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madhavsrinivas
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I got it wrong since I used the 81 to prove there was only one team leader but:

With statement B alone we can mange to find it:

Since there is L<D, L should be 1 2 3 or 4.

But if L is 2 than the number of D should be divided in 2, meaning ... That we have 2.5 directors. Impossible.

Same logic with 3 and 4...

The only possible answer is 1. Choice C only helps to confirm this answer!

Am I right here?
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Hey... I'm not sure about this one, I feel A is sufficient too.

From the question we've got:

Total number of people on Dallas team = L + L*D + L*D*F = L * (D + D*F + 1) = L * (D(1+F) + 1) = 81

Given that 81 = 3^4, L must be either 1, 3, 9, 27, or 81. However we also know that L>D, so there's no need to check the combinations where L = 9 or higher.

There a bunch of combinations where L=1, as D can then be equal to any factor of 81-1.
However, there are no combinations where L=3 and where L>D, because in that case D must be a factor of 26, i.e. 1, 2, or 13. 3 is larger than 1 or 2, and 13 doesn't work because in that case F = 1, and 13 Directors can't split 1 fundraiser between them!

So I find that prompt A is sufficient to determine that L = 1.

But VeritasPrep's CAT says I'm wrong, as does this thread, so please explain what I'm missing here!
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li220
Hey... I'm not sure about this one, I feel A is sufficient too.

From the question we've got:

Total number of people on Dallas team = L + L*D + L*D*F = L * (D + D*F + 1) = L * (D(1+F) + 1) = 81

Given that 81 = 3^4, L must be either 1, 3, 9, 27, or 81. However we also know that L>D, so there's no need to check the combinations where L = 9 or higher.

There a bunch of combinations where L=1, as D can then be equal to any factor of 81-1.
However, there are no combinations where L=3 and where L>D, because in that case D must be a factor of 26, i.e. 1, 2, or 13. 3 is larger than 1 or 2, and 13 doesn't work because in that case F = 1, and 13 Directors can't split 1 fundraiser between them!

So I find that prompt A is sufficient to determine that L = 1.

But VeritasPrep's CAT says I'm wrong, as does this thread, so please explain what I'm missing here!

hi, the highlighted portion is wrong. it's actually the other way around. D>L. now try for L=3, we have D=13 and F=2.

i hope it helps.
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manpreetsingh86
li220
Hey... I'm not sure about this one, I feel A is sufficient too.

From the question we've got:

Total number of people on Dallas team = L + L*D + L*D*F = L * (D + D*F + 1) = L * (D(1+F) + 1) = 81

Given that 81 = 3^4, L must be either 1, 3, 9, 27, or 81. However we also know that L>D, so there's no need to check the combinations where L = 9 or higher.

There a bunch of combinations where L=1, as D can then be equal to any factor of 81-1.
However, there are no combinations where L=3 and where L>D, because in that case D must be a factor of 26, i.e. 1, 2, or 13. 3 is larger than 1 or 2, and 13 doesn't work because in that case F = 1, and 13 Directors can't split 1 fundraiser between them!

So I find that prompt A is sufficient to determine that L = 1.

But VeritasPrep's CAT says I'm wrong, as does this thread, so please explain what I'm missing here!

hi, the highlighted portion is wrong. it's actually the other way around. D>L. now try for L=3, we have D=13 and F=2.

i hope it helps.


Hey thanks Manpreet. You're right, i meant D>L. You've made me realise that actually my mistake was to confuse F and the total number of fundraisers. I assumed that F = 1 means there's only 1 fundraiser total, when actually that means there's 1 fundraiser per Director, which is entirely possible.

So i think what you mean is L = 3, D = 13, and F = 1

Thanks for quick response!
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Pls explain how the colored part is leading to 81?
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siddreal

Pls explain how the colored part is leading to 81?

Hey siddreal ,

Team Leaders, L = 1

If D = 2, that means total number of Group directors = L * D = 1*2 = 2 (Each Leader with D directors means if we have 5 leaders, we will have 5D directors)

Now, if F = 39, the total number of fund raisers = L * D * F = 1* 2 * 39 = 78 (Each Director has F fund raisers. We already know We have LD directors, so fund raisers = LD*F)

Total members in the team = Number of (Leaders + Directors + Fundraisers) = 1 + 2 + 78 = 81.

Does that make sense?
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Kardo
Where does it say that all teams/organizational units are the same size? Must all "D group directors" have the same number of "F fundraisers"? Or why can't one L team leader have 2 D group directors and another L team leader has 3 D group directors ?

Also how can one team have more than one leader ("how many team leaders are on the Dallas team")?

Is this a culture thing?

Or perhaps I am just getting started with my studies so I'm not familiar with the implied constraints for DS questions. To me, it doesn't look like the question is restricting all L team leaders to have the same number of D group directors.

A nonprofit group organizes its local fundraisers in teams, with each of its L team leaders responsible for D group directors, and each of those D group directors responsible for F fundraisers. If the only three positions on each local team are team leaders, group directors, and fundraisers, and there are more group directors than team leaders, how many team leaders are on the Dallas team?
ArupSR

All teams may not be on the same size but this is the structure of each team:
Each of its L team leaders responsible for D group directors, and each of those D group directors responsible for F fundraisers.

L leaders, each leader managing D directors and each Director managing F fundraisers

So team = L + LD + LDF

The value of L, D and F may be different for different teams.

We are concerned about the Dallas team only.

Stmnt 1: L + LD + LDF = 81
L(1 + D + DF) = 81
L = 1, D = 2, F = 39
L = 3, D = 13, F = 1
Not Sufficient

Stmnt 2 tells us that LD = 5 and since we know that L < D,
L = 1 and D = 5
Sufficient.
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if you get this question within 2 min, you deserve to get that 700!

This is the only possible way to distribute when LD=5=1*5
L1
D1 D2 D3 D4 D5


The example below makes D=6, with L=2
L1..........................L2
D1 D2 D3................D4 D5 D6

And, this makes D=4, with L=2
L1...........................L2
D1 D2.....................D3 D4

The only other way this would work of there are 5 team leaders, and 1 director each under them. But in the question it is pretty much given L<D, so even this wouldn't work but just giving you the visual representation below
L1.....L2.....L3.....L4.....L5
D1.....D2....D3.....D4....D5
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chetan2u VeritasKarishma

In statement 2 can we simply say that since number of directors is some integer x multiplied by number of leaders (Because each of the L leader is responsible for D directors) ...... from (2) we know that total number of directors is 5, so
either 1 leader is responsible for 5 directors or
5 leaders are responsible for 1 director each.

Since there are fewer leaders than directors, the number of leader cannot be 5. There Number of leader is 1
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chetan2u VeritasKarishma

In statement 2 can we simply say that since number of directors is some integer x multiplied by number of leaders (Because each of the L leader is responsible for D directors) ...... from (2) we know that total number of directors is 5, so
either 1 leader is responsible for 5 directors or
5 leaders are responsible for 1 director each.

Since there are fewer leaders than directors, the number of leader cannot be 5. There Number of leader is 1

Yes, this is correct.
Check here too: https://gmatclub.com/forum/a-nonprofit- ... l#p2674041
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madhavsrinivas
A nonprofit group organizes its local fundraisers in teams, with each of its L team leaders responsible for D group directors, and each of those D group directors responsible for F fundraisers. If the only three positions on each local team are team leaders, group directors, and fundraisers, and there are more group directors than team leaders, how many team leaders are on the Dallas team?

(1) There are 81 total members on the Dallas team

(2) There are 5 group directors on the Dallas team

The total size of team = L + L*D + L*D*F

L, D and F are leaders, directors and fundraisers respectively.

We are talking about just one team here: Dallas team

St 1: L + L*D + L*D*F = 81
L(1 + D + D*F) = 81
Multiple solutions exist:
Let's take L=1, we need to get 80 in terms of L+D and D/L is an integer.
L = 1, D= 10, F=70
L = 1, D = 2, F = 39
L = 1, D = 20, F = 60
Hence, Not Sufficient

St 2: Given L*D = 5, or (1*5) only possible factor breakup and L < D
Since person can be only integer.
L = 1 and D = 5, and F can be anything.
But we got the no of Leaders: 1
Hence, Sufficient
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Still unable to understand solution , what if 1 group director has more than 1 Team lead ?
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