Bradley owns b video game cartridges. If Bradley’s total is one-third

Question

Bradley owns b video game cartridges. If Bradley’s total is one-third the total owned by Andrew and four times the total owned by Charlie, how many video game cartridges do the three of them own altogether, in terms of b?

A. (16/3)b
B. (17/4)b
C. (13/4)b
D. (19/12)b
E. (7/12)b

Kudos for a correct solution.

A. (16/3)b
B. (17/4)b
C. (13/4)b
D. (19/12)b
E. (7/12)b

Kudos for a correct  solution .

BrentGMATPrepNow · Accepted Answer

# of cartridges owned by Bradley = b 
# of cartridges owned by Andrew = 3b 
# of cartridges owned by Charlie = b/4

TOTAL # of cartridges = b + 3b + b/4 
Rewrite with a common denominator of 4 to get: 4b/4 + 12b/4 + b/4 
Combine terms to get: 17b/4

Answer: B

Cheers,
Brent

GMATinsight · Answer

Let,
Bradley owns B video games
Andrew owns A video games
Charlie owns C video games

B = (1/3)(A) = (4C)
i.e. A = 3B and C = B/4

Total Video game cartridges = A+B+C = 3B + B + B/4 = 17B/4

Answer: option B

KS15 · Answer

Brad owns b video games
Andrew owns 4b games
and Charlie owns b/4 games
Total number of games=b+4b+b/4=17b/4
Answer B

shailendra79s · Answer

Cartridges owned by Bradley = b
Cartridges owned by Andrew = 3b
Cartridges owned by Charlie = b/4
Total Cartridges = b+34+b/4 = (17/4)b
Answer: B

logblogger89 · Answer

Bradley's Ownership: b
Andrew's ownership: a
Charlie's Ownership: c

As per the question, Bradley's ownership, b = (1/3)a => a=3b
Also, Bradley's ownership, b=4c => c=b/4

Answer B

Altogether, they own 3b + b + b/4 = 17b/4

kunal555 · Answer

b=(1/3)a or a=3b
b=4c or c=b/4

Total = a+b+c = 3b+b+b/4 = 17b/4

Answer:-B

Bunuel · Answer

VERITAS PREP OFFICIAL SOLUTION:

Step 1: Categorize the problem

This problem is testing basic algebra and equations, with an extra layer of complexity by having variables in the answer choices.

Step 2: Think like the test maker

What is the key detail or key details in the problem? The key detail to immediately recognize is that the problem gives you Andrew and Charlie’s totals in relation to Bradley’s total rather than giving you Bradley’s total in relation to the other two; and then the problem asks you to solve the problem in terms of b. This means that you have to relate Andrew and Charlie’s values in relation to Bradley’s total. The test maker is attempting to force you to structure the problem in the opposite way that most people are used to structuring information. By gaining this insight, it makes it easier to solve the problem.

Step 3: Solve the problem

b = Bradley’s total

3b = Andrew’s total

(1/4)b = Charlie’s total

Add each total

b + 3b+ (1/4)b = 4b + (1/4)b = (16/4)b + (1/4)b = (17/4b

Therefore,  choose B .

EMPOWERgmatRichC · Answer

Hi All,

This question can be solved by TESTing VALUES.

We're told that:
1) Bradley owns B cartridges
2) Bradley's total is 1/3 of Andrew's Total (A)
3) Bradley's total is 4 times Charlie's Total (C)

We're asked how many TOTAL cartridges there are (so we're asked for the value of A+B+C).

IF...
B = 4
A = 12
C = 1

We're looking for an answer that equals 12+4+1 = 17 when B = 4

The answer choices are written in such a way so that you don't have to do much math to find the correct answer.

Final Answer:  B

GMAT assassins aren't born, they're made,
Rich

sasyaharry · Answer

Using 12 as the value for b we can see that the total number of cartridges = 12+36+4=51
Only answer  B  satisfies the equation because  \frac{17}{4}*12  = 51

DaX1100 · Answer

Great that I checked this Forum. The MGMAT (5th edition) provides "C" as the right answer, but the result in the explanation is 17/4 and therefore "B".
30min of my life wasted by trying to figure out why C instead of B

bumpbot · Answer

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Bradley owns b video game cartridges. If Bradley’s total is one-third

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Bradley owns b video game cartridges. If Bradley’s total is one-third

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