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Take the fourth root: \(|x| < |y|\);

Since both are negative, then \(-x < -y\);


Hi Bunuel,

can you shortly elaborate on the underlying rule of the above steps?

Thank you!
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Take the fourth root: \(|x| < |y|\);

Since both are negative, then \(-x < -y\);


Hi Bunuel,

can you shortly elaborate on the underlying rule of the above steps?

Thank you!

Absolute value properties:

When \(x\leq{0}\) then \(|x|=-x\), or more generally when \(some \ expression\leq{0}\) then \(|some \ expression|={-(some \ expression)}\). For example: \(|-5|=5=-(-5)\);

When \(x\geq{0}\) then \(|x|=x\), or more generally when \(some \ expression\geq{0}\) then \(|some \ expression|={some \ expression}\). For example: \(|5|=5\).

10. Absolute Value



For more check Ultimate GMAT Quantitative Megathread



Hope it helps.
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If x and y are negative and \(x^4-y^4<0\) which of the following must be true?

I: \(x<y\)

II: \(xy<y^2\)

III: \((x+y)^2<(x-y)^2\)

A.) I only
B.) II only
C.) III only
D.) I & II
E.) II & III

From question stem, We can organize exmaples

Let x = -1 & y = -2

Let x = \(\frac{-1}{4}\) & y = \(\frac{-1}{2}\)

Let x = \(\frac{-1}{2}\) & y = -1

I: \(x<y\)........From examples above.......... NOT True

II: \(xy<y^2\)....\(xy-y^2<0\).......y<0 & x>y........From examples above........True

III: \((x+y)^2<(x-y)^2\)..........Take first example to DISPROVE........ NOT True

Answer: B
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If Y^4 is greater than X^4 and both X & Y are negative, then Y has to be less than X (for example -8 & -2. (-8)^4 is greater than (-2)^4, but -8 is less than -2)

Substitute and check for x= -2 & y= -3

Smash B
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If x and y are negative and \(x^4-y^4<0\) which of the following must be true?

I: \(x<y\)

II: \(xy<y^2\)

III: \((x+y)^2<(x-y)^2\)

A.) I only
B.) II only
C.) III only
D.) I & II
E.) II & III
Given x^4 < y^4
=> |x| < |y|

Stmt I:
x<y this may not be true eg x=-1, y=-2

Here |x|<|y| but x>y

Eliminate A,D

Stmt 2:
xy<y^2
Given |x| < |y|
|x||y| < |y|^2 (because absolute value is positive comparison operator remains same.
since both are of same signs this must be equivalent to xy < y^2
Must be True
Eliminate C

Stmt3:
(x+y)^2 < (x-y)^2

(|x| + |y|)^2 = |x|^2 + |y|^2 + 2|x||y|
(|x| - |y|)^2 = |x|^2 + |y|^2 - 2|x||y|

=> (|x| + |y|)^2 > (|x| - |y|)^2

because x and y are of the same sign the above expressions will hold true for (x+y)^2 and (x-y)^2
Therefore (x+y)^2 < (x-y)^2 must be false.
Eliminate E

Correct Answer: B
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I did it by assumption method,

where x=-2 and y=-3

Am i wrong?
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I did it by assumption method,

where x=-2 and y=-3

Am i wrong?
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I did it by assumption method,

where x=-2 and y=-3

Am i wrong?
These values also lead to the correct result that only II must be true. However, generally, for must-be-true questions, relying on specific values is not a good approach. A statement might hold for some chosen values but fail for others. That’s why, for must-be-true questions, number plugging is useful mainly to disprove an option, not to establish that it is always true.
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