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Bunuel
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Bunuel
\((2 + x)(2 + y) – (2 + x) – (2 + y) =\)

(A) 2y
(B) xy
(C) x + y
(D) x – y
(E) x + y + xy

Let’s simplify the given expression:

(2 + x)(2 + y) - (2 + x) - (2 + y)

4 + 2x + 2y + yx - 2 - x - 2 - y

x + y + yx

Answer: E
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Bunuel
\((2 + x)(2 + y) – (2 + x) – (2 + y) =\)

(A) 2y
(B) xy
(C) x + y
(D) x – y
(E) x + y + xy


ANSWER:
=====

All we need to do is simplify this expression.

Multiply (2 + x)(2 + y) using FOIL. [First Outer Inner Last] and simplify

(2 + x)(2 + y) - (2 + x) - (2 + y)
4 + 2x + 2y + yx - 2 - x - 2 - y
x + y + yx


The Answer is E
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took (2+x) common from the first two elements

so (2+x)(2+y) -(2+x)-(2+y)= (2+x) ((2+y)-1) -(2+y)
=(2+x)(1+y)-(2+y)
=2+2y+x+xy-2-y
=x+y+xy
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