Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 1612:00 PM EDT
-11:59 PM EDT
You’re first to know: Save $200 on GMAT prep starting tomorrow, 4/13. Get 6 official practice tests and study with real questions. Be ready to save!
Apr 2212:30 AM EDT
-01:30 AM EDT
At one point, she believed GMAT wasn’t for her. After scoring 595, self-doubt crept in and she questioned her potential. But instead of quitting, she made the right strategic changes. The result? A remarkable comeback to 695. Check out how Saakshi did it.
Apr 2301:30 AM EDT
-02:30 AM EDT
Struggling with GMAT Verbal as a non-native speaker? Harsh improved his score from 595 to 695 in just 45 days—and scored a 99 %ile in Verbal (V88)! Learn how smart strategy, clarity, and guided prep helped him gain 100 points.
Apr 2308:00 PM PDT
-09:00 PM PDT
Video explanations + diagnosis of 10 weakest areas + 150+ short videos + study plan!
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
30 Jun 2025, 15:10
Kudos
Bookmarks
Let N be the total number of integers from x to y, inclusive.
The number of integers from x to y, inclusive, is given by N=y−x+1.
(1) y - x = 9
From this, we can find N:
N=y−x+1=9+1=10.
we can calculate the probability
Since we can find a unique probability, statement (1) is sufficient.
(2) y = -20
This statement only gives the value of y. We still don't know x, and therefore we don't know N.
Since we get different probabilities depending on x, statement (2) is not sufficient.
The number of integers from x to y, inclusive, is given by N=y−x+1.
(1) y - x = 9
From this, we can find N:
N=y−x+1=9+1=10.
we can calculate the probability
Since we can find a unique probability, statement (1) is sufficient.
(2) y = -20
This statement only gives the value of y. We still don't know x, and therefore we don't know N.
Since we get different probabilities depending on x, statement (2) is not sufficient.
30 Jun 2025, 15:19
Kudos
Bookmarks
Statement 1 alone is sufficient , but statement 2 alone is not.
1- Alone we are able to plug in many number optiosn all resulting in y>x. y=100 x=91 , y=-100 x=-109 y=10, x=1, y=11, x=2, y=-12 x=-21
2- We are unable to determine what x is and cant come to a conclusion for y > or < x.
1- Alone we are able to plug in many number optiosn all resulting in y>x. y=100 x=91 , y=-100 x=-109 y=10, x=1, y=11, x=2, y=-12 x=-21
2- We are unable to determine what x is and cant come to a conclusion for y > or < x.
Bunuel
30 Jun 2025, 15:54
Kudos
Bookmarks
Ann and Bob each randomly select an integer from the integers x to y, inclusive. What is the probability that the integer Ann selects is greater than the one Bob selects?
numbers n=y-x+1
n^2 is the total number os odds.
There are exactly n odds that Ann and Bobb choose the same number. In the rest of odds, there is the same probability that Ann chooses a greater number that the one Bob chooses as the opposite happening, so:
P = (n^2-n)/2*n^2 = (n-1)/2n
1) y-x=9
n=10
P=9/20
SUFFICIENT
2)y=-20
No way to find n
INSUFFICIENT
IMO A
numbers n=y-x+1
n^2 is the total number os odds.
There are exactly n odds that Ann and Bobb choose the same number. In the rest of odds, there is the same probability that Ann chooses a greater number that the one Bob chooses as the opposite happening, so:
P = (n^2-n)/2*n^2 = (n-1)/2n
1) y-x=9
n=10
P=9/20
SUFFICIENT
2)y=-20
No way to find n
INSUFFICIENT
IMO A
