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Updated on: 24 Feb 2016, 08:07
Originally posted by Ekland on 24 Feb 2016, 08:01.
Last edited by ENGRTOMBA2018 on 24 Feb 2016, 08:07, edited 1 time in total.
Last edited by ENGRTOMBA2018 on 24 Feb 2016, 08:07, edited 1 time in total.
Reformatted the question.
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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Stacy and Heather are 20 miles apart and walk towards each other along the same route. Stacy walks at constant rate that is 1 mile per hour faster than heather's constant rate of 5 miles/hour. If Heather starts her journey 24 minutes after Stacy, how far from the original destination has Heather walked when the two meet?
A)7 mile
B)8 mile
C)9 mile
D)10 mile
E) 12 mile
A)7 mile
B)8 mile
C)9 mile
D)10 mile
E) 12 mile
25 Feb 2016, 01:07
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Nez
In the time, speed distance problems, it is better to write down the information first.
Attachment:
Stacy heather.JPG [ 11.71 KiB | Viewed 15771 times ]
Distance traveled by Stacy in 24 minutes = 6*(24/60) = 2.4 miles
For the rest of the distance, we can use the concept of relative speed to find out after how much time will they meet
Since both are walking in the same direction, we will add the speeds.
Therefore they will meet after 17.6/11 hours = 1.6 hours
Distance travelled by Heather in 1.6 hours = 5*1.6 = 8 miles.
Option B
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24 Feb 2016, 08:12
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Nez
Good question to practice translation of word problems into actual equations.
Original distance between S and H = 20 miles.
Speed of S = 5+6 = 6 mph, Speed of H = 5 mph.
Time traveled by H = t hours ---> time traveled by S = t+24/60 = t+2/5 hours.
Now, the total distances traveled by S and H = 20 miles ---> 6*(t+2/5)+5*t=20 ---> t= 8/5 hours. Thus H has traveled for 8/5 hours giving you a total distance for H = 5*8/5 = 8 miles.
B is thus the correct answer.
Hope this helps.
P.S.: based on the wording of the question, you should calculate "how far from the original destination has Heather walked when the two meet". 'Original destination' for H does not make any sense. Original destination for H was situated at a distance of 20 miles.
