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Re: What is the probability of (x+3)(x+10) being div by 6?
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25 Apr 2016, 22:55

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chetan2u wrote:

What is the probability of (x+3)(x+10) being div by 6? (1) x > 0 (2) y = x+3, where y is an integer greater than 3..

self made OA in two days

hi the Q asks us probability of (x+3)(x+10) being div by 6.. we are not told if x is an integer or not..

If an integer, 1) (x+3)(x+10) will be div by 2 as ONE of them will be ODD and OTHER will be EVEN..

2) So we are looking for div by 3.. x+3 will have same property of div by 3 as x+3+3 or x+3+3+3 = x+9 will have .. so in a way, for looking for div by 3, we can x+9 and x+10 to be consecutive.. In any three consecutive integers, 2 of them will satisfy the criteria of div by 6.. so Probability will be \(\frac{2}{3}\)

So, what are we looking for- Whether x is an integer..

lets see the statements-

(1) x > 0 we just know x is positive but nothing if it is an integer or fraction Insuff

(2) y = x+3, where y is an integer greater than 3.. We are told y>3 and y=x+3.. so x will be an integer >0.. \(prob = \frac{2}{3}\) Suff

Re: What is the probability of (x+3)(x+10) being div by 6?
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22 Nov 2017, 14:49

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