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555-605 (Medium)|   Roots|      
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Bunuel
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What is 63^(1/2)/147^(1/2) 22 Jun 2017, 23:47
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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25% (medium)

Question Stats:

73% (01:42) correct 27% (02:02) wrong based on 467 sessions

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What is \(\frac{\sqrt{63}}{\sqrt{147}}\)?


A. \(\frac{\sqrt{3}}{7}\)

B. \(\frac{3}{7}\)

C. \(\frac{\sqrt{21}}{7}\)

D. \(\frac{3\sqrt{21}}{7}\)

E. \(\frac{7}{\sqrt{3}}\)
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C
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What is 63^(1/2)/147^(1/2) 22 Jun 2017, 23:55
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What is \(\frac{\sqrt{63}}{\sqrt{147}}\)?


A. \(\frac{\sqrt{3}}{7}\)

B. \(\sqrt{3/7}\)

C. \(\frac{\sqrt{21}}{7}\)

D. \(\frac{3\sqrt{21}}{7}\)

E. \(\frac{7}{\sqrt{3}}\)
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\(\frac{\sqrt{63}}{\sqrt{147}}\)

\(\sqrt{7*3*3/7*7*3}\)

\(\sqrt{3/7}\) . Answer (B)...
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What is 63^(1/2)/147^(1/2) 23 Jun 2017, 00:09
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What is \(\frac{\sqrt{63}}{\sqrt{147}}\)?


A. \(\frac{\sqrt{3}}{7}\)

B. \(\sqrt{3/7}\)

C. \(\frac{\sqrt{21}}{7}\)

D. \(\frac{3\sqrt{21}}{7}\)

E. \(\frac{7}{\sqrt{3}}\)
Show more

\(\frac{\sqrt{63}}{\sqrt{147}}\)
=\(\frac{\sqrt{3*3*7}}{\sqrt{3*7*7}}\)
=\(\frac{\sqrt{3}}{\sqrt{7}}\)

Answer B
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What is 63^(1/2)/147^(1/2) 26 Jun 2017, 09:44
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Why the answer isn't C?

I divide both Numerator and Denominator by 3 and I get 21/49 under square root
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What is 63^(1/2)/147^(1/2) 26 Jun 2017, 11:18
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Bunuel
What is \(\frac{\sqrt{63}}{\sqrt{147}}\)?


A. \(\frac{\sqrt{3}}{7}\)

B. \(\sqrt{3/7}\)

C. \(\frac{\sqrt{21}}{7}\)

D. \(\frac{3\sqrt{21}}{7}\)

E. \(\frac{7}{\sqrt{3}}\)
Show more


\(\sqrt{63} = 3\sqrt{7}\)
\(\sqrt{147} = 7\sqrt{3}\)

So, \(\frac{\sqrt{63}}{\sqrt{147}}\)

\(= 3\sqrt{7}/7\sqrt{3}\)

\(= 3\sqrt{7}*\sqrt{3}/7\sqrt{3}*\sqrt{3}\)

= \(3\sqrt{21}/7*3\)

= \(\frac{\sqrt{21}}{7}\)

Thus, answer will be (C)
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What is 63^(1/2)/147^(1/2) 26 Jun 2017, 11:26
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+C

we must not leave square roots in denominator.
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What is 63^(1/2)/147^(1/2) Updated on: 26 Jun 2017, 12:40
Originally posted by ydmuley on 26 Jun 2017, 11:37.
Last edited by ydmuley on 26 Jun 2017, 12:40, edited 1 time in total.
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What is \(\frac{\sqrt{63}}{\sqrt{147}}\)?

\(\frac{\sqrt{63}}{\sqrt{147}}\)

\(\frac{\sqrt{7 * 3 * 3}}{\sqrt{7 * 7 *3}}\)

\(\frac{3 * \sqrt{7}}{7 * \sqrt{3}}\)

\(\frac{3 * \sqrt{7} * \sqrt{3}}{7 * \sqrt{3} * \sqrt{3}}\)

\(\frac{3 * \sqrt{21}}{7 * 3}\)

\(\frac{\sqrt{21}}{7}\)

Hence, Answer is C
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What is 63^(1/2)/147^(1/2) 26 Jun 2017, 12:03
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Abhishek009
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What is \(\frac{\sqrt{63}}{\sqrt{147}}\)?


A. \(\frac{\sqrt{3}}{7}\)

B. \(\sqrt{3/7}\)

C. \(\frac{\sqrt{21}}{7}\)

D. \(\frac{3\sqrt{21}}{7}\)

E. \(\frac{7}{\sqrt{3}}\)


\(\sqrt{63} = 3\sqrt{7}\)
\(\sqrt{147} = 7\sqrt{3}\)

So, \(\frac{\sqrt{63}}{\sqrt{147}}\)

\(= 3\sqrt{7}/7\sqrt{3}\)

\(= 3\sqrt{7}*\sqrt{3}/7\sqrt{3}*\sqrt{3}\)

= \(3\sqrt{21}/7*3\)

= \(\frac{\sqrt{21}}{7}\)

Thus, answer will be (C)
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Hello Abhishek009 - Why not B in this case? Are you referring to any specific rule to solve this question?
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What is 63^(1/2)/147^(1/2) 26 Jun 2017, 12:07
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Bunuel
What is \(\frac{\sqrt{63}}{\sqrt{147}}\)?


A. \(\frac{\sqrt{3}}{7}\)

B. \(\sqrt{3/7}\)

C. \(\frac{\sqrt{21}}{7}\)

D. \(\frac{3\sqrt{21}}{7}\)

E. \(\frac{7}{\sqrt{3}}\)
Show more

Bunuel Option B and C are the same


B) √(3/7)
C) √21/7 = √3*√7/√7*√7= √(3/7)
.

Posted from my mobile device
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What is 63^(1/2)/147^(1/2) 26 Jun 2017, 12:18
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GMATinsight
Bunuel
What is \(\frac{\sqrt{63}}{\sqrt{147}}\)?


A. \(\frac{\sqrt{3}}{7}\)

B. \(\sqrt{3/7}\)

C. \(\frac{\sqrt{21}}{7}\)

D. \(\frac{3\sqrt{21}}{7}\)

E. \(\frac{7}{\sqrt{3}}\)

Bunuel Option B and C are the same


B) √(3/7)
C) √21/7 = √3*√7/√7*√7= √(3/7)
.

Posted from my mobile device
Show more

Yes, formatting error there. B is simply \(\frac{3}{7}\), not \(\sqrt{3/7}\). Edited. Thank you.
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What is 63^(1/2)/147^(1/2) 26 Jun 2017, 12:43
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Bunuel
What is \(\frac{\sqrt{63}}{\sqrt{147}}\)?


A. \(\frac{\sqrt{3}}{7}\)

B. \(\sqrt{3/7}\)

C. \(\frac{\sqrt{21}}{7}\)

D. \(\frac{3\sqrt{21}}{7}\)

E. \(\frac{7}{\sqrt{3}}\)


\(\sqrt{63} = 3\sqrt{7}\)
\(\sqrt{147} = 7\sqrt{3}\)

So, \(\frac{\sqrt{63}}{\sqrt{147}}\)

\(= 3\sqrt{7}/7\sqrt{3}\)

\(= 3\sqrt{7}*\sqrt{3}/7\sqrt{3}*\sqrt{3}\)

= \(3\sqrt{21}/7*3\)

= \(\frac{\sqrt{21}}{7}\)

Thus, answer will be (C)

Hello Abhishek009 - Why not B in this case? Are you referring to any specific rule to solve this question?
Show more

You can ignore this as Bunuel has changed the options.
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What is 63^(1/2)/147^(1/2) 26 Jun 2017, 12:56
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Bunuel
What is \(\frac{\sqrt{63}}{\sqrt{147}}\)?


A. \(\frac{\sqrt{3}}{7}\)

B. \(\frac{3}{7}\)

C. \(\frac{\sqrt{21}}{7}\)

D. \(\frac{3\sqrt{21}}{7}\)

E. \(\frac{7}{\sqrt{3}}\)
Show more

To resolve the confusion earlier in the thread, here's a recap:

- Originally, B incorrectly said \(\sqrt{\frac{3}{7}}\)
- This is actually the same as C, just simplified differently. \(\sqrt{\frac{3}{7}}\) and \(\frac{\sqrt{21}}{7}\) have the same value - you can plug them into a calculator to check.




- The GMAT will never do this. If the answer choices are numbers, the right answer will always be the one and only answer that has the correct value. You'll never have to make a decision based on how the answer is formatted.
- Unfortunately, that means you can't eliminate answer choices just because they have a square root in the denominator (for example!).
- However, look out for situations where you simplify the answer in a certain way, and then you don't see that answer choice in the options - especially in problems that have square roots and exponents. Normally, you might assume that you got the wrong answer. However, it's possible that your answer is in the answer choices, but it's just written differently. Look out for that!
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What is 63^(1/2)/147^(1/2) 26 Jun 2017, 12:59
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Bunuel
What is \(\frac{\sqrt{63}}{\sqrt{147}}\)?


A. \(\frac{\sqrt{3}}{7}\)

B. \(\frac{3}{7}\)

C. \(\frac{\sqrt{21}}{7}\)

D. \(\frac{3\sqrt{21}}{7}\)

E. \(\frac{7}{\sqrt{3}}\)
Show more

\(\frac{\sqrt{63}}{\sqrt{147}}\)

\(\sqrt{3^2 * 7} / \sqrt{7^2 * 3}\)

\(3 \sqrt{7}/7\sqrt{3}\)

Multiplying numerator and denominator with \(\sqrt{3}\)

\(3 \sqrt{7} * \sqrt{3}\)\(/ 7 * \sqrt{3}\) * \(\sqrt{3}\)

\(3 \sqrt{21} / 7 * 3\)

\(\sqrt{21}/7\) . Answer (C)...
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What is 63^(1/2)/147^(1/2) 27 Jun 2017, 04:52
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Bunuel
What is \(\frac{\sqrt{63}}{\sqrt{147}}\)?


A. \(\frac{\sqrt{3}}{7}\)

B. \(\frac{3}{7}\)

C. \(\frac{\sqrt{21}}{7}\)

D. \(\frac{3\sqrt{21}}{7}\)

E. \(\frac{7}{\sqrt{3}}\)
Show more

√63/√147 < 8/12 = 0.64

A) √3/7 = 1.7/7= 0.2
B) (3/7) = 0.43
C) √21/7 = 4.6/7= 0.65
D) 3√21/7 = 1.8
E) 7/√3 = 4.1

I always prefer approximation in all such questions...

Answer Option C
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What is 63^(1/2)/147^(1/2) 28 Jun 2017, 16:51
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Bunuel
What is \(\frac{\sqrt{63}}{\sqrt{147}}\)?


A. \(\frac{\sqrt{3}}{7}\)

B. \(\frac{3}{7}\)

C. \(\frac{\sqrt{21}}{7}\)

D. \(\frac{3\sqrt{21}}{7}\)

E. \(\frac{7}{\sqrt{3}}\)
Show more
'

We can simplify the given expression:

√63/√147 = (√9 x √7)/(√49 x √3) = (3√7)/(7√3)

Multiplying by √3/√3, we have:

(3√21)/21 = √21/7

Answer: C
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What is 63^(1/2)/147^(1/2) 29 Jun 2017, 09:38
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Bunuel
What is \(\frac{\sqrt{63}}{\sqrt{147}}\)?


A. \(\frac{\sqrt{3}}{7}\)

B. \(\sqrt{3/7}\)

C. \(\frac{\sqrt{21}}{7}\)

D. \(\frac{3\sqrt{21}}{7}\)

E. \(\frac{7}{\sqrt{3}}\)

\(\frac{\sqrt{63}}{\sqrt{147}}\)

\(\sqrt{7*3*3/7*7*3}\)

\(\sqrt{3/7}\) . Answer (B)...
Show more


Both B & C are correct. But now the option B has changed from \(\sqrt{3/7}\) to \(3/7\). So, wrt to current question, (C) is correct.
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What is 63^(1/2)/147^(1/2) 29 Jun 2017, 09:40
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Abhishek009
Bunuel
What is \(\frac{\sqrt{63}}{\sqrt{147}}\)?


A. \(\frac{\sqrt{3}}{7}\)

B. \(\sqrt{3/7}\)

C. \(\frac{\sqrt{21}}{7}\)

D. \(\frac{3\sqrt{21}}{7}\)

E. \(\frac{7}{\sqrt{3}}\)


\(\sqrt{63} = 3\sqrt{7}\)

\(\sqrt{147} = 7\sqrt{3}\)

So, \(\frac{\sqrt{63}}{\sqrt{147}}\)

\(= 3\sqrt{7}/7\sqrt{3}\)

\(= 3\sqrt{7}*\sqrt{3}/7\sqrt{3}*\sqrt{3}\)

= \(3\sqrt{21}/7*3\)

= \(\frac{\sqrt{21}}{7}\)

Thus, answer will be (C)
Show more

Both B & C are correct. But now the option B has changed from \(\sqrt{3/7}\) to \(3/7\). So, wrt to current question, (C) is correct.
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What is 63^(1/2)/147^(1/2) 10 Dec 2024, 03:30
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