Bunuel
If p and q are nonnegative integers, is √x an integer?
(1) \(\frac{x}{5^p2^q}=k\), where k is an integer.
(2) p and q are even integers.
Option (2) should give us a hint.
Statement (1)say p = (1/2) and q = (1/2)
\(\frac{x}{5^p2^q}\). Then if x = \((5^{0.5})*(2^{0.5})\)
we get k= 1.
So condition of statement 1 is satisfied . It can be seen that
√x is not an integerNow say p = 2 and q = 2
\(\frac{x}{5^p2^q}\). Then if x = \((5^2)*(2^2)\)
we get k= 1.
So condition of statement 1 is satisfied . It can be seen that in this situation
√x is an integerSo statement 1 is not sufficient.
Statement 2 says nothing about x hence not sufficientCombining Statement 1 and 2. when x = \((5^2)*(2^2)\); p=2, q=2
We know that, √x is an integer
Suppose
x = 2 * \((5^2)*(2^2)\); p=2, q=2
then both statement 1 and 2 are satisfied.
In this case: √x is not an integer.
E is the answer.