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# [2(2a^(1/2))^2=

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GMAT Club team member
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20 Mar 2020, 23:17
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Difficulty:

5% (low)

Question Stats:

90% (00:21) correct 10% (00:28) wrong based on 39 sessions

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$$(2\sqrt{2a})^2=$$

(A) $$4a$$

(B) $$4a^2$$

(C) $$8a$$

(D) $$8a^2$$

(E) $$6a$$

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GMAT 1: 770 Q49 V46

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21 Mar 2020, 05:14
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Top Contributor
$$(2\sqrt{2a})^2=$$

(A) $$4a$$

(B) $$4a^2$$

(C) $$8a$$

(D) $$8a^2$$

(E) $$6a$$

If $$k \geq 0$$, then $$(\sqrt{k})^2 =k$$

$$(xy)^n = (x^n)(y^n)$$

Given: $$(2\sqrt{2a})^2$$
Apply the above property to get: $$(2^2)(\sqrt{2a})^2$$
Apply the other property to get: $$(4)(2a)$$
Simplify to get: $$8a$$

Cheers,
Brent
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21 Mar 2020, 07:48

Solution

To find
We need to determine
• The value of the given expression $$(2\sqrt{2a})^2$$

Approach and Working out
Squaring the expression inside the bracket, we get
• $$(2\sqrt{2a})^2 = (2)^2 * (\sqrt{2a})^2 = 4 * 2a = 8a$$

Thus, option C is the correct answer.

Correct Answer: Option C
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[2(2a^(1/2))^2=   [#permalink] 21 Mar 2020, 07:48

# [2(2a^(1/2))^2=

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