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Sub 505 (Easy)|   Sequences|                        
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Bunuel
In a certain sequence of 8 numbers, each number after the first is 1 more than the previous number. If the first number is −5, how many of the numbers in the sequence are positive?

(A) None
(B) One
(C) Two
(D) Three
(E) Four


Kudos for a correct solution.
-5,-4,-3,-2,-1,0,1,2 Answer (C)
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First term , a1 = -5
Common difference ,d =1
An= a1+(n-1)d
0 = -5 +(n-1)1 = -5 + n - 1 = n - 6
=> n = 6
Therefore, the number of terms which are positive is 8-6 =2

The list is -5 , -4 , -3 , -2 , -1 , 0 , 1 , 2
Number of terms which are positive = 2
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First term , a1 = -5
Common difference ,d =1
An= a1+(n-1)d
0 = -5 +(n-1)1 = -5 + n - 1 = n - 6
=> n = 6
Therefore, the number of terms which are positive is 8-6 =2

The list is -5 , -4 , -3 , -2 , -1 , 0 , 1 , 2
Number of terms which are positive = 2
Hey Skywalker,

appreciate if you could explain the first part of your solution??
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Hi Bunuel, thank you for your valuable posts, they are well explained and very complete! I have one question about 0 number in the GMAT: According to GMAT rules, 0 is considered as non negative and non positive, but in this example above, it is considered as positive number. Could you please exaplin me in which conditions can we consider it as positive?
Also, is it an even or odd number?
Thank you for your help!
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Hi Bunuel, thank you for your valuable posts, they are well explained and very complete! I have one question about 0 number in the GMAT: According to GMAT rules, 0 is considered as non negative and non positive, but in this example above, it is considered as positive number. Could you please exaplin me in which conditions can we consider it as positive?
Also, is it an even or odd number?
Thank you for your help!

Where above is 0 considered as positive???

ZERO:

1. 0 is an integer.

2. 0 is an even integer. An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even.

3. 0 is neither positive nor negative integer (the only one of this kind).

4. 0 is divisible by EVERY integer except 0 itself.

Check more here: number-properties-tips-and-hints-174996.html
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Given:

The first number in a sequence is -5 and each number after the first is 1 more than the previous number.

So the sequence would be :

-5 , -4 , -3 , -2 , -1 , 0 , 1 , 2 (8 numbers are there in the sequence)

There are only two positive numbers in the sequence: 1 and 2 ( 0 is neither positive nor negative )

The correct answer is C
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Video solution from Quant Reasoning:
Subscribe for more: https://www.youtube.com/QuantReasoning? ... irmation=1
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Bunuel
In a certain sequence of 8 numbers, each number after the first is 1 more than the previous number. If the first number is −5, how many of the numbers in the sequence are positive?

(A) None
(B) One
(C) Two
(D) Three
(E) Four
Solution:

According to the rule of the sequence, we can see that the 8 numbers are:

-5, -4, -3, -2, -1, 0, 1, and 2

Recalling that 0 is neither positive nor negative, we see that there are two positive numbers in the sequence.

Answer: C
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Bunuel
In a certain sequence of 8 numbers, each number after the first is 1 more than the previous number. If the first number is −5, how many of the numbers in the sequence are positive?

(A) None
(B) One
(C) Two
(D) Three
(E) Four



Answer: Option C

Video solution by GMATinsight

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Hi all, I've encountered a similar question in the official EA prep that asks "how many of the numbers in the sequence are exact", instead of the more commonly understood question "how many of the numbers in the sequence are positive". Does "exact" mean "positive" in the GMAT or EA?
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Wei915
Hi all, I've encountered a similar question in the official EA prep that asks "how many of the numbers in the sequence are exact", instead of the more commonly understood question "how many of the numbers in the sequence are positive". Does "exact" mean "positive" in the GMAT or EA?
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No, GMAT does not have its own "math", so I think it's just a typo there.
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Bunuel
In a certain sequence of 8 numbers, each number after the first is 1 more than the previous number. If the first number is −5, how many of the numbers in the sequence are positive?

(A) None
(B) One
(C) Two
(D) Three
(E) Four

Hi Bunuel
Why are we not counting Zero?, Zero is a positive Integer, right?

Thanks Bunuel
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raghav1708
Bunuel
In a certain sequence of 8 numbers, each number after the first is 1 more than the previous number. If the first number is −5, how many of the numbers in the sequence are positive?

(A) None
(B) One
(C) Two
(D) Three
(E) Four

Hi Bunuel
Why are we not counting Zero?, Zero is a positive Integer, right?

Thanks Bunuel

Every real number other than zero is either positive or negative. Numbers to the left of 0 are negative and numbers to the right of 0 are positive.


Notice that:
  • Zero is neither positive nor negative (the only one of this kind)!


ZERO:

1. Zero is an INTEGER.

2. Zero is an EVEN integer.

3. Zero is neither positive nor negative (the only one of this kind)

4. Zero is divisible by EVERY integer except 0 itself (\(\frac{x}{0} = 0\), so 0 is a divisible by every number, x).

5. Zero is a multiple of EVERY integer (\(x*0 = 0\), so 0 is a multiple of any number, x)

6. Zero is NOT a prime number (neither is 1 by the way; the smallest prime number is 2).

7. Division by zero is NOT allowed: anything/0 is undefined.

8. Any non-zero number to the power of 0 equals 1 (\(x^0 = 1\))

9. \(0^0\) case is NOT tested on the GMAT.

10. If the exponent n is positive (n > 0), \(0^n = 0\).

11. If the exponent n is negative (n < 0), \(0^n\) is undefined, because \(0^{negative}=0^n=\frac{1}{0^{(-n)}} = \frac{1}{0}\), which is undefined. You CANNOT take 0 to the negative power.

12. \(0! = 1! = 1\).



2. Properties of Integers



For more check Ultimate GMAT Quantitative Megathread



Hope it helps.
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Bunuel
raghav1708
Bunuel
In a certain sequence of 8 numbers, each number after the first is 1 more than the previous number. If the first number is −5, how many of the numbers in the sequence are positive?

(A) None
(B) One
(C) Two
(D) Three
(E) Four

Hi Bunuel
Why are we not counting Zero?, Zero is a positive Integer, right?

Thanks Bunuel

Every real number other than zero is either positive or negative. Numbers to the left of 0 are negative and numbers to the right of 0 are positive.


Notice that:
  • Zero is neither positive nor negative (the only one of this kind)!


ZERO:

1. Zero is an INTEGER.

2. Zero is an EVEN integer.

3. Zero is neither positive nor negative (the only one of this kind)

4. Zero is divisible by EVERY integer except 0 itself (\(\frac{x}{0} = 0\), so 0 is a divisible by every number, x).

5. Zero is a multiple of EVERY integer (\(x*0 = 0\), so 0 is a multiple of any number, x)

6. Zero is NOT a prime number (neither is 1 by the way; the smallest prime number is 2).

7. Division by zero is NOT allowed: anything/0 is undefined.

8. Any non-zero number to the power of 0 equals 1 (\(x^0 = 1\))

9. \(0^0\) case is NOT tested on the GMAT.

10. If the exponent n is positive (n > 0), \(0^n = 0\).

11. If the exponent n is negative (n < 0), \(0^n\) is undefined, because \(0^{negative}=0^n=\frac{1}{0^{(-n)}} = \frac{1}{0}\), which is undefined. You CANNOT take 0 to the negative power.

12. \(0! = 1! = 1\).



2. Properties of Integers



For more check Ultimate GMAT Quantitative Megathread



Hope it helps.


Thank you for the help Bunuel! Loved the explanation!
Thank you!
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-5,-4, -3, -2, -1, 0, 1, 2

since 0 is neither positive nor negative
the only positive integers are 1 and 2 (2 in number)
Therefore, option C
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