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Senior Manager
Status: Math is psychological
Joined: 07 Apr 2014
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Location: Netherlands
GMAT Date: 02112015
WE: Psychology and Counseling (Other)

There are 1600 jelly beans divided between two jars, X and Y. If the
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06 Feb 2015, 09:03
Question Stats:
74% (02:04) correct 26% (02:17) wrong based on 186 sessions
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There are 1600 jelly beans divided between two jars, X and Y. If there are 100 fewer jelly beans in jar X than three times the number of beans in jar Y, how many beans are in jar X? A. 375 B. 950 C. 1150 D. 1175 E. 1350
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Re: There are 1600 jelly beans divided between two jars, X and Y. If the
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06 Feb 2015, 13:43
Hi All, This question can certainly be solved with Algebra; with 2 variables and 2 unique equations, it's just a matter of translating the text into equations and doing "system" math. The answers are numbers though, and there is a logical pattern in the prompt that you can use to quickly TEST THE ANSWERS. We're told that there are a total of 1600 marbles in two jars. Jar X has 100 less than THREE TIMES the number of marbles in Jar Y. We're asked for the number of marbles in Jar X. 100 marbles is a relatively small amount, compared to the 1600 total marbles. If we ignore the "100" and do a rough estimation, Jar X would be about 1200 and Jar Y would be about 400 (which matches the information about THREE TIMES the number of marbles). Since we DO have to factor in the 100 marbles though, the number of marbles in X has to be LESS than 1200. With this deduction, the answer has to be C or D. Let's TEST C (since it looks like the "nicer" number to deal with). IF.... X = 1150 marbles X + 100 = 1250 1250/3 = 416.6666 marbles 1150 + 416.66666 is NOT 1600 total marbles. Eliminate C. Final Answer: Here's the proof though: IF.... X = 1175 marbles X + 100 = 1275 1275/3 = 425 1175 + 425 = 1600 marbles GMAT assassins aren't born, they're made, Rich
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Joined: 05 Sep 2013
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Re: There are 1600 jelly beans divided between two jars, X and Y. If the
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06 Feb 2015, 13:28
x+y=1600 , X=1600Y x+100=3y, 1700=4Y Y=425
x=1600y=1600425=1175 D



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Joined: 04 Dec 2015
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Re: There are 1600 jelly beans divided between two jars, X and Y. If the
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06 Nov 2018, 20:08
pacifist85 wrote: There are 1600 jelly beans divided between two jars, X and Y. If there are 100 fewer jelly beans in jar X than three times the number of beans in jar Y, how many beans are in jar X?
A. 375
B. 950
C. 1150
D. 1175
E. 1350 Let Jelly beans in jar \(X = x\) and \(Y = y\) \(x + y = 1600\)  (\(i\)) Given jar \(X\) has \(100\) fewer jelly beans than three times the number of beans in jar \(Y\). Therefore; \(x + 100 = 3y\) \(x = 3y  100\) Substituting value of \(x\) in equation (\(i\)), we get; \(3y  100 + y = 1600\) \(4y = 1600 + 100 = 1700\) \(y = \frac{1700}{4} = 425\) Substituting value of \(y\) in equation (\(i\)), we get; \(x + 425 = 1600\) \(x = 1600\) \(\) \(425 = 1175\) Answer D



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Joined: 16 May 2018
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Re: There are 1600 jelly beans divided between two jars, X and Y. If the
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08 Mar 2019, 17:52
Hi, If X has 100 fewer jelly beans than three times the number of beans in jar Y. Then why did we write X+100 ? Shouldnt it be X100?



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Joined: 19 Apr 2017
Posts: 21
Location: Brazil
Concentration: Finance, Entrepreneurship
GPA: 3

Re: There are 1600 jelly beans divided between two jars, X and Y. If the
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08 Mar 2019, 19:35
x+y=1600 (I)
And
3*y = x100
Reorganizing it
3*y100 = x (II)
Subs. (II) in (I)
3*y100+y=1600 4*y=1700 y=425
Then
x=1175
Ans (D)



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Re: There are 1600 jelly beans divided between two jars, X and Y. If the
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09 Mar 2019, 03:13
3*y = x100
Reorganizing it
3*y100 = x (II)
But if 100 go to the other side of equation, shouldnt it become +100?



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Concentration: Finance, Entrepreneurship
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Re: There are 1600 jelly beans divided between two jars, X and Y. If the
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09 Mar 2019, 10:08
hsn81960 wrote: 3*y = x100
Reorganizing it
3*y100 = x (II)
But if 100 go to the other side of equation, shouldnt it become +100? Sorry, it's 3*y = x +100 instead




Re: There are 1600 jelly beans divided between two jars, X and Y. If the
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09 Mar 2019, 10:08






