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fitzpratik
Posts: 224
18 Jan 2019, 08:59
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
67% (01:29) correct
33%
(01:20)
wrong
based on 227
sessions
History
Date
Time
Result
Not Attempted Yet
KanishkM
Joined: 09 Mar 2018
Last visit: 18 Dec 2021
Posts: 755
Given Kudos: 123
Location: India
Schools: DeGroote'21 Desautels '21 NUS '21
18 Jan 2019, 10:34
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fitzpratik
Answer C
Statement A .
8X+16Y+24K = 80
Can be reduced to
X + 2Y + 3K = 10
X = 10 - 2Y - 3K ---------------(a)
2 unknowns cant do anything here, OUT
Statement B
18X+24Y+36K= 180
Can be reduced to
3X + 4Y + 6K = 30
X = (30 - 4Y - 6K)/3 -------------------(b)
2 unknowns cant do anything here, OUT
Combine C, Now we can equate for (a) & (b)
(30 - 4Y - 6K)/3 = 10 - 2Y - 3K
30 - 4Y - 6K = 30 - 6Y - 9K
-4Y + 6Y = -9K + 6K
2Y = 3K
Y = - (3K/2)
Value of Y in (a)
X = 10 + 3k - 3k
X = 10
Mandy001
Joined: 21 Nov 2018
Last visit: 02 Oct 2025
Posts: 233
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Given Kudos: 44
Location: India
Concentration: Strategy, Economics
Schools: Tuck '26 (I) Darden '26 (D) Fuqua '26 (WL)
GMAT 1: 730 Q50 V39
GMAT 2: 750 Q51 V40
WE:Consulting (Consulting)
18 Jan 2019, 10:55
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The answer is option C.
So better not to try and get the value of X by substituting values. Rather try to check whether they are solvable or not.
A. 8X+16Y+24K = 80
B. 18X+24Y+36K= 180
Let me write equation A in the form:- lX + mY + nZ = 80
and equation B in the form:- pX + qY + rZ = 180
So to check whether we can solve this find the value of l:m:n and p:q:r and compare both of them. (we are find the ratio of coef. here)
For equation A, we have l:m:n = 8:16:24 which is equal to 1:2:3
For equation B, we have p:q:r = 18:24:36 which is qual to 3:4:6
We can see here that the ratio of second and the third terms in this ratio are equal (which is 1:2) but the ratio of the first term is not equal with respect to any other term. So somehow if you subtitute, the value of X (the first term) can be found out and not the remaining terms.
So better not to try and get the value of X by substituting values. Rather try to check whether they are solvable or not.
A. 8X+16Y+24K = 80
B. 18X+24Y+36K= 180
Let me write equation A in the form:- lX + mY + nZ = 80
and equation B in the form:- pX + qY + rZ = 180
So to check whether we can solve this find the value of l:m:n and p:q:r and compare both of them. (we are find the ratio of coef. here)
For equation A, we have l:m:n = 8:16:24 which is equal to 1:2:3
For equation B, we have p:q:r = 18:24:36 which is qual to 3:4:6
We can see here that the ratio of second and the third terms in this ratio are equal (which is 1:2) but the ratio of the first term is not equal with respect to any other term. So somehow if you subtitute, the value of X (the first term) can be found out and not the remaining terms.
