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30 Jun 2025, 08:47
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Bookmarks
Total number of tagged animals = 16
There are two sessions, with 8 pairs each
In both sessions, 8 will be dominant and 8 will be subordinate
Out of the 8 subordinates from session 1, 5 stayed subordinates in session 2
=> 3 became dominant
Session 2 has 8 dominant animals, of which 3 switched from subordinate to dominant
Number of dominant animals in session 2 who were already dominant in session 1 = total dominants in session 2 − who became dominant = 8 - 3 = 5
There are two sessions, with 8 pairs each
In both sessions, 8 will be dominant and 8 will be subordinate
Out of the 8 subordinates from session 1, 5 stayed subordinates in session 2
=> 3 became dominant
Session 2 has 8 dominant animals, of which 3 switched from subordinate to dominant
Number of dominant animals in session 2 who were already dominant in session 1 = total dominants in session 2 − who became dominant = 8 - 3 = 5
30 Jun 2025, 08:47
Kudos
Bookmarks
In the wildlife reserve study, 16 animals were paired in two separate tracking sessions, with each session assigning 8 animals as dominant and 8 as subordinate. Of the 8 animals that were subordinate in the first session, 5 remained subordinate in the second session, meaning the other 3 became dominant. Since only 8 animals can be dominant in the second session, and 3 of them came from the previously subordinate group, the remaining 5 dominant animals in the second session must have already been dominant in the first session as well. Therefore, 5 animals were dominant in both sessions.
Bunuel
30 Jun 2025, 08:47
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Bookmarks
**Solution:**
We have 16 animals observed in two sessions. In each session, they're paired into 8 dominant-subordinate pairs.
**Given:**
- 5 animals were subordinate in both sessions.
**Calculations:**
1. **First Session:**
- Subordinate animals (S1): 8
- Dominant animals (D1): 8
2. **Second Session:**
- Subordinate animals (S2): 8
- Dominant animals (D2): 8
3. **Overlap:**
- Animals subordinate in both sessions (S1 ∩ S2) = 5
- Therefore, animals subordinate in first session but dominant in second (S1 ∩ D2) = 8 - 5 = 3
4. **Dominant in Both Sessions:**
- Total dominant in first session (D1) = 8
- Some of these were subordinate in second session (D1 ∩ S2)
- Since total subordinate in second session (S2) = 8, and 5 were from S1, then D1 ∩ S2 = 3
- Thus, dominant in both sessions (D1 ∩ D2) = 8 - 3 = 5
**Final Answer:**
\[
\boxed{5}
\]
This shows 5 animals were dominant in both tracking sessions. The numbers consistently add up to the total of 16 animals when considering all possible role combinations.
We have 16 animals observed in two sessions. In each session, they're paired into 8 dominant-subordinate pairs.
**Given:**
- 5 animals were subordinate in both sessions.
**Calculations:**
1. **First Session:**
- Subordinate animals (S1): 8
- Dominant animals (D1): 8
2. **Second Session:**
- Subordinate animals (S2): 8
- Dominant animals (D2): 8
3. **Overlap:**
- Animals subordinate in both sessions (S1 ∩ S2) = 5
- Therefore, animals subordinate in first session but dominant in second (S1 ∩ D2) = 8 - 5 = 3
4. **Dominant in Both Sessions:**
- Total dominant in first session (D1) = 8
- Some of these were subordinate in second session (D1 ∩ S2)
- Since total subordinate in second session (S2) = 8, and 5 were from S1, then D1 ∩ S2 = 3
- Thus, dominant in both sessions (D1 ∩ D2) = 8 - 3 = 5
**Final Answer:**
\[
\boxed{5}
\]
This shows 5 animals were dominant in both tracking sessions. The numbers consistently add up to the total of 16 animals when considering all possible role combinations.
