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30 Jun 2025, 10:47
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Ans: D
5 were dominant in both sessions.
At a wildlife reserve, two tracking sessions were conducted to study 16 tagged animals. In each session, the animals were randomly grouped into 8 pairs, and in each pair, one animal was observed as dominant and the other as subordinate. Of the animals that were subordinate in the first session, 5 were also subordinate in the second session. How many animals were dominant in both sessions?
Session 1:
8 pairs --> 8 D + 8 S
Session 2:
8 pairs again --> 5 S from the 8S in the first session, so the remaining 3 S from session 1 became 3 D in session 2 and replaced the 3 D from Session 1.
This tells us that only 5 D from session 1 remained in the D position in session 2.
so D in both sessions = 5 animals.
5 were dominant in both sessions.
At a wildlife reserve, two tracking sessions were conducted to study 16 tagged animals. In each session, the animals were randomly grouped into 8 pairs, and in each pair, one animal was observed as dominant and the other as subordinate. Of the animals that were subordinate in the first session, 5 were also subordinate in the second session. How many animals were dominant in both sessions?
Session 1:
8 pairs --> 8 D + 8 S
Session 2:
8 pairs again --> 5 S from the 8S in the first session, so the remaining 3 S from session 1 became 3 D in session 2 and replaced the 3 D from Session 1.
This tells us that only 5 D from session 1 remained in the D position in session 2.
so D in both sessions = 5 animals.
30 Jun 2025, 10:53
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Let the two Sessions be S1 and S2.
Given: Both the sessions had 8 pairs of animals. Each pair has a dominant animal and a subordinate animal. 5 subordinate animals were same in both S1 and S2.
To Find: Number of animals that are dominant in both the sessions.
From the condition "5 subordinate animals were same in both S1 and S2", we can conclude that the remaining 3 subordinate animals in S1 were dominant in S2 and the remaining 3 subordinate animals in S2 were dominant in S1.
i.e. 5 subordinate animals of S2 are formed by 5 subordinate animals of S1 and 3 dominant animals of S2 are formed by remaining 3 subordinate animals of S1. So, the remaining 8 animals of S2 (3 subordinate and 5 dominant) are formed by 8 dominant animals of S1.
So, there are 5 dominant animals that are common in both S1 and S2.
Given: Both the sessions had 8 pairs of animals. Each pair has a dominant animal and a subordinate animal. 5 subordinate animals were same in both S1 and S2.
To Find: Number of animals that are dominant in both the sessions.
From the condition "5 subordinate animals were same in both S1 and S2", we can conclude that the remaining 3 subordinate animals in S1 were dominant in S2 and the remaining 3 subordinate animals in S2 were dominant in S1.
i.e. 5 subordinate animals of S2 are formed by 5 subordinate animals of S1 and 3 dominant animals of S2 are formed by remaining 3 subordinate animals of S1. So, the remaining 8 animals of S2 (3 subordinate and 5 dominant) are formed by 8 dominant animals of S1.
So, there are 5 dominant animals that are common in both S1 and S2.
30 Jun 2025, 11:05
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- In each session, the animals are grouped into 8 random pairs, and in each pair, one is dominant, the other subordinate.
- So in each session:
8 animals are dominant,
8 animals are subordinate.
Of the animals that were subordinate in the first session, 5 were also subordinate in the second session.
Let’s try organizing this.
- Group A = Subordinate in Session 1 = 8 animals
- Out of these 8, 5 stayed subordinate in Session 2.
So the remaining 3 became dominant in Session 2.
Now let's look at the other group:
- Group B = Dominant in Session 1 = the other 8 animals
- Since 5 animals from Group A were still subordinate in Session 2, we need 3 more animals to complete the 8 subordinates in Session 2.
Those 3 must have come from Group B (because there are only 16 animals).
So from Group B:
- 3 animals became subordinate in Session 2
- That means the remaining 5 animals from Group B stayed dominant in both sessions.
That’s what we needed: 5 animals were dominant in both sessions.
Bunuel
