[quote="arhumsid"]I think it should be A.
Since 2 sides of the triangle are the two axes, it has to be a right angled triangle with one of the two axes as base and the other as altitude. The line M is the hypotenuse.
As we are concerned with the area, the quadrant in which the triangle lies wont bother us. Assuming the triangle lies in 1st quadrant.
Line M will intersect X axis at point (x,0) and Y axis at point (0,y).
=> x = height of the triangle and y = base
=> Area = \(\frac{xy}{2}\)
We need to show if \(\frac{xy}{2} > 5\)
S1- Slope of M = \(\frac{-4}{3}\)
=> \(\frac{y-0}{0-x} = \frac{-4}{3}\)
=> \(\frac{-y}{x} = \frac{-4}{3}\)
=>
\(y=4; x=3\)hence, area = \(\frac{4*3}{2}\) = 6 >5.
SufficientS2- x is 25% less than y
=> \(.75y = x\)
here, we can have any pair values that would not necessarily satisfy \(\frac{xy}{2} > 5\)
eg, \(y=1; x=.75\) => \(\frac{xy}{2} < 5\)
and \(y=4; x=3\) => \(\frac{xy}{2} > 5\)
hence
Not sufficientAnswer: AHi arhumsid,
I wanted to know whether
x/y = 4/3 indicates that x=4 and y=3 or
x & y are in a ratio of 4 : 3 ...?If they are in ratio ( That is what i understand ) then A would't be a sufficient solution similar to B.
Answer should be E.