This is a quite simple one:
What we need to do is to find out how many different factors does 20k have.
Here are my steps:
--We know that 20 has 6 different factors: 1, 2, 4, 5, 10, 20
Among the six factors, 2 and 5 are prime (hope you still remember what a prime number is)
(1)K is prime.
In this case, K only has 2 factors: 1 and itself.
Thus there are two possibilities:
--K = 2 or 5
--K ≠ 2 or 5
If k = 2 or 5, then K itself is one of the 6 factors of 20, thus K doesn't provide a new factor for 20K. (The question is to find how many 'distinct' factors 20K has! )
So it's clear that 20K has only 6 factors(namely the 6 factors of 20)
If K≠ 2 or 5, then K will provide one new factor to 20K (namely itself). So 20K has 6+1=7 factors.
See, (1) is
not sufficient because 6 and 7 factors are both possible in this case.
(2) K is 7.
In this case, K is a prime AND K ≠ 2 or 5.
So according to the reasoning in (1), 20K will have 7 factors.
SUFFICIENT