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GMAT Club Olympics 2025 (Day 2): A water bottling machine is designed 01 Jul 2025, 08:00
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Small Bottles: 18 Large Bottles: 5
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79% (01:55) correct 21% (02:13) wrong based on 684 sessions

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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
Small Bottles Large Bottles
3
5
18
50
90
180
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Small Bottles: 18 Large Bottles: 5
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GMAT Club Olympics 2025 (Day 2): A water bottling machine is designed 01 Jul 2025, 08:30
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Bunuel
A bottling machine is designed to fill two types of bottles—small and large—with water at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
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­

GMAT Club Official Explanation:




Step 1: Calculate how many bottles are filled in one minute

Small bottles:
The rate is 3 per second.
In one minute, that is 3 * 60 = 180 small bottles.

Large bottles:
The rate is 5 every 6 seconds.
In one minute, 60/6 = 10 such intervals.
So, 5 * 10 = 50 large bottles.

Step 2: Distribute bottles into 10 crates

Each crate contains:
180 / 10 = 18 small bottles
50 / 10 = 5 large bottles

Final Answer:
Small Bottles = 18
Large Bottles = 5
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GMAT Club Olympics 2025 (Day 2): A water bottling machine is designed 01 Jul 2025, 08:07
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Rates:

Small : 3 bottles / 1 second
Large : 5 bottles / 6 seconds

1 minute = 60 seconds.

Total production:
Small = 60 seconds * 3 bottles / 1 second = 60 * 3 bottles = 180 bottles
Large = 60 seconds * 5 bottles / 6 seconds = 10 * 5 bottles = 50 bottles

Equally dividing the bottles in 10 packs let us with, for each pack: 18 Smalls and 5 Large bottles.
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GMAT Club Olympics 2025 (Day 2): A water bottling machine is designed 01 Jul 2025, 08:24
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Step 1: Calculate total bottles filled in one minute (60 seconds).

* Total Small Bottles = 3 bottles/second * 60 seconds = 180.
* Total Large Bottles = (5 bottles / 6 seconds) * 60 seconds = 5 * 10 = 50.

Step 2: Divide the totals by the number of crates (10).

* Small bottles per crate = 180 / 10 = 18.
* Large bottles per crate = 50 / 10 = 5.

Thus, Small Bottles = 18 and Large Bottles = 5.
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GMAT Club Olympics 2025 (Day 2): A water bottling machine is designed 01 Jul 2025, 08:28
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The machine runs for 1 minute = 60 seconds

It fills:

Small bottles at 3 per second
So in 60 seconds: 3×60=180 small bottles total.

Large bottles at 5 every 6 seconds
So in 60 seconds:
(60/6)×5 = 10×5 = 50 large bottles total.

The total bottles are packed into 10 crates, and each crate has the same number of small and large bottles.

So divide:
Small bottles per crate: 180/10 = 18
Large bottles per crate: 50/10 = 5

Final Answer:
Small Bottles per crate: 18
Large Bottles per crate: 5
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GMAT Club Olympics 2025 (Day 2): A water bottling machine is designed 01 Jul 2025, 08:33
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Correct Answer
  • Small Bottles: 18
  • Large Bottles: 5
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GMAT Club Olympics 2025 (Day 2): A water bottling machine is designed 01 Jul 2025, 08:34
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work done in 1 sec on small bottles = 3*1 = 3 units.
work done in 60 sec on small bottles = 3*60 = 180 units.

work done in 1 sec on large bottles = (5/6)*1 = 5/6
work done in 60 sec on large bottles = (5/6)*60 = 50 units.

so, no of small bottles in 1 crate = 180/10 = 18
no of large bottles in 1 crate = 50/10 = 5.

hence, ans is 18,5
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GMAT Club Olympics 2025 (Day 2): A water bottling machine is designed 01 Jul 2025, 08:39
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Small bottles, 3 per sec
In one minute = 3*60=180
Divided in 10 crates so each crate has 180/10 =18 small bottles

Large bottles, 5 every 6 sec
In one minute = 5*10=50
Divided into 10 crates so each crate has 50/10=5 large bottles
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GMAT Club Olympics 2025 (Day 2): A water bottling machine is designed 01 Jul 2025, 08:44
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Smalllarge
Fill rate3/s5/6s
Bottles filled in a min=3*60=180=5/6*60=50
Bottles in each crate=180/10=18=50/10=5

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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
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GMAT Club Olympics 2025 (Day 2): A water bottling machine is designed 01 Jul 2025, 08:45
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Small bottle - 3 per second --> 60*3 = 180 in 1 minute.
Large bottle - 5 every 6 second --> in 1 second 5/6 bottle --> in 1 minute ((5/6) * 60) = 50 bottles.

10 crates --> 180/10 = 18 small bottles, 50/5 = 5 large bottles.
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GMAT Club Olympics 2025 (Day 2): A water bottling machine is designed 01 Jul 2025, 08:49
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Lets consider conditions as following:
A) Calculate the number of small bottles filled in one minute:
Rate of small bottles: 3 bottles per second
Time: 1 minute = 60 seconds
Number of small bottles filled = 3 bottles/second * 60 seconds = 180 small bottles

B) Calculate the number of large bottles filled in one minute:
Rate of large bottles: 5 bottles every 6 seconds
Number of 6-second intervals in one minute = 60 seconds / 6 seconds/interval = 10 intervals
Number of large bottles filled = 5 bottles/interval * 10 intervals = 50 large bottles

C) Determine the number of small and large bottles per crate:
Total small bottles filled = 180
Total large bottles filled = 50
Number of shipping crates = 10

Number of small bottles per crate = Total small bottles / Number of crates = 180 / 10 = 18 small bottles per crate
Number of large bottles per crate = Total large bottles / Number of crates = 50 / 10 = 5 large bottles per crate

Therefore, Small Bottles (per crate): 18 and Large Bottles (per crate): 5
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Types: Small and Large

Small- 3 per second (18 every 6 seconds)
Large - 5 every 6 seconds

10 shipping crates. same number of small and large. after 1 minute.

Small - 180 bottles for 1 minute
Large - 50 for 1 minute

10 crates. 50/10=5. 5 bottles each.

5 because they are the same.
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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Small bottles filled in 1 minute = 3*60 = 180 small bottles
Large bottles filled in 1 minute = 5*60/6 = 50 large bottles

Small bottles in each crate = 180/10 = 18
Large bottles in each crate = 50/10 = 5

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.

Small BottlesLarge Bottles
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GMAT Club Olympics 2025 (Day 2): A water bottling machine is designed 01 Jul 2025, 08:55
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First, let's calculate how many small and large bottles are filled in one minute:
Small bottles: 3 bottles per second × 60 seconds = 180 small bottles
Large bottles: 5 bottles every 6 seconds
In 60 seconds, we have 60 ÷ 6 = 10 intervals of 6 seconds
So large bottles filled = 5 × 10 = 50 large bottles
Now, these bottles are packed into exactly 10 shipping crates, with each crate containing the same number of bottles:
Small bottles per crate = 180 ÷ 10 = 18 small bottles per crate
Large bottles per crate = 50 = 10 = 5 large bottles per crate
Therefore, each shipping crate contains 18 small bottles and 5 large bottles.
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GMAT Club Olympics 2025 (Day 2): A water bottling machine is designed 01 Jul 2025, 08:57
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small bottle speed -> 3 bottles/sec
In 1 minute, 60*3=180 small bottles are produced.
large bottle speed-> 5 bottles in 6 sec
In 1 minute, 50 large bottles are produced.

They should be fit in 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.
If equally divide b/w 10 crates,
small bottles =18*10 crates
large bottles=5*10 crates

Ans : 18 5
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GMAT Club Olympics 2025 (Day 2): A water bottling machine is designed 01 Jul 2025, 09:04
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Information given:
- Machine fills small bottles at 3 per second
- Machine fills large bottles at 5 every 6 seconds
- It runs for 1 minute (60 seconds)
- Total small and large bottles are packed into exactly 10 crates, each crate has the same number of small and large bottles

Question:
- How many small and large bottles per crate?

Solution:
- First, calculate the total bottles produced
- Small bottles: 3 per sec * 60 sec = 180 bottles
- Large bottles: 5 every 6 sec: rate = 5/6 = 0.8333 per sec
- 0.8333 * 60 = 50 bottles
- In total, 180 small bottles and 50 large bottles are produced

- Since there are 10 crates, there will be 180/10 = 18 small bottles per crate and 50/10 = 5 large bottles per crate

Answer: small bottles 18 per crate, large bottles 5 per crate
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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
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We are given:
  • Small bottles:
    3 per second so 3 × 60 = 180 per minute
  • Large bottles:
    5 every 6 seconds so (60 ÷ 6) × 5 = 50 per minute

They fill 10 crates, each crate must contain the same number of each bottle:
  • Small per crate: 180 ÷ 10
    = 18
  • Large per crate: 50 ÷ 10
    = 5
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Bunuel
 


This question was provided by GMAT Club
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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
Show more
In 60 seconds, machine produces 3x60 = 180 small bottles and (5/6) x 60 = 50 large bottles.

Each container has equal large and small bottles.

Each container among 10 has 180/10 = 18 small bottles and 50/5 = 5 large bottles.
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GMAT Club Olympics 2025 (Day 2): A water bottling machine is designed 01 Jul 2025, 09:10
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Small bottles filled at constant rate of 3 per second, therefore in one minute, machine fills 180 small bottles.
Large bottles filled at constant rate of 5 every 6 seconds, therefore in one minute, machine filled 50 large bottles.
Now, we have been given that these small and large bottles are packed into exactly 10 crate with each crate having same number of small and large bottles, thus we have, 18 small bottles (180/10) and 5 large bottles (50/10) in each crate.

hope this helps :)

regards,
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This question was provided by GMAT Club
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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
Show more

It can be seen that the number of small bottles in one minute is 3*60=180 but there are 10 crates implies 180/10=18 bottles for every crate, similarly for large bottles there are 5 for every 6 seconds in a minute it is 5*10=50 bottles ,but there are 10 crates implies 50/10=5 bottles for every crate.
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