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In the correctly-worked multiplication problem above, each symbol repr

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In the correctly-worked multiplication problem above, each symbol repr [#permalink]

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In the correctly-worked multiplication problem above, each symbol represents a different nonzero digit. What is the value of C?

(1) D is prime.
(2) B is not prime.


Kudos for a correct solution.


[Reveal] Spoiler:
Attachment:
AlphameticPost3.jpg
AlphameticPost3.jpg [ 3.66 KiB | Viewed 4013 times ]
[Reveal] Spoiler: OA

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Re: In the correctly-worked multiplication problem above, each symbol repr [#permalink]

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Since the last digit of the product is 5, either B or D has to be 5.

Statement 1 - D is Prime. D can be 5, but can also be 3 or 7. This statement is insufficient.

Statement 2 - B is not prime. This statement implies that B is not 5, so D has to be 5. Now, 1995 is perfectly divisible by 05, 15, 35 and 95.
05 is not acceptable as per the condition given in the question. 15 will also be rejected, as AB will then need to be 133.
35 is also rejected, as AB will be 57, but all the digits are distinct.

Thus, only remaining option is 95 (95*21). All conditions are satisfied and C will be 9.

Answer - B.
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Re: In the correctly-worked multiplication problem above, each symbol repr [#permalink]

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New post 06 May 2015, 18:34
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AB x CD = 1995... breaking 1995 into its prime factors - 3 x 5 x 7 x 19.. looking to find combinations of 2 digits from this 4 prime factors, will lead to only possibility of 21 x 95 i.e., other options are not possible like 35 x 57... 5 repeats here.. other 2 possibilities result in 3 digit numbers..

statement (1) D is prime.. meaning D=5 only possibility.. hence sufficient

statement (2) B is not prime.. meaning B=1 only possibility.. hence sufficient

Hence D.
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Re: In the correctly-worked multiplication problem above, each symbol repr [#permalink]

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Bunuel wrote:
Image
In the correctly-worked multiplication problem above, each symbol represents a different nonzero digit. What is the value of C?

(1) D is prime.
(2) B is not prime.


Kudos for a correct solution.


[Reveal] Spoiler:
Attachment:
AlphameticPost3.jpg


VERITAS PREP OFFICIAL SOLUTION:

We multiply two two-digit integers and get 1995. The good thing is that we know the result of the multiplication will be 1995. Usually, multiplication alphametics are harder since they involve multiple levels, but here the multiplication is actually a blessing. There are many many ways in which you can ADD two integers to give 1995 but there are only a few ways in which you can multiply two integers to give you 1995.

Let’s prime factorize 1995:

1995 = 3*5*7*19

We can probably count on our fingers the number of ways in which we can select AB and CD.

19 needs to be multiplied with one other factor to give us a two digit number since 5*3*7 = 105 (a three digit number) so AB and CD cannot be 19 and 105.

19*3 = 57, 5*7 = 35 – This is not possible since two of the four digits are same here – 5.

19*5 = 95, 3*7 = 21 – This is one option for AB and CD.

19*7 = 133 – Three digit number not possible.

Hence AB and CD can only take values out of 21 and 95.

As of now, C can be 2 or 9. We need to find whether the given statements give us a unique value of C.

Statement 1: D is prime

D is the units digit of CD. So D can be 1 or 5.

1 is not prime so CD cannot be 21. Hence, CD must be 95 and AB must be 21.

Hence, C must be 9.

This statement alone is sufficient.

Statement 2: B is not prime

If B is not prime then AB cannot be 95. Hence AB must be 21.

This means CD will be 95 and C will be 9.

This statement alone is sufficient.

Answer (D)

Note that the entire question was just about number properties – prime factors, prime numbers etc. Actually it required no iterative steps and no hit and trial. Rest assured that if it is a GMAT question, it will be reasoning based and will not require painful calculations.
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PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: In the correctly-worked multiplication problem above, each symbol repr [#permalink]

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New post 11 May 2015, 18:06
Hi kunals31,

You made a nice deduction when dealing with Fact 1, but in DS questions you have to factor in ALL of the information that you're given (AND answer the question that's asked) before you can state that a Fact is sufficient or insufficient.

Here, we're told that each of the 4 letters represents a DIFFERENT NON-0 digit. Given the possibilities that you've described, what would each letter in the final equation be? Would there be ANY DUPLICATES (because that's NOT allowed according to the prompt)...?

Sometimes DS questions require a couple of extra "steps" to prove what the correct answer is. As you score higher and higher in the Quant section, you're more likely to come across questions that require a bit more work.

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Re: In the correctly-worked multiplication problem above, each symbol repr [#permalink]

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New post 12 Dec 2016, 13:02
Bunuel wrote:
Image
In the correctly-worked multiplication problem above, each symbol represents a different nonzero digit. What is the value of C?

(1) D is prime.
(2) B is not prime.


Kudos for a correct solution.


[Reveal] Spoiler:
Attachment:
AlphameticPost3.jpg


Sol :
factorize 1995 : 3x5x7x19

for multiplication : either D OR B must be 5, otherwise we cant get 1995

and both numbers must be TWO digit numbers.

Either : 19x3= 57 so 2 numbers will be 57 and 35 ( but all digits must be distinct as stated)

or 19x5=95 so 2 numbers will be 95 and 21

Either AB = 95 or CD=95


Stmnt 1) D is prime

so CD = 95 : since 1 not prime

so c=9
Sufficient

Stmnt 2:
B is not prime : same CD= 95
Sufficient

D is answer.

My kudos please :)
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Re: In the correctly-worked multiplication problem above, each symbol repr [#permalink]

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Re: In the correctly-worked multiplication problem above, each symbol repr   [#permalink] 21 Dec 2017, 13:38
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