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D2 S2
D1 8
S1 5 8
8 8

From the table we can deduce all the values. We know that S1 and S2 = 5 -> S1 and D2 = 3 -> D1 and D2 = 5

IMO D
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Was not too sure how to answer this one, but given 5 were subordinate, it stands the reason that 5 were also dominant.
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8 animals are dominant in each session. If 5 animals are subordinate in both sessions, it means that 3 animals were subordinate in the first session and dominant in the second. Therefore, 5 animals are also dominant in both sessions.
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The three other subs in the first session will be dominant in the second. So, three of the dominant in session one will be sub in session 2. Hence 5 will be left with dominant place in both sessions.

Bunuel
At a wildlife reserve, two tracking sessions were conducted to study 16 tagged animals. In each session, the animals were randomly grouped into 8 pairs, and in each pair, one animal was observed as dominant and the other as subordinate. Of the animals that were subordinate in the first session, 5 were also subordinate in the second session. How many animals were dominant in both sessions?

(A) 2
(B) 3
(C) 4
(D) 5
(E) 6


 


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I think the answer is 5. They are paired so if 5 are subordinate on both session, then accordingly 5 should be dominate on both session.
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In the first session, there are 8 subordinates.

In the second session, out of a total of 8 subordinates, there are 5 subordinates same as the first session. The remaining 3 are unique subordinates.

Combining both sessions, there are 11 unique subordinates. The remaining \(5\) tagged animals were dominant in both sessions

Answer: D
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IMO should be D

Only 5 animals have been subordinate in both the sessions. Thus, we can conclude that 5 animals must have been dominant in both sessions
Bunuel
At a wildlife reserve, two tracking sessions were conducted to study 16 tagged animals. In each session, the animals were randomly grouped into 8 pairs, and in each pair, one animal was observed as dominant and the other as subordinate. Of the animals that were subordinate in the first session, 5 were also subordinate in the second session. How many animals were dominant in both sessions?

(A) 2
(B) 3
(C) 4
(D) 5
(E) 6


 


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for the GMAT Club Olympics Competition

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Given there are 8 subordinates and 8 dominant in first session
If 3 sub ordinate turns dominant in next then correspondingly 3 dominant should turn subordinate.
Hence 5 dominant will be persistnant in two sessions Option D
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Let D1 be the number of animals that were dominant in Session 1.
Let D2 be the number of animals that were dominant in Session 2.
Let D12 be the number of animals that were dominant in both sessions.
Let S12 be the number of animals that were not dominant in any sessions, which equals the number of animals that were subordinate in both sessions.

We have:
D1 + D2 - D12 + S12 = 16
D1 = 8
D2 = 8
S12 = 5
--> D12 = 5
Bunuel
At a wildlife reserve, two tracking sessions were conducted to study 16 tagged animals. In each session, the animals were randomly grouped into 8 pairs, and in each pair, one animal was observed as dominant and the other as subordinate. Of the animals that were subordinate in the first session, 5 were also subordinate in the second session. How many animals were dominant in both sessions?

(A) 2
(B) 3
(C) 4
(D) 5
(E) 6


 


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for the GMAT Club Olympics Competition

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Bunuel
At a wildlife reserve, two tracking sessions were conducted to study 16 tagged animals. In each session, the animals were randomly grouped into 8 pairs, and in each pair, one animal was observed as dominant and the other as subordinate. Of the animals that were subordinate in the first session, 5 were also subordinate in the second session. How many animals were dominant in both sessions?

(A) 2
(B) 3
(C) 4
(D) 5
(E) 6

Label each animal by what it was in the two tracking sessions:

First - Second sessionCount
S-S5
S-D3
D-Dx
D-Sy


  • We are told that 8 animals were subordinate in the first session.
    SS+SD=5+3=8
  • Exactly 8 animals are dominant in each session.
    For the second session this gives
    SD+DD=8 ⟹ 3+x=8 ⟹ x=5
  • Finally, the animals that were dominant in the first session satisfy
    DS+DD=8 ⟹ y+5=8 ⟹ y=3
    which is consistent
Therefore 5 animals were dominant in both sessions.

(D)
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S1= 8 dominant(d1) 8 subordinates(S1)
S2= 8 dominant(d2) 8 subordinates(S2)
given,
of the 8 s1 animals 5 r s2
8-5=3 s1 animals are d2
d2 animals come from
some d1 animal(lets say n) and the 3 s1-d2 animals
total d2=n+3 = 8
n=5
Ans: D
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Animals dominant in the first session D1 = 8
Animals subordinate in the first session S1 = 8
Animals dominant in the second session D2 = 8
Animals subordinate in the second session S2 = 8

As S1 ∩ S2 = 5 an (S1 ∩ S2) + (D1 ∩ S2) = 8 then D1 ∩ S2 = 3
As D1 ∩ S2 = 3 an (D1 ∩ S2) + (D1 ∩ D2) = 8 then D1 ∩ D2 = 5

Answer D
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For 16 animals and 8 pairs, there will be 2 in each pair.

First Tracking session
Considering 8 as dominant and 8 as subordinate.

Second Tracking session
Considering 5 to be the same subordinate out of 8, only 5 would have been the same dominant out of 8.
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It's 5 were dominant in both.
Bunuel
At a wildlife reserve, two tracking sessions were conducted to study 16 tagged animals. In each session, the animals were randomly grouped into 8 pairs, and in each pair, one animal was observed as dominant and the other as subordinate. Of the animals that were subordinate in the first session, 5 were also subordinate in the second session. How many animals were dominant in both sessions?

(A) 2
(B) 3
(C) 4
(D) 5
(E) 6


 


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Thre are 16 animals and in each session exactly 8 are dominant. Of the 8 that were subordinate in session 1, 5 were also subordinate in session 2, so the other 3 from that group must have been dominant in session 2. Session 2 has 8 dominants total, so 8 – 3 = 5 animals must have been dominant in both sessions.

Bunuel
At a wildlife reserve, two tracking sessions were conducted to study 16 tagged animals. In each session, the animals were randomly grouped into 8 pairs, and in each pair, one animal was observed as dominant and the other as subordinate. Of the animals that were subordinate in the first session, 5 were also subordinate in the second session. How many animals were dominant in both sessions?

(A) 2
(B) 3
(C) 4
(D) 5
(E) 6


 


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for the GMAT Club Olympics Competition

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Study 1 -

Dominant - 8 animals - D D D D D D D D
Subordinate - 8 animals - S S S S S S S S

Study 2 -

Of the 8 subordinate animals, 5 were subordinate in the second session, so 3 have now become dominant. The pairs will look like this now:

Dominant - D D D D D D D D
Subordinate - [color=#17b529]S S S S S S S S[/color]

Thus, the number of animals that were dominant in both sessions is 5, option (D).
Bunuel
At a wildlife reserve, two tracking sessions were conducted to study 16 tagged animals. In each session, the animals were randomly grouped into 8 pairs, and in each pair, one animal was observed as dominant and the other as subordinate. Of the animals that were subordinate in the first session, 5 were also subordinate in the second session. How many animals were dominant in both sessions?

(A) 2
(B) 3
(C) 4
(D) 5
(E) 6


 


This question was provided by GMAT Club
for the GMAT Club Olympics Competition

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8 animals were subordinate in first round
5 same animals were subordinate in the second round plus 3 new animals were subordinate.
Hence total number of animals that were dominant= 16-11=5
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