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zxcvbnmas
What is the value of m in the equation below? \((\frac{1}{5})^m * (\frac{1}{4})^{24} = (\frac {1}{2(10)})^{47}\)

A) 23

B) 24

C) 46

D) 47

E) 48

Hi,

firsly, the Q in its present state cannot be correct and cannot have any of these answers..
the Q should have been
\((\frac{1}{5})^m * (\frac{1}{4})^{24} = (\frac {1}{2(10)^{47}})\)


In such Qs, we should get all the values in its simplest form..
\((\frac{1}{5})^m * (\frac{1}{4})^{24} = (\frac {1}{2(10)^{47}})\)..
\((\frac{1}{5})^m * (\frac{1}{2})^{24*2} = (\frac {1}{2*2^{47}*5^{47}})\)..
\((\frac{1}{5})^m * (\frac{1}{2})^{48} = (\frac {1}{2^{48}*5^{47}})\)..
fromthe two sides of eq we can get the power of 5 has to be 47..
so m =47...
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The strategy is to convert each side of the equation into multiples of 2 and 5 and then finally equate.
\(10^{47}\) can be written as \((2.5)^{47}\)

Rewriting the equation as below:

\(\frac{(1)^m}{(5)^m}\) . \(\frac{(1)^{24}}{(4)^{24}}\) = \(\frac{1}{2.(2.5)^{47}}\)

\(4^{24}\) can be written as \((2^2)^{24}\), which is equal to \(2^{48}\)

\(\frac{1}{(5)^m}\) . \(\frac{1}{(2)^{48}}\) = \(\frac{1}{2.(2.5)^{47}}\)

Now, cross multiply the denominators on both the sides.

\(2.(2.5)^{47}\) = \(5^m\) . \(2^{48}\)

Separating the powers, we get:

\(2^{48}.5^{47}\) = \(5^m\) . \(2^{48}\)

Rewriting the equation above

\(2^{48}.5^{47}\) = \(2^{48}\).\(5^m\)

Finally, since the bases are equal on either side of the equation, we could equate the powers of each base.

Therefore,
m=47
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Option D is correct
This is how I attempted
(1/5)^m*(1/4)^24=1/2(10)47
(1/5)^m=4^24/2(2*5)^47
(1/5)^m=2^48/2^48*5^47
left it with
(1/5)^m=1/5^47
so
m=47
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zxcvbnmas
What is the value of m in the equation below? \((\frac{1}{5})^m * (\frac{1}{4})^{24} = (\frac {1}{2(10)^{47}})\)

A) 23

B) 24

C) 46

D) 47

E) 48

EDITED THE Q

I agree with the explanation of AaronPond.

You need to make 47 zeros to equate both RHS and LHS. You have enough 2's. All you need is 47 5's and that's it. Straight D.
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The equation is the same as 5^m*4^24 = 2*10^47

=which is nothing but: 5^m*2^48 = 2^48*5^47

=> M=47

Ans D
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I just saw that rhs has (1/5)^47 and (1/5)^m on the lhs, and since no other no. was including 5 as a factor, I marked my answer as 47.
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