Forum Home > GMAT > Quantitative > Problem Solving (PS)
Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Dec 1511:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease.
Dec 1410:00 AM EST
-12:00 PM EST
Think a 100% GMAT Verbal score is out of your reach? Target Test Prep will make you think again! Our course uses techniques such as topical study and spaced repetition to maximize knowledge retention and make studying simple and fun.- Dec 14
11:00 AM IST
-01:00 PM IST
Attend this session to learn how to Deconstruct arguments, Pre-Think Author’s Assumptions, and apply Negation Test. 
Dec 1608:00 AM PST
-11:59 PM PST
GMAT Club 12 Days of Christmas is a 4th Annual GMAT Club Winter Competition based on solving questions. This is the Winter GMAT competition on GMAT Club with an amazing opportunity to win over $40,000 worth of prizes!- Dec 17
09:00 AM PST
-10:00 AM PST
Join Manhattan Prep instructor Whitney Garner for a fun—and thorough—review of logic-based (non-math) problems, with a particular emphasis on Data Sufficiency and Two-Parts. - Dec 18
10:00 AM PST
-11:00 AM PST
Here is the essential guide to securing scholarships as an MBA student! In this video, we explore the various types of scholarships available, including need-based and merit-based options.
14 Jun 2022, 13:15
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
66% (02:50) correct
34%
(02:47)
wrong
based on 41
sessions
History
Date
Time
Result
Not Attempted Yet
200 students in an MBA program voted for 2 electives A and B to be included in their curriculum. A student could vote for either one or both or none of the electives. If 30% of the students voted for elective A, how many students voted for both the electives?
(1) The sum of the number of students who voted for none of the electives and those who voted for only elective A is 50% more than the number of students who voted for only elective B.
(2) 60% of the students did not vote for elective B.
(1) The sum of the number of students who voted for none of the electives and those who voted for only elective A is 50% more than the number of students who voted for only elective B.
(2) 60% of the students did not vote for elective B.
14 Jun 2022, 21:35
Kudos
Bookmarks
Let a be the number of students who voted for elective A only,
Let b be the number of students who voted for elective B only,
Let x be the number of students who voted for elective A and B both, and
Let n be the number of students who voted for none of the electives.
Given:
=> a + b + x + n = 200 .......... (I)
30% of the students voted for elective A => a + x = 30% of 200 = 60 ........ (II)
We need to find exact value for 'x'
Statement (1) The sum of the number of students who voted for none of the electives and those who voted for only elective A is 50% more than the number of students who voted for only elective B.
=> n + a = 1.5*b
Also, given a + x = 60 and a + b + x + n = 200
Even with these 3 equations we don't know the value of x. 'x' can be any value less than or equal to '60'
Statement (1) alone is insufficient.
Statement (2) 60% of the students did not vote for elective B.
=> 40% of students voted for elective B => b + x = 40% *200
b + x = 80
Also, given a + x = 60 and a + b + x + n = 200
Again, 'x' can be any number less than or equal to 60.
Combining statements (1) and (2) we get,
n + a = 1.5*b
a + x = 60
b + x = 80
and a + b + x + n = 200
(b+x) + (n+a) = 200
80 + 1.5*b = 200
=> b = 2/3*120 = 80
=> x = 0
Hence, combining two statements we get an exact value for the number of students who voted for both the electives.
Answer: C
Let b be the number of students who voted for elective B only,
Let x be the number of students who voted for elective A and B both, and
Let n be the number of students who voted for none of the electives.
Given:
=> a + b + x + n = 200 .......... (I)
30% of the students voted for elective A => a + x = 30% of 200 = 60 ........ (II)
We need to find exact value for 'x'
Statement (1) The sum of the number of students who voted for none of the electives and those who voted for only elective A is 50% more than the number of students who voted for only elective B.
=> n + a = 1.5*b
Also, given a + x = 60 and a + b + x + n = 200
Even with these 3 equations we don't know the value of x. 'x' can be any value less than or equal to '60'
Statement (1) alone is insufficient.
Statement (2) 60% of the students did not vote for elective B.
=> 40% of students voted for elective B => b + x = 40% *200
b + x = 80
Also, given a + x = 60 and a + b + x + n = 200
Again, 'x' can be any number less than or equal to 60.
Combining statements (1) and (2) we get,
n + a = 1.5*b
a + x = 60
b + x = 80
and a + b + x + n = 200
(b+x) + (n+a) = 200
80 + 1.5*b = 200
=> b = 2/3*120 = 80
=> x = 0
Hence, combining two statements we get an exact value for the number of students who voted for both the electives.
Answer: C
Moderator:
