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Two dice are tossed simultaneously

As we are rolling 2 dice => Number of cases = \(6^2\) = 36

What's the probability that the total score is not more than 3?

Lets start listing down the cases where total is not more than 3
(1,1), (1,2), (2,1)

=> 3 cases

=> P(Total not more than 3) = \(\frac{3}{36}\) = \(\frac{1}{12}\)

So, Answer will be B
Hope it helps!

Playlist on Solved Problems on Probability here

Watch the following video to MASTER Dice Rolling Probability Problems

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