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30 Jun 2025, 23:48
Kudos
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Bunuel
Let us consider animals numbered from 1 to 16.
Now in the first session:
Let's assume:
Animals are grouped in pairs: (1,2), (3,4), (5,6), (7,8), (9,10), (11,12), (13,14), (15,16).
Here, Odd-numbered animals are dominant.
Even-numbered animals are subordinate.
During the second session:
5 of the animals that were subordinate in the first session are also subordinate in the second one.
So, let's consider animals numbered 2,4,6,8, and 10 were subordinate in both.
That means animals numbered 12, 14, and 16 are dominant in the second session.
Total dominant in the first session =8.
Out of which 3 (11, 13, and 15) become subordinate in the second session.
Hence total number of animals dominant in both sessions is 5.
The correct answer is option D.
30 Jun 2025, 23:52
Kudos
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There are 16 total Tagged animals out of which 8 pairs were made.
Let us denote Dominant by D and Subordiantes by S.
So in session 1 there were 8D1 and 8S1.
Now for session 2,
Out of these 8S1, 5S1 became 5S2.
Remaining 3S2 came from 3D1.
Thus for subordinates, 5S1+3D1= 8S2
Remaining 3S1 became 3D2
And remaining 5D2 came from 5D1.
Thus for dominants, 5D1+3S1=8D2.
Therefore, animals who were dominant in both sessions were 5.
Let us denote Dominant by D and Subordiantes by S.
So in session 1 there were 8D1 and 8S1.
Now for session 2,
Out of these 8S1, 5S1 became 5S2.
Remaining 3S2 came from 3D1.
Thus for subordinates, 5S1+3D1= 8S2
Remaining 3S1 became 3D2
And remaining 5D2 came from 5D1.
Thus for dominants, 5D1+3S1=8D2.
Therefore, animals who were dominant in both sessions were 5.
30 Jun 2025, 23:54
Kudos
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16 animals in total
In each session: 8 dominant, 8 subordinate
5 animals were subordinate in both sessions
So, 16 − 5 = 11 animals were not subordinate in both
These 11 animals include those who were dominant in both sessions and those who switched roles.
Let x = number of animals dominant in both sessions
So, animals who switched roles = 11 − x
Each switch adds one dominant role in only one session.
So:
Total dominant roles =
.x (dominant in both)
.2 × (8 − x) = 16 − 2x (dominant in only one session)
Total = x + (16 − 2x) = 16 − x
We know total dominant roles = 16 →
16 − x = 16 → x=5
In each session: 8 dominant, 8 subordinate
5 animals were subordinate in both sessions
So, 16 − 5 = 11 animals were not subordinate in both
These 11 animals include those who were dominant in both sessions and those who switched roles.
Let x = number of animals dominant in both sessions
So, animals who switched roles = 11 − x
Each switch adds one dominant role in only one session.
So:
Total dominant roles =
.x (dominant in both)
.2 × (8 − x) = 16 − 2x (dominant in only one session)
Total = x + (16 − 2x) = 16 − x
We know total dominant roles = 16 →
16 − x = 16 → x=5
