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30 Jun 2025, 08:30
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| First Dominant | First Subordinate | Total | |
| Second Dominant | =8-3=5 | 8 | |
| Second Subordinate | =8-5=3 | 5 | 8 |
| Total | 8 | 8 | 16 |
Given the values, calculating Second Subordinate and First Dominant = 8-5=3
Subsequently, calculating dominant in both sessions = 8-3=5
Answer 5
Bunuel
30 Jun 2025, 08:32
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We know that each pair is always made up of 2 animals with different traits thus, of the 8 animals observed as subordinate in the second round of pairings, 5 were also subordinate in the first round. These 5 animals can never be paired with other subordinate animals so it must be the case that there are also 5 dominant animals in round 1 which were also dominant in round 2.
Answer: D) 5
Answer: D) 5
30 Jun 2025, 08:33
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Let's denote the status of an animal as "status in the first session | status in the second session"
For each of the two sessions, all 16 animals were observed each time. Further, for each session, they were split into groups of 2 (so a total of 8 pairs) and then within each pair they were observed to be wither Subordinate (S) or Dominant (D)
The thing to note is that for each pair, there will be one animal that will be S and the other one will be D. Since we have 8 pairs we will have 8 animals that are S and then 8 animals that are D, for each session.
Let's talk about the animals that were observed to be S,
In the first session we start with 8 animals that are S, so we have
Now for the 8 animals that are D we have
So the correct answer is
D. 5
For each of the two sessions, all 16 animals were observed each time. Further, for each session, they were split into groups of 2 (so a total of 8 pairs) and then within each pair they were observed to be wither Subordinate (S) or Dominant (D)
The thing to note is that for each pair, there will be one animal that will be S and the other one will be D. Since we have 8 pairs we will have 8 animals that are S and then 8 animals that are D, for each session.
Let's talk about the animals that were observed to be S,
In the first session we start with 8 animals that are S, so we have
- It's given that, 5 animals were S in both the sessions; 5 (S|S)
- We can thus infer, that in the second session, there were 3 (D|S) > 3 animals that were D in session 1 but S in session 2, since the total of S needs to be 8
Now for the 8 animals that are D we have
- 3 animals that were S before but now are D; 5 (S|D) > since only 5 animals from the first session have retained their status, the other 3 (out of the 8) would have become D
- Now since the total for D need to add up to 8, we can say that the remaining animals that were D in both sessions 1 and 2 is 5 (D|D)
So the correct answer is
D. 5
