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shasadou
Joined: 12 Aug 2015
Last visit: 24 Nov 2022
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Concentration: General Management, Operations
Schools: Johnson '18 (WL) Duke '18 (M) Tuck '18 (D)
GMAT 1: 640 Q40 V37
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GPA: 3.3
WE:Management Consulting (Consulting)
16 May 2016, 23:39
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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In the figure above, a circle is tangent to a pair of opposite sides of a parallelogram. The length of each of these opposite sides is 58 cm. What is the area of the parallelogram in square centimeters?
(1) The perimeter of the parallelogram is 120 cm.
(2) The circumference of the circle is "pi".
Attachment:
2016-05-17_12-29-37.png [ 7.32 KiB | Viewed 59531 times ]
16 May 2016, 23:53
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shasadou
Hi,
Area of parallelogram = Base * height...
Base can be taken either of the parallel sides...
we are given one base as 58, but if you look at the height, it is nothing BUT the diameter of circle as both the opposite sides are tangent to circle..
lets see the statements
(1) The perimeter of the parallelogram is 120 cm.
we know the length of the other side, BUT we cannot deduce the HEIGHT..
Also with All sides known, there can be various types of llgm possible, which will have different areas..
Insuff
(2) The circumference of the circle is "pi".
From the circumference we can find the DIA, which is nothing BUT the height
2*pi*r = pi, SO DIA = 1..
so area = 1*58 = 58
Suff
B
General Discussion
17 May 2016, 16:35
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If we modify the original condition and the question, the area of the parallelogram can be found if we find the height of the parallelogram. Hence, we only have to find the diameter of the circle. However, from the condition 2), we get 2r=d(diameter)=1 from 2pi r=pr. The answer is unique and the condition is sufficient. Hence the correct answer is B.
Once we modify the original condition and the question according to the variable approach method 1, we can solve approximately 30% of DS questions.
Once we modify the original condition and the question according to the variable approach method 1, we can solve approximately 30% of DS questions.
