is almost a proverb. Education will not: the world is full of educated derelicts. Persistence and determination alone are omnipotent."

Best AWA Template: https://gmatclub.com/forum/how-to-get-6-0-awa-my-guide-64327.html#p470475

Non-Human User
User avatar
Joined: 09 Sep 2013
Posts: 8772
Premium Member
Re: The table above is a 3 by 3 grid of 9 numbers, 5 of which are given  [#permalink]

Show Tags

New post 15 Jul 2018, 06:56
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

GMAT Books | GMAT Club Tests | Best Prices on GMAT Courses | GMAT Mobile App | Math Resources | Verbal Resources

GMAT Club Bot
Re: The table above is a 3 by 3 grid of 9 numbers, 5 of which are given &nbs [#permalink] 15 Jul 2018, 06:56
Display posts from previous: Sort by

The table above is a 3 by 3 grid of 9 numbers, 5 of which are given

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


Copyright

GMAT Club MBA Forum Home| About| Terms and Conditions and Privacy Policy| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.