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Bunuel
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Since the last digit of the product is 5, either B or D has to be 5.

Statement 1 - D is Prime. D can be 5, but can also be 3 or 7. This statement is insufficient.

Statement 2 - B is not prime. This statement implies that B is not 5, so D has to be 5. Now, 1995 is perfectly divisible by 05, 15, 35 and 95.
05 is not acceptable as per the condition given in the question. 15 will also be rejected, as AB will then need to be 133.
35 is also rejected, as AB will be 57, but all the digits are distinct.

Thus, only remaining option is 95 (95*21). All conditions are satisfied and C will be 9.

Answer - B.
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Hi kunals31,

You made a nice deduction when dealing with Fact 1, but in DS questions you have to factor in ALL of the information that you're given (AND answer the question that's asked) before you can state that a Fact is sufficient or insufficient.

Here, we're told that each of the 4 letters represents a DIFFERENT NON-0 digit. Given the possibilities that you've described, what would each letter in the final equation be? Would there be ANY DUPLICATES (because that's NOT allowed according to the prompt)...?

Sometimes DS questions require a couple of extra "steps" to prove what the correct answer is. As you score higher and higher in the Quant section, you're more likely to come across questions that require a bit more work.

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Bunuel

In the correctly-worked multiplication problem above, each symbol represents a different nonzero digit. What is the value of C?

(1) D is prime.
(2) B is not prime.


Kudos for a correct solution.


Attachment:
AlphameticPost3.jpg

Sol :
factorize 1995 : 3x5x7x19

for multiplication : either D OR B must be 5, otherwise we cant get 1995

and both numbers must be TWO digit numbers.

Either : 19x3= 57 so 2 numbers will be 57 and 35 ( but all digits must be distinct as stated)

or 19x5=95 so 2 numbers will be 95 and 21

Either AB = 95 or CD=95


Stmnt 1) D is prime

so CD = 95 : since 1 not prime

so c=9
Sufficient

Stmnt 2:
B is not prime : same CD= 95
Sufficient

D is answer.

My kudos please :)
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Took about 4 minutes to do this one, but was using hit and trial. Many thanks to the succinct solutions above. My method is as follows:
1995 --> to get a 5 in unit's place, we need 7*5, 9*5, 3*5

(1) D is prime.

--> thus, D has to be 3,5,7. Factorization of 1995 gives = 19*7*3*5 --> out of this only one combination 35*57 has D as prime. But, when I re-read the question, we CANNOT repeat the numbers. So only fits -->the other one 21*95, has one of them composite, one prime and no repeats
(2) B is not prime. --> this was one easier --> only 21*95 fits.

So picked D.

Kudos, if you found this useful
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