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Praetorian
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[#23] 2 Min. Challenge : Candle 17 Mar 2004, 12:22
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1. Time yourself
2. Solve as fast as you can
3. write your solution here, and please mention your time.

A Candle burns in 6 Hrs. Another candle of the same height and width
burns in 8 Hrs. If both the candles are lit at the same time, after how many hours will the height of the first candle will be half of the second candle.

1. 2 hrs
2. 4 hrs
3. 4.8 hrs
4. 5.5 hrs
5. 6 hrs



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[#23] 2 Min. Challenge : Candle 17 Mar 2004, 12:36
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3 minutes

4.8 hours
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Virtual
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[#23] 2 Min. Challenge : Candle 17 Mar 2004, 12:41
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4.8 hrs.

(2 * (6-4.8)/6) = (8-4.8)/8
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pakoo
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[#23] 2 Min. Challenge : Candle 17 Mar 2004, 15:56
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4.8 hrs

1st candle burns 4.8/6 = 4.5 in 4.8 hrs, So ramaining is 1/5
2nd candel burns 4.8/8 = 3/5 in 4.8 hrs, So ramining 2/5, which is twice First OR first is half of second.

I got this by picking numbers in 1 min. Any other way.
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[#23] 2 Min. Challenge : Candle 17 Mar 2004, 20:25
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praetorian123
1. Time yourself
2. Solve as fast as you can
3. write your solution here, and please mention your time.

A Candle burns in 6 Hrs. Another candle of the same height and width
burns in 8 Hrs. If both the candles are lit at the same time, after how many hours will the height of the first candle will be half of the second candle.

1. 2 hrs
2. 4 hrs
3. 4.8 hrs
4. 5.5 hrs
5. 6 hrs
Show more


4.8 hrs is correct.

height of candle1 after x hrs=(6-x)/6
height of candle2 after x hrs=(8-x)/8
2*(6-x)6=(8-x)/8
x=4.8



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!