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Math Expert V
Joined: 02 Sep 2009
Posts: 60460
In a certain sequence of 8 numbers, each number after the first is 1  [#permalink]

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5 00:00

Difficulty:   5% (low)

Question Stats: 84% (00:39) correct 16% (00:43) wrong based on 976 sessions

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In a certain sequence of 8 numbers, each number after the first is 1 more than the previous number. If the first number is −5, how many of the numbers in the sequence are positive?

(A) None
(B) One
(C) Two
(D) Three
(E) Four

Kudos for a correct solution.

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Re: In a certain sequence of 8 numbers, each number after the first is 1  [#permalink]

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1
Bunuel wrote:
In a certain sequence of 8 numbers, each number after the first is 1 more than the previous number. If the first number is −5, how many of the numbers in the sequence are positive?

(A) None
(B) One
(C) Two
(D) Three
(E) Four

Kudos for a correct solution.

SVP  V
Status: It's near - I can see.
Joined: 13 Apr 2013
Posts: 1699
Location: India
GPA: 3.01
WE: Engineering (Real Estate)
Re: In a certain sequence of 8 numbers, each number after the first is 1  [#permalink]

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1
Bunuel wrote:
In a certain sequence of 8 numbers, each number after the first is 1 more than the previous number. If the first number is −5, how many of the numbers in the sequence are positive?

(A) None
(B) One
(C) Two
(D) Three
(E) Four

Kudos for a correct solution.

My Solution:

-5, -4, -3, -2, -1, 0, 1, 2

So only two numbers are positive (1 & 2) Answer C

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Verbal Forum Moderator V
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Re: In a certain sequence of 8 numbers, each number after the first is 1  [#permalink]

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1
First term , a1 = -5
Common difference ,d =1
An= a1+(n-1)d
0 = -5 +(n-1)1 = -5 + n - 1 = n - 6
=> n = 6
Therefore, the number of terms which are positive is 8-6 =2

The list is -5 , -4 , -3 , -2 , -1 , 0 , 1 , 2
Number of terms which are positive = 2
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Re: In a certain sequence of 8 numbers, each number after the first is 1  [#permalink]

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we have 0,1,2 as the non negative numbers; o is a positive number.
hence we have three positive numbers.

Thanks
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Re: In a certain sequence of 8 numbers, each number after the first is 1  [#permalink]

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2
In a certain sequence of 8 numbers, each number after the first is 1 more than the previous number. If the first number is −5, how many of the numbers in the sequence are positive?

(A) None
(B) One
(C) Two
(D) Three
(E) Four

In GMAT Zero is considered as an integer which is neither positive nor negative.

Non - Negative ( zero to positive infinity )

Solution to the question :
-5,-4,-3,-2,-1,0 , 1,2

Hence ans is 2 ..option C
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Re: In a certain sequence of 8 numbers, each number after the first is 1  [#permalink]

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Skywalker18 wrote:
First term , a1 = -5
Common difference ,d =1
An= a1+(n-1)d
0 = -5 +(n-1)1 = -5 + n - 1 = n - 6
=> n = 6
Therefore, the number of terms which are positive is 8-6 =2

The list is -5 , -4 , -3 , -2 , -1 , 0 , 1 , 2
Number of terms which are positive = 2

Hey Skywalker,

appreciate if you could explain the first part of your solution??
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Verbal Forum Moderator V
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Re: In a certain sequence of 8 numbers, each number after the first is 1  [#permalink]

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2
2
colorblind wrote:
Skywalker18 wrote:
First term , a1 = -5
Common difference ,d =1
An= a1+(n-1)d
0 = -5 +(n-1)1 = -5 + n - 1 = n - 6
=> n = 6
Therefore, the number of terms which are positive is 8-6 =2

The list is -5 , -4 , -3 , -2 , -1 , 0 , 1 , 2
Number of terms which are positive = 2

Hey Skywalker,

appreciate if you could explain the first part of your solution??

Hi colorblind ,
Please find the highlighted explanation in Blue .

First term , a1 = -5
Common difference ,d =1 (each number after the first is 1 more than the previous number )
The below is the formula for A.P
An= a1+(n-1)d
To find number of positive terms in the sequence we need to need number of integers equal to or less than 0.
So , i have calculated the position of 0 in the sequence . Zero is the 6th term in the sequence

0 = -5 +(n-1)1 = -5 + n - 1 = n - 6
=> n = 6
Therefore, the number of terms which are positive is 8-6 =2

Hope it helps !! _________________
When everything seems to be going against you, remember that the airplane takes off against the wind, not with it. - Henry Ford
The Moment You Think About Giving Up, Think Of The Reason Why You Held On So Long
Manager  G
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Re: In a certain sequence of 8 numbers, each number after the first is 1  [#permalink]

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Skywalker18 wrote:
First term , a1 = -5
Common difference ,d =1
An= a1+(n-1)d
0 = -5 +(n-1)1 = -5 + n - 1 = n - 6
=> n = 6
Therefore, the number of terms which are positive is 8-6 =2

The list is -5 , -4 , -3 , -2 , -1 , 0 , 1 , 2
Number of terms which are positive = 2

Hi Skywalker,

Thanks for the response, so:
An is the value of the nth term = 0
A1 is the first term = -5
n is the term number of interest =to find
d is the difference = 1

An = A1 + (n-1)d
0 = -5 + (n-1)*1
n = 6
So this formula comes handy for big set of numbers!

Great, I have never used this formula before. Thanks again!
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Re: In a certain sequence of 8 numbers, each number after the first is 1  [#permalink]

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Hi Bunuel, thank you for your valuable posts, they are well explained and very complete! I have one question about 0 number in the GMAT: According to GMAT rules, 0 is considered as non negative and non positive, but in this example above, it is considered as positive number. Could you please exaplin me in which conditions can we consider it as positive?
Also, is it an even or odd number?
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In a certain sequence of 8 numbers, each number after the first is 1  [#permalink]

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KariLouise wrote:
Hi Bunuel, thank you for your valuable posts, they are well explained and very complete! I have one question about 0 number in the GMAT: According to GMAT rules, 0 is considered as non negative and non positive, but in this example above, it is considered as positive number. Could you please exaplin me in which conditions can we consider it as positive?
Also, is it an even or odd number?

1. 0 is neither negative nor positive. In this question zero is not considered positive. Only digits 1 and 2 are considered positive.

2. Non-negative integers include "0"

2. 0 is an even number.
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Math Expert V
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Posts: 60460
Re: In a certain sequence of 8 numbers, each number after the first is 1  [#permalink]

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KariLouise wrote:
Hi Bunuel, thank you for your valuable posts, they are well explained and very complete! I have one question about 0 number in the GMAT: According to GMAT rules, 0 is considered as non negative and non positive, but in this example above, it is considered as positive number. Could you please exaplin me in which conditions can we consider it as positive?
Also, is it an even or odd number?

Where above is 0 considered as positive???

ZERO:

1. 0 is an integer.

2. 0 is an even integer. An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even.

3. 0 is neither positive nor negative integer (the only one of this kind).

4. 0 is divisible by EVERY integer except 0 itself.

Check more here: number-properties-tips-and-hints-174996.html
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Re: In a certain sequence of 8 numbers, each number after the first is 1  [#permalink]

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A rule in GMAT about the characteristics of the number zero:

Zero in an integer
Zero in neither positive or negative
Zero is an even number

Memorise these three points and you will ALWAYS get these type of questions right!
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Re: In a certain sequence of 8 numbers, each number after the first is 1  [#permalink]

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Given:

The first number in a sequence is -5 and each number after the first is 1 more than the previous number.

So the sequence would be :

-5 , -4 , -3 , -2 , -1 , 0 , 1 , 2 (8 numbers are there in the sequence)

There are only two positive numbers in the sequence: 1 and 2 ( 0 is neither positive nor negative )

_________________ Re: In a certain sequence of 8 numbers, each number after the first is 1   [#permalink] 01 Jun 2019, 21:17
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