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30 Jun 2025, 09:46
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(D) 5
Of the 8 dominants of the first session, 8-5=3 became subordinate in the second one, hence, leaving the other 5 again as dominant.
Of the 8 dominants of the first session, 8-5=3 became subordinate in the second one, hence, leaving the other 5 again as dominant.
Bunuel
At a wildlife reserve, two tracking sessions were conducted to study 16 tagged animals. In each session, the animals were randomly grouped into 8 pairs, and in each pair, one animal was observed as dominant and the other as subordinate. Of the animals that were subordinate in the first session, 5 were also subordinate in the second session. How many animals were dominant in both sessions?
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
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30 Jun 2025, 09:48
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Bookmarks
A
Tried working backwards but got confused with all the numbers. Only a few animals could stay dominat right? But didn't account for all the switching properly.
B
Mixed up the numbers here. Saw that 3 animals switched from subordinate to dominant, so thought maybe 3 also stayed dominant. That's not how it works out tho.
C
Was close but made an error somwhere. Didn't keep track of all the animals correctly when they were switching between roles.
D (Correct)
Worked it out step by step. If 5 stayed subordinate and 3 switched from sub to dominant, then 3 others had to switch the other way to keep numbers balanced. Leaves 5 animals that stayed dominant both times.
E
I Thnk there was overcounting somewhere. Maybe forgot that the total has to add up to 16, or mixed up which direction animals were switching.
Tried working backwards but got confused with all the numbers. Only a few animals could stay dominat right? But didn't account for all the switching properly.
B
Mixed up the numbers here. Saw that 3 animals switched from subordinate to dominant, so thought maybe 3 also stayed dominant. That's not how it works out tho.
C
Was close but made an error somwhere. Didn't keep track of all the animals correctly when they were switching between roles.
D (Correct)
Worked it out step by step. If 5 stayed subordinate and 3 switched from sub to dominant, then 3 others had to switch the other way to keep numbers balanced. Leaves 5 animals that stayed dominant both times.
E
I Thnk there was overcounting somewhere. Maybe forgot that the total has to add up to 16, or mixed up which direction animals were switching.
30 Jun 2025, 09:48
Kudos
Bookmarks
No of sessions : 2
First session, Dominant animals (D1) = 8, Subordinate animals (S1) = 8
Second session, Dominant animals (D2) = 8, Subordinate animals (S2) = 8
Now, 5 out of S1 are part of S2, meaning 3 are part of D2.
By similar logic, if S2 must have 3 from D1.
=> D2 must have 5 animals from D1.
Answer is 5
First session, Dominant animals (D1) = 8, Subordinate animals (S1) = 8
Second session, Dominant animals (D2) = 8, Subordinate animals (S2) = 8
Now, 5 out of S1 are part of S2, meaning 3 are part of D2.
By similar logic, if S2 must have 3 from D1.
=> D2 must have 5 animals from D1.
Answer is 5
Bunuel
At a wildlife reserve, two tracking sessions were conducted to study 16 tagged animals. In each session, the animals were randomly grouped into 8 pairs, and in each pair, one animal was observed as dominant and the other as subordinate. Of the animals that were subordinate in the first session, 5 were also subordinate in the second session. How many animals were dominant in both sessions?
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
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