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stolyar
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AkamaiBrah
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That is why I call it a complex problem.
36 is a sum of two primes.
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AkamaiBrah
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kpadma
It took 10 minutes to find the prime numners?
What shoud one do to bring the timing to 2 or 3 minutes?


It shouldn't have taken you that long if you think logically and use a systematic method of ellimination. Just using commonly known rules of divisibility (or using quick long division for 7 and 11), you could quickly eliminate everything up trhough 11.

20*20 is too high so we know that at least one factor must be 13, 17, or 19. The last digit is 3 and 17 x 19 would have a last digit of 3 so the would be my first guess. Took about 45seconds.
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Konstantin Lynov
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Sorry guys, but I vote for 'B'

Logic is as follows:
simplifying 1/x+1/y=36/323 yields (x+y)/xy=36/323. We can solve it using a system of equations: a) x+y=36, b)xy=323.
From the system of equations four solutions are possible: x=17,19; y=17,19.

Now, from 'B' it follows that 1<y<x, therefore, it is sufficient.
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Lynov Konstantin
Sorry guys, but I vote for 'B'

Logic is as follows:
simplifying 1/x+1/y=36/323 yields (x+y)/xy=36/323. We can solve it using a system of equations: a) x+y=36, b)xy=323.
From the system of equations four solutions are possible: x=17,19; y=17,19.

Now, from 'B' it follows that 1<y<x, therefore, it is sufficient.


Sorry, but (x+y)/xy = 36/323 does NOT mean a) x+y=36, b)xy=323. You are breaking up ONE equation and TWO unknowns into ONE PARTICULAR solution of TWO equations and TWO unknowns.

Example: a/b = 4/5. We cannot say that a=4 and b=5.

X and Y have unlimited solutions unless constrained to prime integers.
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You got me Akamai. Looks like the skies are on your side today.
But choice B is so tempting...



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