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Difficulty:
65%
(hard)
Question Stats:
57% (02:08) correct
43%
(02:11)
wrong
based on 23
sessions
History
Date
Time
Result
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25 man and 10 women can finish a task in 6 days. 21 men and 30 women finish the same task in 3 days. How many women along with 23 men are required to finish the task in 4 days?
A)12
B)20
C)24
D)48
E)50
A)12
B)20
C)24
D)48
E)50
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05 Nov 2019, 06:22
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this question can be solved through man/women-day work formula
(25M+10W)*6 = (21M+30W)*3 (since work done in both the case is same)
29M = 10W
M = \(\frac{10W}{29}\)
now let there be x women
men = 23 and time taken to complete the same work = 4
(23M+xW)*4 = (21M+30W)*3 (since work done in both the case is same)
(23*\(\frac{10}{29}\)W+xW)*4 = (21*\(\frac{10}{29}\)W+30W)*3
(92*\(\frac{10}{29}\)+4x)W = (63*\(\frac{10}{29}\)+90)W
29*\(\frac{10}{29}\)+4x = 90
4x = 80
x = 20
hence 20 women are required
(25M+10W)*6 = (21M+30W)*3 (since work done in both the case is same)
29M = 10W
M = \(\frac{10W}{29}\)
now let there be x women
men = 23 and time taken to complete the same work = 4
(23M+xW)*4 = (21M+30W)*3 (since work done in both the case is same)
(23*\(\frac{10}{29}\)W+xW)*4 = (21*\(\frac{10}{29}\)W+30W)*3
(92*\(\frac{10}{29}\)+4x)W = (63*\(\frac{10}{29}\)+90)W
29*\(\frac{10}{29}\)+4x = 90
4x = 80
x = 20
hence 20 women are required
