chetan2u
filipembribeiro
For any integer greater than 1, n* denotes the sum of all integers from 1 to n, inclusive. How many even numbers are there from 15* to 20*, inclusive?
(A) 42
(B) 43
(C) 44
(D) 45
(E) 46
Source please.
15* is sum of all integers from 1 to 15.
So from 15* to 20*, we will have 6 integers: 15*, 16*…..20*.
How can you have answers in 40s?
So, the official answer is:
Right answer: (E) 46Explanation:
Essentially \(n*\) is the sum of an arithmetic sequence in the first term is 1 and each term increases by 1. To find the sum of such a sequence, take the average of the first and last terms and multiply this by the number of terms in the sequence. To this end:
15* = \(\frac{(15+1)*15}{2} = 120 \)
20* = \(\frac{(20+1)*20}{2} = 210\)
And to find the number of multiples of a given number within in a range, we first take
the difference between the endpoints and divide them by the number in question:
\(\frac{(210-120)}{2}\) = \(\frac{90}{2}\) =
45Now add 1 because both of the endpoints are even and the question specifies
"inclusive." (E) is correct: it is 46.