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Option B

\(7^1\) = 7
\(7^2\) = 49
\(7^3\) = 343
\(7^4\) = 2401
\(7^5\) = 16807
\(7^6\) = 117649
\(7^7\) = 823543
\(7^8\) = 5764801

...

So, 7^100 is something that ends with 01.

The remander is 1.
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=>

The remainder when \(7^{100}\) is divided by \(50\) depends only on the units and tens digits.

The units digits of \(7^n\) cycle through the four values \(7, 9, 3\), and \(1\).
The tens digits of \(7^n\) cycle through the four values \(0, 4, 4\), and \(0\).

We have the following sequence of units and tens digits for \(7^n\):

\(7^1 = 07 ~ 07\)
\(7^2 = 49 ~ 49\)
\(7^3 = 343 ~ 43\)
\(7^4 = 2401 ~ 01\)
\(7^5 = 16807~ 07\)


So, \(7^{100} = (7^4)^{25}\) has the same units and tens digits as \(7^4\), that is, \(01\).
Thus, the remainder when \(7^{100}\) is divided by \(50\) is \(1\).

Therefore, B is the answer.

Answer : B
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[GMAT math practice question]

What is the remainder when \(7^{100}\) is divided by \(50\)?

\(A. 0\)
\(B. 1\)
\(C. 7\)
\(D. 21\)
\(E. 49\)

We see that 7^2 = 49, which is 50 - 1. Although 49/50 = 0 R 49, rather than using the remainder of 49, let’s call the remainder “-1”.

Since 7^100 = (7^2)^50 = 49^50, which is equivalent to (-1)^50 when it’s divided by 50, and since (-1)^50 = 1, so when (-1)^50 is divided by 50, the remainder is 1.

Answer: B
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\(7^{100}/50=49^{50}/50=(50-1)^{50}/50\) - only \((-1)^{50} = 1^{50}=1\) - won't be devisable by 50. The remainder is 1.

Answer B.
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[GMAT math practice question]

What is the remainder when \(7^{100}\) is divided by \(50\)?

\(A. 0\)
\(B. 1\)
\(C. 7\)
\(D. 21\)
\(E. 49\)

We see that 7^2 = 49, which is 50 - 1. Although 49/50 = 0 R 49, rather than using the remainder of 49, let’s call the remainder “-1”.

Since 7^100 = (7^2)^50 = 49^50, which is equivalent to (-1)^50 when it’s divided by 50, and since (-1)^50 = 1, so when (-1)^50 is divided by 50, the remainder is 1.

Answer: B


Hi,

thanks for this solution, but I have a doubt. this question doesn't say that there is exponent for 50. then, How can we take (-1)^50 ?

Waiting for reply.

Regards,
Kishlay
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[GMAT math practice question]

What is the remainder when \(7^{100}\) is divided by \(50\)?

\(A. 0\)
\(B. 1\)
\(C. 7\)
\(D. 21\)
\(E. 49\)

7 ^ 100 = (7 ^ 4) ^ 25 because 7 has a multiplicity of 4

7^4 = 2401 -> Express this as 2400 + 1. Therefore (2400 + 1)^25
All terms except the last will be divisible by 50. The last term is 1. So, remainder = 1

The answer is B
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[GMAT math practice question]

What is the remainder when \(7^{100}\) is divided by \(50\)?

\(A. 0\)
\(B. 1\)
\(C. 7\)
\(D. 21\)
\(E. 49\)


What is the remainder when \(7^{100}\) is divided by \(50\)?

Remainder when 50 divides \(7^{100}\)
=Remainder when 50 divides \((50-1)^{50}\)
= Remainder when 50 divides \((-1)^{50}\)
= Remainder when 50 divides 1 = 1

IMO B
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[GMAT math practice question]

What is the remainder when \(7^{100}\) is divided by \(50\)?

\(A. 0\)
\(B. 1\)
\(C. 7\)
\(D. 21\)
\(E. 49\)

Asked: What is the remainder when \(7^{100}\) is divided by \(50\)?

7^4 = 2401

7^100mod50 = 7^{4*25}mod100 = 1mod100

IMO B
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MathRevolution
[GMAT math practice question]

What is the remainder when \(7^{100}\) is divided by \(50\)?

\(A. 0\)
\(B. 1\)
\(C. 7\)
\(D. 21\)
\(E. 49\)

Remainder (7/50) = 7

Remainder (\(7^2\)/50) = 49 or -1 [i.e. 49 in access or 1 short for it to be divisible by 50]

Taking power 50 both sides


Remainder (\(7^{100}\)/50) = \((-1)^50 = +1\)

Answer: Option B
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