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Bunuel
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Bunuel
Sn = n^2 + 5n + 94 and K = S6 – S5 + S4 – S3 + S2 – S1. What is the value of K?

(A) 67
(B) 50
(C) 45
(D) 41
(E) 36


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two ways , i would solve it..
1) Sn = n^2 + 5n + 94
K=S6 – S5 + S4 – S3 + S2 – S1
=(6^2-5^2+4^2-3^2+2^2-1^2)+5(6-5+4-3+2-1)+0
=(36-25+16-9+4-1)+5(3)+0=36
2) looking at the choices avail..
we know there are three even terms in +ive and three odd terms in -ive...
so 94 gets cancelled out..
if you add square of three even numbers and subtract square of odd no, it will always be odd..
so n^2 will be odd and 5*n will also be odd, so answer should be even....only B and E are left..


Also if we just concentrate on last digits of n^2 and n.. we can easily see it has to be 6.. only 36 is left
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Bunuel
Sn = n^2 + 5n + 94 and K = S6 – S5 + S4 – S3 + S2 – S1. What is the value of K?

(A) 67
(B) 50
(C) 45
(D) 41
(E) 36


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Can I just ignore the "+94" in the first equation because we always have a subtraction between Sn - S(n-1)? Like this:

S6-S5 = 6^2 + 5*6 - 5^2 +5*5 =16
S4-S3 = 4^2 + 5*4 - 3^2 + 5*3 = 12
S2-S1 = 2^2 + 2*5 - 1 + 5 = 8
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Bunuel
Sn = n^2 + 5n + 94 and K = S6 – S5 + S4 – S3 + S2 – S1. What is the value of K?

(A) 67
(B) 50
(C) 45
(D) 41
(E) 36


Kudos for a correct solution.

Can I just ignore the "+94" in the first equation because we always have a subtraction between Sn - S(n-1)? Like this:

S6-S5 = 6^2 + 5*6 - 5^2 +5*5 =16
S4-S3 = 4^2 + 5*4 - 3^2 + 5*3 = 12
S2-S1 = 2^2 + 2*5 - 1 + 5 = 8

Yes, you can ignore 94 but only because the number of negative terms = number of positive terms and the coefficients of positive terms (all are 1) = coefficients of negative terms (all are 1).

Had it been : s5-s4+s3-s2+s1 , you could not have 'ignored' 94 as the number of terms for positive vs negative are not equal. So 94 would not have been cancelled.

Also, if it had been: s4- 3s3 + 2s2-s1 , even in this case, you can not ignore 94 (you might still be able to cancel all 94s but you should follow a systematic approach for questions that will provide highest ROI with least scope of error.
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Bunuel- how were we supposed to know that s6 meant plug in 6 for n and s5 meant plug in 5 for n? I have not seen this is any of my prep materials. Maybe I am dumb- but I was not able to draw that inference from the question.
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My 2 cents on this:

I don't think this is a tough question. I do however think this question can take time if not done properly.

The way I grouped these statements were as follows:

= 6^2-5^2 + 4^-3^2 + 2^2 - 1^2

+ 30 - 25 + 20-15 + 10 - 5

+ 94-94+94-94+94-94

= 21 + 15
= 36

E.
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