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Math Expert V
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If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respect  [#permalink]

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Question Stats: 57% (01:22) correct 43% (01:39) wrong based on 93 sessions

HideShow timer Statistics If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respectively, and 5 tons of cement are available, howmany tons of the mixture can be made? (Assume there is enough gravel and sand available to use all the cement.)

A. 15
B. 20
C. 25
D. 30
E. 75

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If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respect  [#permalink]

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Bunuel wrote:
If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respectively, and 5 tons of cement are available, howmany tons of the mixture can be made? (Assume there is enough gravel and sand available to use all the cement.)

A. 15
B. 20
C. 25
D. 30
E. 75

the mixture is in ratio 3:5:7 , so with 5 tons of cement, ratio becomes 5:x:y (where X and Y are the total quantities of gravel and sand)

3/5 = 5/x; X = 25/3

and

3/7 = 5/y; Y = 35/3

Total mixture = 5 + 25/3 + 35/3
= 5 + 60/3
= 5 + 20
= 25

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Re: If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respect  [#permalink]

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1
Bunuel wrote:
If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respectively, and 5 tons of cement are available, howmany tons of the mixture can be made? (Assume there is enough gravel and sand available to use all the cement.)

A. 15
B. 20
C. 25
D. 30
E. 75

given 3:5:7
and 5:x:y ratio of cement: gravel:sand

we can say 3/15= 5/5+x+y
x+y=20

similarly for gravel
5/15= x/25 or say x= 25/3
and sand
7/15=y/25 or say y= 35/3
total ; 35/3+25/3+5 = 75/3= 25 IMO C
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Re: If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respect  [#permalink]

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Quote:
If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respectively, and 5 tons of cement are available, howmany tons of the mixture can be made? (Assume there is enough gravel and sand available to use all the cement.)

A. 15
B. 20
C. 25
D. 30
E. 75

So... 3x+5x+7x=15x,
3x=5
x=5/3
15*5/3=25
VP  P
Joined: 07 Dec 2014
Posts: 1198
Re: If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respect  [#permalink]

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Bunuel wrote:
If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respectively, and 5 tons of cement are available, howmany tons of the mixture can be made? (Assume there is enough gravel and sand available to use all the cement.)

A. 15
B. 20
C. 25
D. 30
E. 75

5/3*(3+5+7)=25
C
GMAT Tutor B
Joined: 07 Nov 2016
Posts: 56
GMAT 1: 760 Q51 V42 Re: If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respect  [#permalink]

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1
Bunuel wrote:
If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respectively, and 5 tons of cement are available, howmany tons of the mixture can be made? (Assume there is enough gravel and sand available to use all the cement.)

A. 15
B. 20
C. 25
D. 30
E. 75

In ratio terms cement = 3, and total mixture = 3 + 5 + 7 = 15

i.e the total mixture is 5 times the quantity of cement

If cement = 5 tons, total mixture will be 5 *5 = 25 tons

Choice C
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Math Expert V
Joined: 02 Aug 2009
Posts: 7765
Re: If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respect  [#permalink]

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1
1
Bunuel wrote:
If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respectively, and 5 tons of cement are available, howmany tons of the mixture can be made? (Assume there is enough gravel and sand available to use all the cement.)

A. 15
B. 20
C. 25
D. 30
E. 75

We do not have to get into too much of calculations

If we take common ratio to be X..
C:G:S becomes 3x:5x:7x...
Now 3x=5...
Now, don't complicate by taking value of x and substituting in total
Just add the total value => 3x+5x+7x=15x=5*(3x)=5*(5)=25

C
_________________ Re: If cement, gravel, and sand are to be mixed in the ratio 3:5:7 respect   [#permalink] 13 Jan 2019, 21:26
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