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01 Jul 2025, 07:17
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To simply visualize in first session there were 8 Dominants and 8 Subordinates,
In second session, out the 8 above only 5 continued to be subordinate, that means 3 became dominant, which implies, 3 dominant became subordinate to compensate the gap. That means only 5 dominant continued to be dominant in the second session. Hence, option (D).
In second session, out the 8 above only 5 continued to be subordinate, that means 3 became dominant, which implies, 3 dominant became subordinate to compensate the gap. That means only 5 dominant continued to be dominant in the second session. Hence, option (D).
Bunuel
01 Jul 2025, 07:48
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Out of 16 tagged animals, we are given that in each session the animals were randomly grouped into 8 pairs,
In each pair one animal was observed as dominant and the other as subordinate.
From these statements we can understand that for each session the total number of subordinate animals must be 8, and the total number of dominant animals must also be 8.
Then, we are given that "Of the animals that were subordinate in the first session, 5 were also subordinate in the second session. " (highlighted)
We can then use the total figures to fill up the table and mark the final answer as option D: 5 animals were Dominant in both sessions
[ltr]
[/ltr]
In each pair one animal was observed as dominant and the other as subordinate.
From these statements we can understand that for each session the total number of subordinate animals must be 8, and the total number of dominant animals must also be 8.
Then, we are given that "Of the animals that were subordinate in the first session, 5 were also subordinate in the second session. " (highlighted)
We can then use the total figures to fill up the table and mark the final answer as option D: 5 animals were Dominant in both sessions
[ltr]
[b]Subordinate in Session 1[/b] | [b]Dominant in Session 1[/b] | ||
[b]Subordinate in Session 2[/b] | [u][b]5[/u][/b] | [b]8-5 = 3 [/b] | [b]Total Subordinate in Session 2 8[/b] |
[b]Dominant in Session 2[/b] | [b]8 - 5 = 3 [/b] | [b]5[/b] | [b]Total Dominant in Session 2 8[/b] |
Total Subordinate in Session 1 8 | [b]Total Dominant in Session 1 8[/b] | [b]Total Tagged Animals = 16[/b] |
01 Jul 2025, 07:51
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This is a set question.
So I would use a table for it:
Session 2 Subordinate Session 2 Dominant Total
Session 1 Subordinate 5 8
Session 1 Dominant b X 8
Total 8 8 16
two tracking sessions were conducted to study 16 tagged animals
The total population is 16.
The population was divided into 2 sessions of 8 pairs.
Of the animals that were subordinate in the first session, 5 were also subordinate in the second session
How many animals were dominant in both sessions?
We can easily answer the question about the animals that were dominant in session 1 but subordinate in session 2 as indicated by b. This is 3.
Thus the animals dominant in both sessions is 8-3=5
The answer is D
So I would use a table for it:
Session 2 Subordinate Session 2 Dominant Total
Session 1 Subordinate 5 8
Session 1 Dominant b X 8
Total 8 8 16
two tracking sessions were conducted to study 16 tagged animals
The total population is 16.
The population was divided into 2 sessions of 8 pairs.
Of the animals that were subordinate in the first session, 5 were also subordinate in the second session
How many animals were dominant in both sessions?
We can easily answer the question about the animals that were dominant in session 1 but subordinate in session 2 as indicated by b. This is 3.
Thus the animals dominant in both sessions is 8-3=5
The answer is D
