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Statement 1:X is not prime
Implies that the absolute difference will always be greater than 1 except for just one case when x=1.Insufficient
Statement 2 in itself is also insufficient.When x=2,y=3 & absolute diff=1(not greater than 1)
It will be greater than 1 for x=4 etc.
Combining both statements, we have x=neither prime nor 1,so absolute diff of x & y will always be greater than 1.
Ans C

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Hi All,

This question is built around several Number Properties, but you don't need to know those rules to get the question correct. TESTing VALUES and pattern-matching will get you the correct answer.

We're told that X and Y are positive integers and the Y = the sum of all the unique factors of X. We're asked if |X-Y| > 1. This is a YES/NO question.

Fact 1: X is NOT prime

IF....
X = 1
The only factor of 1 is 1
Y = 1
|1-1| = 0 and the answer to the question is NO

IF....
X = 4
The factors of 4 are 1, 2 and 4
Y = 7
|4-7| = 3 and the answer to the question is YES
Fact 1 is INSUFFICIENT

Fact 2: X does NOT = 1

IF....
X = 2
The factors of 2 are 1 and 2
Y = 3
|2-3| = 1 and the answer to the question is NO

IF....
X = 4
The factors of 4 are 1, 2 and 4
Y = 7
|4-7| = 3 and the answer to the question is YES
Fact 2 is INSUFFICIENT

Combined, we know....
X is NOT prime
X is NOT 1

IF....
X = 4
The factors of 4 are 1, 2 and 4
Y = 7
|4-7| = 3 and the answer to the question is YES

IF....
X = 6
The factors of 6 are 1, 2, 3 and 6
Y = 12
|6-12| = 6 and the answer to the question is YES

From these examples, you can see that since X is NOT prime (and NOT 1), then it will have factors BESIDES itself and the number 1. Thus Y will always be MORE than 1 greater than X and the answer to the question will ALWAYS be YES.
Combined, SUFFICIENT

Final Answer:
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If positive integer y is equal to the sum of all the unique factors of the positive integer x, is |x-y| > 1?

(1) x is not prime.
(2) x does not equal 1.

So here is the thing about sum of unique factors of positive integers:
Except 1 every positive integer has 2 or more factors -
Prime numbers have exactly 2 factors: 1 and itself -
Composite numbers have more than 2 factors: 1, itself and at least one more.

So if x = 1, sum of factors (y) = 1
If x = prime, sum of factors (y) = x+1
If x is Composite, sum of factors (y) = x+1+ (At least one more factor)

So difference between x and y is greater than 1 for only the composite numbers.

Statement 1 tells us that x is not prime and statement 2 tells us that it is not equal to 1 (1 is neither prime nor composite). So together, we know that x is composite. Hence we need both statements to answer the question.

Answer (C)

Hi Karishma, what about perfect numbers?

If we take the example of 6(from the given conditions its not prime and not 1) : factors of 6 are 1,2,3 sum=1+2+3 is 6 ..here x-y is 0.

Can you pls explain this ...I marked the answer as E based on this reasoning
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Hi schazamhuzzah,

You've made a minor mistake with your example:

The factors of 6 are 1, 2, 3 AND 6.....so the sum of the factors is 12 (not 6). By extension, the value of |X-Y| = |6-12| = |-6| = 6.

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I got tricked and answered A because I thought that 1 was a prime.

For |x-y| > 1, x cant be 1, 2, 3, 5, 7, any prime

For x = 1, |x-y| = 0. For x = 2 and 3, their only factors are themselves and 1, so |x-y| = 1 which is not > 1. Because I thought 1 was a prime, I thought it was eliminated from the possible result set, so I thought it was sufficient because it was telling us x = 4 or more.

In reality, since 1 is NOT a prime, statement 1 still gives 2 possible answers |x-y| < 1 if x = 1, and > 1 if x = 4, 6, etc.

Therefore statement 2 completes for us because it elimiantes 1, and x is 4, 6, 8, etc.

Note to self, memorize properties of numbers for edge cases near 0!
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schazamhuzzah
VeritasPrepKarishma
BabySmurf
If positive integer y is equal to the sum of all the unique factors of the positive integer x, is |x-y| > 1?

(1) x is not prime.
(2) x does not equal 1.

So here is the thing about sum of unique factors of positive integers:
Except 1 every positive integer has 2 or more factors -
Prime numbers have exactly 2 factors: 1 and itself -
Composite numbers have more than 2 factors: 1, itself and at least one more.

So if x = 1, sum of factors (y) = 1
If x = prime, sum of factors (y) = x+1
If x is Composite, sum of factors (y) = x+1+ (At least one more factor)

So difference between x and y is greater than 1 for only the composite numbers.

Statement 1 tells us that x is not prime and statement 2 tells us that it is not equal to 1 (1 is neither prime nor composite). So together, we know that x is composite. Hence we need both statements to answer the question.

Answer (C)

Hi Karishma, what about perfect numbers?

If we take the example of 6(from the given conditions its not prime and not 1) : factors of 6 are 1,2,3 sum=1+2+3 is 6 ..here x-y is 0.

Can you pls explain this ...I marked the answer as E based on this reasoning

Every number has at least 2 factors: 1 and itself. You forgot the itself part. It may have other factors too.
So 6 has 6 as a factor too.

For more on factors, check this post: https://www.gmatclub.com/forum/veritas-prep-resource-links-no-longer-available-399979.html#/2010/12 ... ly-number/
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If positive integer y is equal to the sum of all the unique factors of the positive integer x, is \(|x-y| > 1\)?

(1) x is not prime.
(2) \(x ≠ 1\).

Official solution from Veritas Prep.

Solution: C

Try to break the pattern first. If x is prime, it will have two factors: itself and 1, so \(y = x+1\). \(|x-(x+1)| = 1\), so if x is prime \(|x-y|\) will not be greater than 1. If x is exactly one, then y = x and \(|x-x| = 0\), which is not greater than 1. If x is ANY OTHER eligible integer (a positive integer greater than 1 that is not prime) \(|x-y| > 1\). (Try a few if you like – the extra factors other than the number itself and 1 guarantee that \(y\) is at least \(= x+2\).) Statement (1) is thus not sufficient, nor is statement (2), but together both primes and 1 are ruled out, meaning that \(|x-y| > 1\). (C).
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