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nave81
If 3|3 – x| = 7, what is the product of all the possible values of x?

A. 1/9
B. 1/3
C. 2/3
D. 16/9
E. 32/9

3|3 – x| = 7 So, |3 – x| = 7/3 or (3-x) = +7/3 or -7/3
Solving we get x = 2/3 or 16/3
product = \(2/3 * 16/3 = 32/9\)
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If 3|3 – x| = 7, what is the product of all the possible values of x?

x≥3, x<3

x≥3:
3|3 – x| = 7
3 -(3-x) = 7
3 (-3+x) = 7
-9 + 3x = 7
3x = 16
x=16/3 Valid

x<3
3(3-x) = 7
9-3x = 7
-3x=-2
x=2/3

(16/3)*(2/3) = 32/9

(E)
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I don't agree with E. 16/3, when substituted in the original equation doesn't satisfy it. you would get |-9/3| = 7/3 which is not legit. So we should discard 16/3 as a solution of the equation. That leaves us with 2/3 which is option C

Best Regards
Dheeraj Rekula
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Caesar_1987
If 3|3 – x| = 7, what is the product of all the possible values of x?

A. 1/9
B. 1/3
C. 2/3
D. 16/9
E. 32/9

I don't agree with E. 16/3, when substituted in the original equation doesn't satisfy it. you would get|-9/3| = 7/3 which is not legit. So we should discard 16/3 as a solution of the equation. That leaves us with 2/3 which is option C

Best Regards
Dheeraj Rekula

16/3 does satisfy the equation:
3|3 – 16/3| = 7;
3*7/3 = 7.

Hope it's clear.
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3|3-x| = 7 can be rewritten as: |3−x|=7/3
so we have
1. 3-x =7/3
x=2/3

2. 3-x=-7/3
x=16/3

so product will be
32/9
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nave
If 3|3 – x| = 7, what is the product of all the possible values of x?

A. 1/9
B. 1/3
C. 2/3
D. 16/9
E. 32/9


Given : 3|3 – x| = 7

3 – x = 7/3 or 3 – x = -7/3

x = 2/3 or 16/3

Product of all the possible values of x = 2/3 * 16*3 = 32/9

(E)
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the equation leads to two values of x
2/3 , 16/3
their product equals to 32/9 i.e. E
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When |3-x| is -ve

9-3x=7
2=3x
x=2/3


when |3-x| is +ve
-9+3x=7
3x=16
x=16/3

2/3*16/3=32/9
nave
If 3|3 – x| = 7, what is the product of all the possible values of x?

A. 1/9
B. 1/3
C. 2/3
D. 16/9
E. 32/9
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