A stretch of land measuring 50 m in length is covered with wall on sid

Question

A stretch of land measuring 50 m in length is covered with wall on sides. If 2*2 *2m boxes are to placed at equal interval of 5m from each other and atleast 5 m from the walls, how many boxes can be placed in entire length of 50m?

(A) 6
(B) 7
(C) 8
(D) 9
(E) 10

New Question

(A) 6
(B) 7
(C) 8
(D) 9
(E) 10

New Question

debarshipulock · Answer

max 6 can be placed.

Posted from my mobile device

banuprakash · Answer

I think 7 is the answer.

50/(2+5)=7.1something

Here, 2 is the width of block + 5 meter interval.

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Mick1005 · Answer

I think B.
5B5B5B5B5B5B5B. Each B measures 2.
Each 5B measures seven.
So we can accommodate seven 5B's. Thus, seven B's.

AkshdeepS · Answer

Its (A)

Total length = 50 m

As first box has to be placed 5 mts away from the wall and one box is of 2 m (as all dimensions are of 2 m);

we have (5+2) + (5+ 2) + (5 +2) + (5+2) + (5+2) + (5+2) = 6 sets covered 42 mts

If we place one more box it will give us 49 mts, but as the distance from wall should be 5 mts, we can't place this set.

Therefore (A), we can place only 6 boxes.

Fighter28 · Answer

Ans is A.
For better understanding pls find attached file. File contains sketch, which is self explanatory.

bumpbot · Answer

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A stretch of land measuring 50 m in length is covered with wall on sid

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A stretch of land measuring 50 m in length is covered with wall on sid

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