Official Solution:If the graph of the equation \(|\frac{x}{3}|+|\frac{y}{9}|=10\) encloses a certain region on the coordinate plane, what is the area of that region?A. \(675\)
B. \(1350\)
C. \(2700\)
D. \(5400\)
E. \(10800\)
Let's find the \(x\) and \(y\) intercepts.
When \(y = 0\), we have \(x = 30\) or \(x = -30\).
When \(x = 0\), we have \(y = 90\) or \(y = -90\).
So, we have 4 points: (30, 0), (-30, 0), (0, 90), and (0, -90). When connecting these points, we obtain the following rhombus:
The area of a rhombus can be calculated as \(\frac{d_1 * d_2}{2}\), where \(d_1\) and \(d_2\) are the lengths of the diagonals. Thus, the area of the enclosed figure is \(\frac{60 * 180}{2} = 5,400\).
Answer: D