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Bunuel
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If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respect 24 Dec 2018, 22:25
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C
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71% (01:30) correct 29% (01:41) wrong based on 431 sessions

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If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respectively, and 5 tons of cement are available, howmany tons of the mixture can be made? (Assume there is enough gravel and sand available to use all the cement.)

A. 15
B. 20
C. 25
D. 30
E. 75
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C
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If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respect 13 Jan 2019, 04:55
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Quote:
If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respectively, and 5 tons of cement are available, howmany tons of the mixture can be made? (Assume there is enough gravel and sand available to use all the cement.)

A. 15
B. 20
C. 25
D. 30
E. 75
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So... 3x+5x+7x=15x,
3x=5
x=5/3
15*5/3=25
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If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respect 24 Dec 2018, 22:34
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Bunuel
If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respectively, and 5 tons of cement are available, howmany tons of the mixture can be made? (Assume there is enough gravel and sand available to use all the cement.)

A. 15
B. 20
C. 25
D. 30
E. 75
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the mixture is in ratio 3:5:7 , so with 5 tons of cement, ratio becomes 5:x:y (where X and Y are the total quantities of gravel and sand)

3/5 = 5/x; X = 25/3

and

3/7 = 5/y; Y = 35/3

Total mixture = 5 + 25/3 + 35/3
= 5 + 60/3
= 5 + 20
= 25

answer = C
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If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respect 25 Dec 2018, 03:24
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Bunuel
If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respectively, and 5 tons of cement are available, howmany tons of the mixture can be made? (Assume there is enough gravel and sand available to use all the cement.)

A. 15
B. 20
C. 25
D. 30
E. 75
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given 3:5:7
and 5:x:y ratio of cement: gravel:sand

we can say 3/15= 5/5+x+y
x+y=20

similarly for gravel
5/15= x/25 or say x= 25/3
and sand
7/15=y/25 or say y= 35/3
total ; 35/3+25/3+5 = 75/3= 25 IMO C
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If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respect 13 Jan 2019, 18:14
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Bunuel
If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respectively, and 5 tons of cement are available, howmany tons of the mixture can be made? (Assume there is enough gravel and sand available to use all the cement.)

A. 15
B. 20
C. 25
D. 30
E. 75
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5/3*(3+5+7)=25
C
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If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respect 13 Jan 2019, 21:10
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Bunuel
If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respectively, and 5 tons of cement are available, howmany tons of the mixture can be made? (Assume there is enough gravel and sand available to use all the cement.)

A. 15
B. 20
C. 25
D. 30
E. 75
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In ratio terms cement = 3, and total mixture = 3 + 5 + 7 = 15

i.e the total mixture is 5 times the quantity of cement

If cement = 5 tons, total mixture will be 5 *5 = 25 tons

Choice C
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If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respect 13 Jan 2019, 21:26
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Bunuel
If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respectively, and 5 tons of cement are available, howmany tons of the mixture can be made? (Assume there is enough gravel and sand available to use all the cement.)

A. 15
B. 20
C. 25
D. 30
E. 75
Show more


We do not have to get into too much of calculations

If we take common ratio to be X..
C:G:S becomes 3x:5x:7x...
Now 3x=5...
Now, don't complicate by taking value of x and substituting in total
Just add the total value => 3x+5x+7x=15x=5*(3x)=5*(5)=25

C
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If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respect 10 May 2020, 09:14
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Bunuel
If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respectively, and 5 tons of cement are available, howmany tons of the mixture can be made? (Assume there is enough gravel and sand available to use all the cement.)

A. 15
B. 20
C. 25
D. 30
E. 75
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\(\frac{5}{3}*(3+5+7)\)

= \(\frac{5}{3}*15\)

= \(25\), Answer must be (C) 25
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If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respect 27 Oct 2025, 22:10
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