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Bunuel
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Machine A
produce x/10 boxes in 1 minute

Machine B
produce 2x/5 boxes in 1 minute

Combined they produce X/10 + 2X/5 = 5x/10 = x/2 boxes in 1 minute

and hence produce 3X boxes in 6 minutes.

So D. 6 minutes must be the correct Answer
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the answer is D

lets say tha x=150 then 2x=300 and 3x=450
so A= 15*10=150
B= 60*5=300.
(A+B)*S=450 so (15+60)*s=450 so s=6 minutes.
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Bunuel
Working alone at its constant rate, machine A produces x boxes in 10 minutes and working alone at its constant rate, machine B produces 2x boxes in 5 minutes. How many minutes does it take machines A and B, working simultaneously at their respective constant rates, to produce 3x boxes?

A. 3 minutes
B. 4 minutes
C. 5 minutes
D. 6 minutes
E. 12 minutes

Kudos for a correct solution.

Machine A produces x/10 boxes in 1 minute
Machine B produces 2x/5 boxes in 1 minute
Together they produce X/10 + 2X/5 = 5x/10 = x/2 boxes in 1 minute

and therefore produce 3X boxes in 6 minutes.
Answer D
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Rate of A = X/10 boxes per minute;
Rate of B = 2X/5 boxes per minute;
Combined rate is X/10 +2X/5 = X/2 = work/time; therefore time = 3*2= 6
Hence answer is D
Thanks,
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Hi All,

This question can be solved in a variety of ways, depending on how you want to organize your information. It's actually perfect for TESTing VALUES:

We're given information on the rates of two machines:
1) Machine A can produce X boxes in 10 minutes
2) Machine B can produce 2X boxes in 5 minutes

We're asked how long it takes the two machines, working together, to produce 3X boxes.

IF...
X = 10
Machine A produces 10 boxes in 10 minutes (1 box per minute)
Machine B produces 20 boxes in 5 minutes (4 boxes per minute)
Working together, they would produce 5 boxes per minute

3X boxes = 3(10) = 30 boxes

Given the above combined rate, it would take 30/5 = 6 minutes to produce 30 boxes.

Final Answer:
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Bunuel
Working alone at its constant rate, machine A produces x boxes in 10 minutes and working alone at its constant rate, machine B produces 2x boxes in 5 minutes. How many minutes does it take machines A and B, working simultaneously at their respective constant rates, to produce 3x boxes?

A. 3 minutes
B. 4 minutes
C. 5 minutes
D. 6 minutes
E. 12 minutes
Ans: D

Solution: N*(x/10 + 2x/5) = 3x ; where x/10 and 2x/5 are number of boxes produced by A and B respectively in one minute.
N = 6

Ans : D
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working alone at its constant rate, machine A produces x boxes in 10 minutes and working alone at its constant rate, machine B produces 2x boxes in 5 minutes. How many minutes does it take machines A and B, working simultaneously at their respective constant rates, to produce 3x boxes?

A. 3 minutes
B. 4 minutes
C. 5 minutes
D. 6 minutes
E. 12 minutes


The problem is about Time and Work . It needs to follow simple understanding of the concept

Rate = Work / Time

Given Rate of Machine A = X / 10 min

Machine B Produces 2x boxes in 5 min hence , Machine B produces 4x boxes in 10 min .

Rate of Machine B = 4x / 10

we need to find the combined time that machines A and B, working simultaneously take at their respective constant rates


let's first find the combined Rate of Machine A and B

Rate of Machine A = X / 10 min + Rate of Machine B = 4x / 10 = 5X/10

Now combine Time = combine work needs to be done / Combine Rate = 3x/5x * 10 = 6 Min



Ans: D
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Bunuel
Working alone at its constant rate, machine A produces x boxes in 10 minutes and working alone at its constant rate, machine B produces 2x boxes in 5 minutes. How many minutes does it take machines A and B, working simultaneously at their respective constant rates, to produce 3x boxes?

A. 3 minutes
B. 4 minutes
C. 5 minutes
D. 6 minutes
E. 12 minutes

Kudos for a correct solution.


A -> x boxes in 10 min so 3x boxes in 30 mins
So in 1 min -> 1/30th work will be completed

B -> 2x boxes in 5 mins so 3x boxes in 15/2 mins
So in 1 min -> 2/15th work will be completed

Work done by A+B in 1 min -> 1/30 + 2/15 = 1/6

Therefore, total work done by A+B in -> 1/(1/6) = 6 mins!

Kudos please ;)
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[quote="Bunuel"]Working alone at its constant rate, machine A produces x boxes in 10 minutes and working alone at its constant rate, machine B produces 2x boxes in 5 minutes. How many minutes does it take machines A and B, working simultaneously at their respective constant rates, to produce 3x boxes?

A. 3 minutes
B. 4 minutes
C. 5 minutes
D. 6 minutes
E. 12 minutes

[i]Kudos for a correct solution.[/

Keep it simple:

A -- x boxes in 10 mins ------ 3x boxes in 30 mins
B -- 2x boxes in 5 mins ----- x boxes in 2.5 mins ---- 3x boxes in 7.5 mins
Thus A+B ---- 3x boxes in (30*7.5)/(30+7.5) = 6 mins

Kudos please!!
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Working alone at its constant rate, machine A produces x boxes in 10 minutes and working alone at its constant rate, machine B produces 2x boxes in 5 minutes. How many minutes does it take machines A and B, working simultaneously at their respective constant rates, to produce 3x boxes?

A. 3 minutes
B. 4 minutes
C. 5 minutes
D. 6 minutes
E. 12 minutes

Different Approach-
In 10mins, A produces x boxes and B produces 4x boxes. Total A+B produces x+4x=5x boxes in 10 mins.

So time T taken to produce 3x boxes -> 10:T :: 5x:3x -> 10*3x = T*5x -> T = 6.

Thanks,

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Working alone at its constant rate, machine A produces x boxes in 10 minutes and working alone at its constant rate, machine B produces 2x boxes in 5 minutes. How many minutes does it take machines A and B, working simultaneously at their respective constant rates, to produce 3x boxes?

A. 3 minutes
B. 4 minutes
C. 5 minutes
D. 6 minutes
E. 12 minutes
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Time taken by machine A to produce x boxes = 10 minutes

Time taken by machine B to produce 2x boxes = 5 minutes

Number of boxes produced in 10 minutes by Machine B = 2*2x = 4x

Number of boxes produced in 10 minutes by machines A and B working simultaneously = x + 4x = 5x

Time taken by Machine A and B working simultaneously to produce x boxes = 10/5 = 2 minutes

Time taken by Machine A and B working simultaneously to produce 3x boxes = 2*3 = 6minutes

The correct answer is D
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