The average of four integers is 8. If the greatest of the four intege

Question

The average of four integers is 8. If the greatest of the four integers is 16, what is the minimum possible value of the least of the four integers

A. -32
B. -16
C. -13
D. 0
E. 1

calappa1234 · Answer

Not getting this at all.

If the average of 4 integers is 32, then the sum of those 4 integers should be equal to 4*32 = 128

If the greatest of the 4 numbers is 16, then to minimize the smallest integer, I set the 2nd and 3rd integer to the highest that they could be (1 less than 16) = 15.

16+15+15 = 46.

Therefore to get the value of the smallest, i subtracted the sum of what all four should equal to get an avg of 32 (128), from the sum of the greatest 3 integers (46). I get 82 as an answer. This doesn't make any sense at all.

What am i doing wrong here? Help!

pushpitkc · Answer

Given data:  
Average(4 integers) : 8
Max number : 16

Since the average of 4 numbers is 8, the total must be 32.
If the maximum possible value of the integers is 16, the minimum value could be -16 if the other 2 integers are also 16.
Though -13,0 and 1 are also possible, since we are asked to find the minimum value, Option B stands out and is our answer!

Average =  \frac{16+16+16-16}{4} = \frac{32}{4} = 8 (Option B)

Luckisnoexcuse · Answer

sum of all integers will be 8*4 = 32
 Greatest  of all integers is 16
-32 is not possible as -32+16=-16..we cannot construct 48 with two integers less than 16
-16 is not possible as we cannot construct 32 with two integers less than 16
-13 is possible as -13+16 = 3..we can construct 29 with two integers less than 16 (14 and 15)

C

shruthiarvindh · Answer

Average of four integers is 8. Sum = 32.
Greatest integer is 16, Sum of remaining 3 integers is 32-16 = 16

i.e. sum of ( the least of four integers + remaining 2 integers )= 16
Trial and error based on answer choices above.

A. -32 + x = 16
 x = 48 . Sum of remaining two cannot be 48 since it is greater than overall sum. Eliminated
B. -16 + x = 16
 x = 32. Eliminated
C. -13 + x = 16
 x = 29. 
D. 0 +x = 16
 x = 16. 
E. 1 + x = 16
 x = 15.

Answer is C, since that is the lesser value compared D and E.

Luckisnoexcuse · Answer

shruthiarvindh 
i think u missed -13 + x = 16 => x= 29 (14,15)

Ammi1717 · Answer

I think answer is B

Avg = sum/no. of integers i.e sum= 4x8 = 32.

-16 + 16 + 16 + 16 = 32.

Correct me if I went wrong somewhere.

Sent from my iPhone using GMAT Club Forum

Nikkb · Answer

given : a+b+c+d /4 = 8 and let d be greatest and a be smallest number
a+b+c+d =32

given greatest number d=16

greatest number =16 => means other numbers are less or equal to 16.

a+b+c+16 =32 => a+b+c =16

option 1 if a =-32 => b+c =16+32 = 48 . So basically 48/2 =24 will be minimum value of one of the variable. Not possible because d=16 is greatest.

option 2 of a=-16 => b+c=16+16 =32. . So basically 32/2 =16 will be minimum value of one of the variable. so both b and c can be 16. And in this condition also greatest number will remain 16. This satisfy given condition.
Therefore minimum possible value of a =-16

Answer = B

gracie · Answer

if the greatest integer=16,
then the first three integers must sum to 16
assume least integer=-16
16-(-16)=32
thus, the two middle integers must sum to 32
32=16+16
thus, the four integers are -16,16,16,16
B

generis · Answer

If the average of four integers is 8, their sum is 32.

The greatest integer of the four is 16.

Nothing in the problem says the integers cannot be the same.

The least of the four integers will be the smallest when the two "middle" values are equal to the greatest possible integer, which is given as 16 -- if we "weight" the average heavily on the high end, then we allow one value with less weight to be very small.

So if three of the four = 16, the least possible value of the fourth integer is

16 + 16 + 16 + x = 32
48 + x = 32
x = -16

(And  \frac{-16 +16 +16 +16}{4}  =  \frac{32}{4}  = 8 average)

Answer B

JeffTargetTestPrep · Answer

Using the formula average = sum/quantity, we see that the sum of the integers is 8 x 4 = 32. If the greatest integer is 16, the next two “smaller” integers can also be 16. So, the sum of the three largest integers is 16 x 3 = 48 and the smallest-value integer would be 32 - 48 = -16.

Answer: B

gblessing · Answer

The average of four integers is 8. If the greatest of the four integers is 16, what is the minimum possible value of the least of the four integers

The average of four integers is 8 -> (w+x+y+z)/4=8
Greatest of the four is 16 -> (16+x+y+z)/4=8

32= 16+x+y+z (multiple both sides by four)
16= x+y+z (subtract 16 from both sides)

If we are trying to find the minimum value of the smallest, then we can maximize the other two: 15 +14. Please remember 16 was the highest of all the numbers (given). Therefore the next two highest could be 29 (15+14). 29 + X =16. Therefore answer c (-13) is my response.

Please let me know your thoughts. First time posting, looking forward to this GMAT journey with all of you!

GMATYoda · Answer

When you're working with a Min/Max problem - such as this one that asks you to minimize the least value in a set of numbers - you will want to organize your work by asking yourself:

Since the four values average to 8, that means that their sum is 32. Therefore 16 + 16 + 16 + x = 32. This then means that x = -16, making answer choice B correct.

ichbinpolly · Answer

Please, could someone help me to understand?

if someone gives you 3 numbers a, b and c.
a = 1 
b = 1
c = 1

and ask you to pick the greatest.

If the 3 numbers are equal, how are you supposed to choose?

Can a number be the greatest and still be the same as others? Does anyone have a formal definition for "greatest"?

The average of four integers is 8. If the  greatest value the integers can be is 16 , what is the minimum possible value of the least of the four integers?

shivangi2202 · Answer

Hello, I solved the following question as -32+0+16+16, can anyone help me understand why this is incorrect?

Bunuel · Answer

The average of -32, 0, 16, and 16 is 0, not 8.

AVMachine · Answer

Total = 8 * 4 = 32
Max = 16
Four Nos. Can Be = 16 + 16 + 16 - 16 = 32

So least no -16.

bumpbot · Answer

Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.

The average of four integers is 8. If the greatest of the four intege

Prep Toolkit

Top 5 GMAT Debrief Videos

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards

GMAT Problem Solving (PS) Questions

The average of four integers is 8. If the greatest of the four intege

Prep Toolkit

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards