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BillyZ
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GMAT 1: 750 Q51 V40 (Online)
Posts: 1,134
23 Feb 2017, 23:25
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
71% (02:53) correct
29%
(02:59)
wrong
based on 425
sessions
History
Date
Time
Result
Not Attempted Yet
A ball drops from a certain height. The height it will reach after rebounding from the floor is 80 percent of the previous height. The total travel is 3,104cm when it touches the floor on the third time. What is the value of the original height, in cm?
A. 400cm
B. 500cm
C. 600cm
D. 700cm
E. 800cm
A. 400cm
B. 500cm
C. 600cm
D. 700cm
E. 800cm
24 Feb 2017, 08:49
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AustinKL
Let x be the ball's original height
So, x = distance of the ball's first DROP
And 0.8x = distance of the ball's first RISE
0.8x = distance of the ball's second DROP
(0.8)(0.8x) = distance of the ball's second RISE
(0.8)(0.8x) = distance of the ball's third DROP
At this point, the ball touches the ground for the third time.
So, the TOTAL distance = x + 0.8x + 0.8x + (0.8)(0.8x) + (0.8)(0.8x) = 3104 cm
Simplify: x + 0.8x + 0.8x + 0.64x + 0.64x = 3104 cm
Simplify: 3.88x = 3104
Solve: x = 800
Answer: E
General Discussion
0akshay0
Joined: 19 Apr 2016
Last visit: 14 Jul 2019
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Location: India
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GMAT 1: 570 Q48 V22
GMAT 2: 640 Q49 V28
GPA: 3.5
WE:Web Development (Computer Software)
24 Feb 2017, 00:26
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AustinKL
Let x be original height
total distance traveled => x + 2*0.8x + 2*0.64x = 3104
x + 1.6x + 1.28x = 3104
3.88x = 3104
x = 800
Hence option E is correct
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