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06 Jul 2026, 23:48
Kudos
Bookmarks
Given :
6 spaces (1 to 6). Odd Positions (1,3,5). Even Positions (2,4,6). A & B must occupy adjacent spaces.
The question: Is F in Space 1?
(1) B and C are in even-numbered spaces
Since B is even and A is adjacent to B, A must be odd. Now, let's take 2 cases
a. F in Space 1 -: F B A C D E
b. F not in Space 1 -: A B F C D E
Thus, we can't be certain where F is.
Insufficient
(2) D and E are in odd-numbered spaces
D and E occupy 2 of the 3 odd-numbered spaces. Since A and B are adjacent, one of them must occupy an odd-numbered space. Since all 3 odd spaces are occupied, F certainly can't be in Space 1.
Sufficient
Ans = B
6 spaces (1 to 6). Odd Positions (1,3,5). Even Positions (2,4,6). A & B must occupy adjacent spaces.
The question: Is F in Space 1?
(1) B and C are in even-numbered spaces
Since B is even and A is adjacent to B, A must be odd. Now, let's take 2 cases
a. F in Space 1 -: F B A C D E
b. F not in Space 1 -: A B F C D E
Thus, we can't be certain where F is.
Insufficient
(2) D and E are in odd-numbered spaces
D and E occupy 2 of the 3 odd-numbered spaces. Since A and B are adjacent, one of them must occupy an odd-numbered space. Since all 3 odd spaces are occupied, F certainly can't be in Space 1.
Sufficient
Ans = B
06 Jul 2026, 23:52
Kudos
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Ans: B
firstly, this is a case question so it will be neat to solve it in tabular format. separating the question and each statement therein.
secondly, you don't have to try to check all possible cases, if you can just find 2 cases that make the statement insufficient (means the statement give both answers yes, no) then you'll be able to rule out an option.
from statement 1 you can easily find this scenario. eg: place B, C at 2, 4. and according to the question place A as per the question requirements.
from statement 2, you can make 3 possible arrangement for D, E (we're counting D, E and E, D as 1 here). then if you place A and B adjacently in all 3 scenarios, you realise each time place 1 is occupied. so no room for F there. hence we can give a definite no as the answer.
firstly, this is a case question so it will be neat to solve it in tabular format. separating the question and each statement therein.
secondly, you don't have to try to check all possible cases, if you can just find 2 cases that make the statement insufficient (means the statement give both answers yes, no) then you'll be able to rule out an option.
from statement 1 you can easily find this scenario. eg: place B, C at 2, 4. and according to the question place A as per the question requirements.
from statement 2, you can make 3 possible arrangement for D, E (we're counting D, E and E, D as 1 here). then if you place A and B adjacently in all 3 scenarios, you realise each time place 1 is occupied. so no room for F there. hence we can give a definite no as the answer.
06 Jul 2026, 23:53
Kudos
Bookmarks
Answer: B
Explanation:
As cars A and B are parked next to each other, they will park in one even-numbered space and one odd-numbered space. With (2), Cars C and E are both parked in odd-numbered spaces, there are no more odd-numbered spaces. Hence, this will answer that car F is not parked in space 1.
Explanation:
As cars A and B are parked next to each other, they will park in one even-numbered space and one odd-numbered space. With (2), Cars C and E are both parked in odd-numbered spaces, there are no more odd-numbered spaces. Hence, this will answer that car F is not parked in space 1.
Bunuel
