(-1)^(-1/3)(-8)^(-1/3)(-27)^(-1/3)(-64)^(-1/3) =

If factoring out the negative exponent is unfamiliar, you can take a very traditional route (not too time-consuming -- I was under a minute and I checked accuracy with another method)

\((-1)^{(-\frac{1}{3})}(-8)^{(-\frac{1}{3})}(-27)^{(-\frac{1}{3})}(-64)^{(-\frac{1}{3})} =\)


\(\frac{1}{\sqrt[3]{-1}}\) * \(\frac{1}{\sqrt[3]{-8}}\) * \(\frac{1}{\sqrt[3]{-27}}\) * \(\frac{1}{\sqrt[3]{-64}}\) = **


\(\frac{1}{-1}\) * \(\frac{1}{-2}\) * \(\frac{1}{-3}\) * \(\frac{1}{-4}\)

Multiply the denominators. The answer will be positive because there are an even number of negative factors, that is (-)(-)(-)(-) = (+)

\(\frac{1}{24}\)

ANSWER B

** If thinking in fractional exponents is easier , this stage of the expression could be written

\(\frac{1}{(-1)^{\frac{1}{3}}}\) * \(\frac{1}{(-8)^{\frac{1}{3}}}\) * \(\frac{1}{(-27)^{\frac{1}{3}}}\) * \(\frac{1}{(-64)^{\frac{1}{3}}}\)