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30 Jun 2025, 15:11
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D
Session 1: 8 animals were subordinate (Sub1) and 8 were Dominate (Dom1)
Session 2: 8 animals were subordinate (Sub2). in Sub2, 5 of these were from the Sub1 grouping meaning that 3 are from Dom1. The reverse means that in the Dom2 group we have 3 from Sub1 and 5 from Dom1.
The 5 from Dom1 are also in Dom2 and have been Dominate for both sessions.
Session 1: 8 animals were subordinate (Sub1) and 8 were Dominate (Dom1)
Session 2: 8 animals were subordinate (Sub2). in Sub2, 5 of these were from the Sub1 grouping meaning that 3 are from Dom1. The reverse means that in the Dom2 group we have 3 from Sub1 and 5 from Dom1.
The 5 from Dom1 are also in Dom2 and have been Dominate for both sessions.
Bunuel
30 Jun 2025, 15:30
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Answer: D.
The question states:
For the 1st session we have: 8 subordinate and 8 dominant animals in total
For the 2nd session, we also must have: 8 subordinate and 8 dominant animals in total
This pattern will repeat for every other session. Note that this condition must be fulfilled, as per the stated rules.
Now, let's get to the crucial condition also stated in the question:
Remember that for the 2nd session we must have 8 subordinate animals as well?
(2) To satisfy this condition, exactly 3 dominant animals must have become submissive for the 2nd session. While 5 must have remained dominant animals.
Therefore, for both sessions, only 5 animals were dominant.
The question states:
Quote:
Translating:
For the 1st session we have: 8 subordinate and 8 dominant animals in total
For the 2nd session, we also must have: 8 subordinate and 8 dominant animals in total
This pattern will repeat for every other session. Note that this condition must be fulfilled, as per the stated rules.
Now, let's get to the crucial condition also stated in the question:
Quote:
(1) That means that 3 of the subordinate animals became dominant for the 2nd session. While 5 remained subordinate.
Remember that for the 2nd session we must have 8 subordinate animals as well?
(2) To satisfy this condition, exactly 3 dominant animals must have become submissive for the 2nd session. While 5 must have remained dominant animals.
Therefore, for both sessions, only 5 animals were dominant.
VizzyFanboy
Joined: 14 Jul 2023
Last visit: 17 Mar 2026
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Location: India
Schools: IIMA '26 (A) EPGP '26 (A)
GMAT Focus 1: 675 Q88 V84 DI79 
30 Jun 2025, 15:43
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8 animals were subordinate in the first session, and among them, 5 were subordinate in the second session = which means, 3 of the animals who were subordinate in the first session were dominant in the second session.
We also know that in both the sessions, the number of dominant and subordinate animals were the same. So, among the 8 dominant animals in the first session, there were 8-3 = 5 animals dominant in the second session.
Answer = 5
We also know that in both the sessions, the number of dominant and subordinate animals were the same. So, among the 8 dominant animals in the first session, there were 8-3 = 5 animals dominant in the second session.
Answer = 5
30 Jun 2025, 15:43
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D2 S2
D1 8
S1 5 8
8 8
From the table we can deduce all the values. We know that S1 and S2 = 5 -> S1 and D2 = 3 -> D1 and D2 = 5
IMO D
D1 8
S1 5 8
8 8
From the table we can deduce all the values. We know that S1 and S2 = 5 -> S1 and D2 = 3 -> D1 and D2 = 5
IMO D
